Question Number 19964 by ajfour last updated on 19/Aug/17 Commented by ajfour last updated on 19/Aug/17 $${Inscribed}\:{in}\:{a}\:{right}\:{circular}\:{cone} \\ $$$${is}\:{a}\:{sphere}\:{whose}\:{surface}\:{area}\:{is} \\ $$$${equal}\:{to}\:{the}\:{area}\:{of}\:{the}\:{base}\:{if}\:{the} \\ $$$${cone}.\:{In}\:{what}\:{ratio}\:{is}\:{the}\:{lateral} \\ $$$${side}\:{of}\:{the}\:{cone}\:{divided}\:{by}\:{the}\:{line}…
Question Number 85498 by Roland Mbunwe last updated on 22/Mar/20 $$\left(\mathrm{1}−{x}^{\mathrm{2}} \right)\frac{{dy}}{{dx}\:}−\mathrm{2}{xy}=\mathrm{0} \\ $$ Commented by niroj last updated on 22/Mar/20 $$\:\left(\mathrm{1}−\mathrm{x}^{\mathrm{2}} \right)\frac{\mathrm{dy}}{\mathrm{dx}}−\mathrm{2xy}=\mathrm{0} \\ $$$$\:\:\:\:\left(\mathrm{1}−\mathrm{x}^{\mathrm{2}}…
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Question Number 151028 by kalenis last updated on 17/Aug/21 Answered by amin96 last updated on 17/Aug/21 $$\begin{cases}{{x}+{y}−{z}=\mathrm{7}\:\:\:\:\:−}\\{{x}−{y}+\mathrm{2}{z}=\mathrm{3}}\\{\mathrm{2}{x}+{y}+{z}=\mathrm{9}}\end{cases}\Rightarrow\begin{cases}{\mathrm{2}{x}+{z}=\mathrm{10}}\\{\mathrm{10}+{y}=\mathrm{9}}\end{cases}\:\Rightarrow\begin{cases}{\mathrm{2}{x}+{z}=\mathrm{10}}\\{{y}=−\mathrm{1}}\end{cases} \\ $$$$\begin{cases}{{x}−{z}=\mathrm{8}}\\{{x}+\mathrm{2}{z}=\mathrm{2}}\end{cases}\:\:\begin{cases}{\mathrm{2}{x}−\mathrm{2}{z}=\mathrm{16}}\\{{x}+\mathrm{2}{z}=\mathrm{2}}\end{cases}\Rightarrow\mathrm{3}{x}=\mathrm{18}\:\:{x}=\mathrm{6} \\ $$$${x}−{z}=\mathrm{8}\:\:\Rightarrow\:\:{z}=−\mathrm{2}\:\:\:\:\:{answer}\:\:\left(\mathrm{6};\:\:−\mathrm{1};\:\:−\mathrm{2}\right) \\ $$ Terms of…
Question Number 85490 by oustmuchiya@gmail.com last updated on 22/Mar/20 $${Given}\:{that}\:{the}\:{expression}\:\mathrm{2}{x}^{\mathrm{3}} +{px}^{\mathrm{2}} −\mathrm{8}{x}+\mathrm{9}\:{is}\:{exactly}\:{divisable}\:{by}\:{x}^{\mathrm{2}} −\mathrm{6}{x}+\mathrm{5},\:{find}\:{the}\:{value}\:{of}\:\boldsymbol{\mathrm{p}}\:{and}\:\boldsymbol{\mathrm{q}}.\:{Hence}\:{factorise}\:{the}\:{expression}\:{fully} \\ $$ Commented by john santu last updated on 22/Mar/20 $${nothing}\:{q}\:{in}\:{this}\:{equation}. \\…
Question Number 19955 by ajfour last updated on 19/Aug/17 Commented by ajfour last updated on 19/Aug/17 $${Find}\:{the}\:{volume}\:{of}\:{the}\:{regular} \\ $$$${tetrahedron}\:{in}\:{terms}\:{of}\:\boldsymbol{{r}}\:. \\ $$ Commented by ajfour last…
Question Number 85488 by john santu last updated on 22/Mar/20 $$\int\:\frac{{dx}}{\left({x}^{\mathrm{4}} +{x}^{\mathrm{2}} +\mathrm{1}\right)^{\frac{\mathrm{3}}{\mathrm{4}}} } \\ $$ Answered by MJS last updated on 22/Mar/20 $$\mathrm{trying}\:\mathrm{around}\:\mathrm{I}\:\mathrm{landed}\:\mathrm{on} \\…
Question Number 19953 by mondodotto@gmail.com last updated on 19/Aug/17 Terms of Service Privacy Policy Contact: info@tinkutara.com