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Author: Tinku Tara

Question-150838

Question Number 150838 by mathdanisur last updated on 15/Aug/21 Answered by amin96 last updated on 15/Aug/21 $$\frac{\left(\mathrm{3}^{\mathrm{4}} +\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\mathrm{5}^{\mathrm{4}} +\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\mathrm{7}^{\mathrm{4}} +\frac{\mathrm{1}}{\mathrm{4}}\right)}{\left(\mathrm{4}^{\mathrm{4}} +\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\mathrm{6}^{\mathrm{4}} +\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\mathrm{8}^{\mathrm{4}} +\frac{\mathrm{1}}{\mathrm{4}}\right)}=\frac{\left(\left(\mathrm{3}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} −\mathrm{9}\right)\left(\left(\mathrm{5}^{\mathrm{2}}…

If-sin-x-cos-x-tan-x-cosec-x-cot-x-sec-x-7-then-find-the-value-of-sin-2x-

Question Number 19760 by Tinkutara last updated on 15/Aug/17 $$\mathrm{If}\:\mathrm{sin}\:{x}\:+\:\mathrm{cos}\:{x}\:+\:\mathrm{tan}\:{x}\:+\:\mathrm{cosec}\:{x}\:+ \\ $$$$\mathrm{cot}\:{x}\:+\:\mathrm{sec}\:{x}\:=\:\mathrm{7},\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{sin}\:\mathrm{2}{x}. \\ $$ Answered by ajfour last updated on 15/Aug/17 $$\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}+\frac{\mathrm{1}}{\mathrm{sin}\:\mathrm{x}}+\frac{\mathrm{1}}{\mathrm{cos}\:\mathrm{x}}+\frac{\mathrm{sin}\:\mathrm{x}}{\mathrm{cos}\:\mathrm{x}} \\…

lim-x-0-1-x-1-2x-2020-

Question Number 85293 by jagoll last updated on 20/Mar/20 $$\underset{{x}\rightarrow\mathrm{0}^{+} \:} {\mathrm{lim}}\:\sqrt{\frac{\mathrm{1}}{\mathrm{x}}}−\sqrt{\frac{\mathrm{1}}{\mathrm{2x}}−\mathrm{2020}}\:? \\ $$ Commented by jagoll last updated on 20/Mar/20 $$\mathrm{what}\:\mathrm{is}\:\mathrm{result}?\:\mathrm{0}\:\mathrm{or}\:\infty? \\ $$ Answered…

who-can-help-write-out-the-mechanism-for-the-reaction-C-6-H-6-HNO-3-H-2-SO-4-C-6-H-5-NO-2-

Question Number 85279 by Rio Michael last updated on 20/Mar/20 $$\mathrm{who}\:\mathrm{can}\:\mathrm{help}\:\mathrm{write}\:\mathrm{out}\:\mathrm{the}\:\mathrm{mechanism}\:\mathrm{for}\:\mathrm{the}\: \\ $$$$\mathrm{reaction} \\ $$$$\:\:\:\mathrm{C}_{\mathrm{6}} \mathrm{H}_{\mathrm{6}} \:\underset{\mathrm{HNO}_{\mathrm{3}} } {\overset{\mathrm{H}_{\mathrm{2}} \mathrm{SO}_{\mathrm{4}} } {\rightarrow}}\:\:\mathrm{C}_{\mathrm{6}} \mathrm{H}_{\mathrm{5}} \mathrm{NO}_{\mathrm{2}} \\…