Question Number 150792 by mathdanisur last updated on 15/Aug/21 $$\mathrm{if}\:\:\:\frac{\mathrm{y}+\mathrm{z}}{\mathrm{x}}\:=\:\frac{\mathrm{10}}{\mathrm{3}}\:\:\mathrm{and}\:\:\frac{\mathrm{x}}{\mathrm{z}}\:=\:\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\mathrm{find}\:\:\frac{\mathrm{x}}{\mathrm{y}}\:=\:? \\ $$ Answered by nimnim last updated on 15/Aug/21 $${y}=\frac{\mathrm{10}{x}−\mathrm{3}{z}}{\mathrm{3}}\:\:\:\:{and}\:\:\:\:\mathrm{3}{z}=\mathrm{4}{x} \\ $$$$\therefore\frac{{x}}{{y}}=\frac{{x}}{\frac{\mathrm{10}{x}−\mathrm{4}{x}}{\mathrm{3}}}\:=\frac{\mathrm{1}}{\mathrm{2}} \\…
Question Number 85256 by john santu last updated on 20/Mar/20 $$\int\underset{\mathrm{0}} {\overset{\:\mathrm{1}} {\:}}\:\frac{\mathrm{sin}\:\left(\mathrm{ln}\:\mathrm{x}\right)}{\mathrm{ln}\:\left(\mathrm{x}\right)}\:\mathrm{dx}\: \\ $$ Commented by john santu last updated on 20/Mar/20 $$\mathrm{sin}\:\left(\mathrm{z}\right)\:=\:\frac{\mathrm{e}^{\mathrm{iz}\:} −\mathrm{e}^{−\mathrm{iz}}…
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Question Number 150789 by cherokeesay last updated on 15/Aug/21 Answered by nimnim last updated on 15/Aug/21 $$\frac{\mathrm{1}}{\:\sqrt{{r}}}=\frac{\mathrm{1}}{\:\sqrt{{R}}}+\frac{\mathrm{1}}{\:\sqrt{{R}}}\Rightarrow\frac{\mathrm{1}}{\:\sqrt{{r}}}=\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow{r}=\mathrm{1} \\ $$$${S}_{{area}} =\pi\left(\mathrm{1}\right)^{\mathrm{2}} =\pi\:{cm}^{\mathrm{2}} \\ $$…
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Question Number 85250 by niroj last updated on 20/Mar/20 $$\:\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{general}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{singular}}\:\boldsymbol{\mathrm{solution}}\:\boldsymbol{\mathrm{of}}\: \\ $$$$\:\left(\mathrm{i}\right).\:\boldsymbol{\mathrm{y}}=\:\boldsymbol{\mathrm{px}}\:+\:\boldsymbol{\mathrm{p}}^{\boldsymbol{\mathrm{n}}} \\ $$$$\left(\mathrm{ii}\right).\:\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}\right)\boldsymbol{\mathrm{p}}^{\mathrm{2}} +\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{y}}\right)\boldsymbol{\mathrm{p}}−\boldsymbol{\mathrm{y}}=\mathrm{0} \\ $$$$\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 85248 by jagoll last updated on 20/Mar/20 $$\mathrm{find}\:\mathrm{minimum} \\ $$$$\mathrm{y}\:=\:\mathrm{2}\mid\mathrm{x}−\mathrm{3}\mid\:+\:\mid\mathrm{4x}+\mathrm{2}\mid\: \\ $$ Commented by mr W last updated on 20/Mar/20 $${x}−\mathrm{3}=\mathrm{0}\:\Rightarrow{x}=\mathrm{3} \\ $$$$\mathrm{4}{x}+\mathrm{2}=\mathrm{0}\:\Rightarrow{x}=−\frac{\mathrm{1}}{\mathrm{2}}…
Question Number 150786 by KONE last updated on 15/Aug/21 Answered by KONE last updated on 15/Aug/21 $${de}\:{l}'{aide} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 150783 by jlewis last updated on 15/Aug/21 $$\mathrm{The}\:\mathrm{current}\:\mathrm{in}\:\mathrm{the}\:\mathrm{windings}\:\mathrm{on}\:\mathrm{a}\:\mathrm{toroid} \\ $$$$\mathrm{is}\:\mathrm{2A}.\:\mathrm{There}\:\mathrm{are}\:\mathrm{400turns}\:\mathrm{and}\:\mathrm{the}\:\mathrm{mean} \\ $$$$\mathrm{circumferential}\:\mathrm{length}\:\mathrm{is}\:\mathrm{40cm}.\:\mathrm{With} \\ $$$$\mathrm{the}\:\mathrm{aid}\:\mathrm{of}\:\mathrm{a}\:\mathrm{search}\:\mathrm{coil}\:\mathrm{and}\:\mathrm{charge} \\ $$$$\mathrm{measuring}\:\mathrm{instrument},\mathrm{the}\:\mathrm{magnetic} \\ $$$$\mathrm{field}\:\mathrm{is}\:\mathrm{found}\:\mathrm{to}\:\mathrm{be}\:\mathrm{1}.\mathrm{0T}.\:\mathrm{calculate}: \\ $$$$\left.\mathrm{i}\left.\right)\mathrm{magnetic}\:\mathrm{intensity}\:\mathrm{ii}\right)\mathrm{magnetization} \\ $$$$\left.\mathrm{iii}\right)\mathrm{the}\:\mathrm{equivalent}\:\mathrm{surface}\:\mathrm{current} \\…