Question Number 150641 by maged last updated on 14/Aug/21 $$\mathrm{1}+\sqrt{\mathrm{3}^{\mathrm{x}} }=\mathrm{2}^{\mathrm{x}} \\ $$$$\mathrm{x}=? \\ $$ Commented by amin96 last updated on 14/Aug/21 $$\sqrt{\mathrm{3}^{{x}} }=\mathrm{3}^{{m}} \:\:\:\:\mathrm{3}^{{x}}…
Question Number 85104 by jagoll last updated on 19/Mar/20 $$\mathrm{Given}\: \\ $$$$\begin{cases}{\mathrm{x}^{\mathrm{2}} −\mathrm{2xy}−\mathrm{3x}\:=\:−\mathrm{1}}\\{\mathrm{4y}^{\mathrm{2}} −\mathrm{2xy}+\mathrm{6y}\:=\:−\mathrm{1}}\end{cases} \\ $$$$\mathrm{find}\:\mathrm{2y}\:−\:\mathrm{x} \\ $$ Commented by john santu last updated on…
Question Number 85105 by naka3546 last updated on 19/Mar/20 Answered by MJS last updated on 19/Mar/20 $${x}=\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{8}}{\mathrm{9}}+\mathrm{1}+\frac{\mathrm{64}}{\mathrm{81}}+\frac{\mathrm{125}}{\mathrm{243}}+…={S}_{\infty} \\ $$$${S}_{{n}} =\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{{k}^{\mathrm{3}} }{\mathrm{3}^{{k}} }\:=\frac{\mathrm{33}}{\mathrm{8}}−\left(\frac{{n}^{\mathrm{3}} }{\mathrm{2}}+\frac{\mathrm{9}{n}^{\mathrm{2}}…
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Question Number 85097 by jagoll last updated on 19/Mar/20 $$\underset{−\pi} {\overset{\pi} {\int}}\:\mathrm{x}^{\mathrm{2020}} \:\left(\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}\right)\:\mathrm{dx}\:=\:\mathrm{8} \\ $$$$\mathrm{find}\:\underset{−\pi} {\overset{\pi} {\int}}\:\mathrm{x}^{\mathrm{2020}} \:\mathrm{cos}\:\mathrm{x}\:\mathrm{dx}\:=\:? \\ $$ Answered by john santu last…
Question Number 150628 by aupo14 last updated on 14/Aug/21 Answered by som(math1967) last updated on 14/Aug/21 $$\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{2}.\boldsymbol{{x}}.\frac{\mathrm{1}}{\mathrm{2}}\:+\frac{\mathrm{1}}{\mathrm{4}}=\mathrm{4}+\frac{\mathrm{1}}{\mathrm{4}}−\mathrm{4}\boldsymbol{{y}} \\ $$$$\left(\boldsymbol{{x}}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =\left(\frac{\mathrm{17}}{\mathrm{4}}−\mathrm{4}\boldsymbol{{y}}\right) \\ $$$$\left(\boldsymbol{{x}}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =−\mathrm{4}\left(\boldsymbol{{y}}−\frac{\mathrm{17}}{\mathrm{16}}\right) \\…
Question Number 19557 by ajfour last updated on 12/Aug/17 Commented by ajfour last updated on 12/Aug/17 $$\mathrm{If}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{line}\:\mathrm{through}\:\:\mathrm{z}=\:\mathrm{z}_{\mathrm{0}} \\ $$$$\mathrm{and}\:\:\mathrm{z}=\mathrm{c}\:\:\:\mathrm{be}\:\:\bar {\mathrm{a}z}+\mathrm{a}\bar {\mathrm{z}}+\mathrm{k}=\mathrm{0} \\ $$$$\mathrm{find}\:\mathrm{z}=\mathrm{a}\:\mathrm{and}\:\mathrm{scalar}\:\mathrm{k}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of} \\ $$$$\mathrm{z}_{\mathrm{0}}…
Question Number 19556 by chernoaguero@gmail.com last updated on 12/Aug/17 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 19555 by Tinkutara last updated on 12/Aug/17 $$\mathrm{Find}\:\mathrm{center}\:\mathrm{and}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{circle}\:\mathrm{having} \\ $$$$\mathrm{equation}\:{z}\bar {{z}}\:+\:\left(\mathrm{1}\:−\:{i}\right){z}\:+\:\left(\mathrm{1}\:+\:{i}\right)\bar {{z}}\:−\:\mathrm{1}\:=\:\mathrm{0}. \\ $$ Answered by ajfour last updated on 12/Aug/17 $$\mathrm{Equation}\:\mathrm{of}\:\mathrm{circle}: \\…
Question Number 85091 by pew_247 last updated on 18/Mar/20 Commented by john santu last updated on 19/Mar/20 $$\left(\mathrm{1}\right)\:\mathrm{n}\left(\mathrm{S}\right)\:=\:\mathrm{C}_{\mathrm{13}} ^{\mathrm{52}} ×\mathrm{C}_{\mathrm{13}} ^{\mathrm{39}} \:×\mathrm{C}_{\mathrm{13}} ^{\mathrm{26}} ×\mathrm{1} \\…