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Author: Tinku Tara

If-cos-2pi-5-i-sin-2pi-5-then-find-the-value-of-2-3-4-

Question Number 19435 by Tinkutara last updated on 11/Aug/17 $$\mathrm{If}\:\alpha\:=\:\mathrm{cos}\:\frac{\mathrm{2}\pi}{\mathrm{5}}\:+\:{i}\:\mathrm{sin}\:\frac{\mathrm{2}\pi}{\mathrm{5}}\:,\:\mathrm{then}\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{value}\:\mathrm{of}\:\alpha\:+\:\alpha^{\mathrm{2}} \:+\:\alpha^{\mathrm{3}} \:+\:\alpha^{\mathrm{4}} . \\ $$ Answered by ajfour last updated on 11/Aug/17 $$\underset{\mathrm{r}=\mathrm{1}}…

If-1-i-3-1-i-3-n-is-an-integer-then-n-is-

Question Number 19434 by Tinkutara last updated on 11/Aug/17 $$\mathrm{If}\:\left(\frac{\mathrm{1}\:+\:{i}\sqrt{\mathrm{3}}}{\mathrm{1}\:−\:{i}\sqrt{\mathrm{3}}}\right)^{{n}} \:\mathrm{is}\:\mathrm{an}\:\mathrm{integer},\:\mathrm{then}\:{n}\:\mathrm{is} \\ $$ Answered by ajfour last updated on 11/Aug/17 $$\left(\frac{\mathrm{1}+{i}\sqrt{\mathrm{3}}}{\mathrm{1}−{i}\sqrt{\mathrm{3}}}\right)^{\mathrm{n}} =\left(\frac{\mathrm{e}^{{i}\pi/\mathrm{6}} }{\mathrm{e}^{−{i}\pi/\mathrm{6}} }\right)^{\mathrm{n}} =\left[\mathrm{x}\right]…

5-12i-5-12i-5-12i-5-12i-

Question Number 19433 by Tinkutara last updated on 11/Aug/17 $$\frac{\sqrt{\mathrm{5}\:+\:\mathrm{12}{i}}\:+\:\sqrt{\mathrm{5}\:−\:\mathrm{12}{i}}}{\:\sqrt{\mathrm{5}\:+\:\mathrm{12}{i}}\:−\:\sqrt{\mathrm{5}\:−\:\mathrm{12}{i}}}\:= \\ $$ Answered by ajfour last updated on 11/Aug/17 $$=\frac{\left(\sqrt{\mathrm{5}+\mathrm{12i}}+\sqrt{\mathrm{5}−\mathrm{12i}}\right)^{\mathrm{2}} }{\mathrm{24i}} \\ $$$$=\frac{\mathrm{10}+\mathrm{2}\sqrt{\mathrm{25}+\mathrm{144}}}{\mathrm{24i}}=\frac{\mathrm{3}}{\mathrm{2i}}=−\frac{\mathrm{3}}{\mathrm{2}}\mathrm{i}\:. \\ $$…

let-c-is-a-constant-vector-and-r-xi-yj-zk-then-proved-that-grad-c-r-n-n-c-r-n-2-c-r-c-

Question Number 84969 by subhankar10 last updated on 18/Mar/20 $$\mathrm{let}\:\mathrm{c}\:\mathrm{is}\:\mathrm{a}\:\mathrm{constant}\:\mathrm{vector}\:\mathrm{and}\:\overset{\rightarrow} {\mathrm{r}}=\mathrm{x}\hat {\mathrm{i}}+\mathrm{y}\hat {\mathrm{j}}+\mathrm{z}\hat {\mathrm{k}}\:\mathrm{then}\:\mathrm{proved}\:\mathrm{that}\:\mathrm{grad}\:\mid\mathrm{c}×\overset{\rightarrow} {\mathrm{r}}\mid^{\mathrm{n}} =\mathrm{n}\mid\mathrm{c}×\overset{\rightarrow} {\mathrm{r}}\mid^{\mathrm{n}−\mathrm{2}} \mathrm{c}×\left(\overset{\rightarrow} {\mathrm{r}}×\mathrm{c}\right). \\ $$ Terms of Service Privacy…