Question Number 19083 by mondodotto@gmail.com last updated on 04/Aug/17 Commented by ajfour last updated on 04/Aug/17 $$\mathrm{something}\:\mathrm{wrong}\:\mathrm{with}\:\mathrm{the}\:\mathrm{question}\:! \\ $$ Commented by mondodotto@gmail.com last updated on…
Question Number 150154 by math55 last updated on 09/Aug/21 $$\left.\mathrm{1}\right)\mathrm{The}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{a}\:\mathrm{Malaria}\:\mathrm{patient}\: \\ $$$$\mathrm{surviving}\:\mathrm{from}\:\mathrm{a}\:\mathrm{newly}\:\mathrm{discovered} \\ $$$$\mathrm{drug}\:\mathrm{is}\:\mathrm{0}.\mathrm{27},\mathrm{while}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{of} \\ $$$$\mathrm{a}\:\mathrm{typhoid}\:\mathrm{patient}\:\mathrm{surviving}\:\mathrm{from}\:\mathrm{another} \\ $$$$\mathrm{newly}\:\mathrm{discovered}\:\mathrm{drug}\:\mathrm{is}\:\mathrm{0}.\mathrm{85}.\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{probabilities}\:\mathrm{of}\: \\ $$$$\left.\mathrm{i}\right)\mathrm{Either}\:\mathrm{of}\:\mathrm{the}\:\mathrm{two}\:\mathrm{patient}\:\mathrm{surviving} \\ $$$$\left.\mathrm{ii}\right)\mathrm{Neither}\:\mathrm{of}\:\mathrm{the}\:\mathrm{two}\:\mathrm{patient}\:\mathrm{surviving} \\…
Question Number 19080 by mondodotto@gmail.com last updated on 04/Aug/17 Commented by iostream last updated on 04/Aug/17 $${a}\:\mathrm{can}\:\mathrm{be}\:\mathrm{any}\:\mathrm{integer}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 19077 by Joel577 last updated on 04/Aug/17 $$\int\:\mathrm{sec}^{\mathrm{3}} \:{x}\:{dx} \\ $$ Answered by ajfour last updated on 04/Aug/17 $$\mathrm{I}=\int\mathrm{sec}\:\theta\left(\mathrm{sec}\:^{\mathrm{2}} \theta\mathrm{d}\theta\right) \\ $$$$=\mathrm{sec}\:\theta\int\mathrm{sec}\:^{\mathrm{2}} \theta\mathrm{d}\theta−\int\left[\frac{\mathrm{d}}{\mathrm{d}\theta}\left(\mathrm{sec}\:\theta\right).\int\mathrm{sec}\:^{\mathrm{2}}…
Question Number 150150 by Tawa11 last updated on 09/Aug/21 Commented by MJS_new last updated on 10/Aug/21 $$\mathrm{6}×\mathrm{6}−\left[\mathrm{4}{quarter}\:{circles}\:{r}=\mathrm{2}\right]−\left[\mathrm{3}{circles}\:{r}=\mathrm{1}\right]= \\ $$$$=\mathrm{36}−\mathrm{7}\pi \\ $$ Commented by Tawa11 last…
Question Number 19073 by behi.8.3.4.1.7@gmail.com last updated on 04/Aug/17 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 84607 by M±th+et£s last updated on 14/Mar/20 $$\left.\mathrm{1}\right)\int\sqrt{{sin}\left({x}\right)}\:{dx} \\ $$$$\left.\mathrm{2}\right)\int{cos}\left({x}^{\mathrm{2}} \right){dx} \\ $$$$ \\ $$ Commented by john santu last updated on 14/Mar/20…
Question Number 150136 by Tawa11 last updated on 09/Aug/21 Commented by Tawa11 last updated on 09/Aug/21 $$\mathrm{Thanks}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}.\:\mathrm{I}\:\mathrm{appreciate}\:… \\ $$ Answered by mr W last updated…
Question Number 84600 by john santu last updated on 14/Mar/20 $$\underset{{x}\rightarrow\infty\:} {\mathrm{lim}}\:{x}\sqrt{\frac{{x}−\mathrm{1}}{\mathrm{9}{x}+\mathrm{2}}}\:−\:\frac{{x}}{\mathrm{3}} \\ $$ Commented by jagoll last updated on 14/Mar/20 $$\mathrm{nice}\:\mathrm{mister} \\ $$ Commented…
Question Number 19064 by 99 last updated on 03/Aug/17 Commented by 99 last updated on 03/Aug/17 $${sir}\:{please}\:{solve}\:{this}\:{question} \\ $$ Commented by 99 last updated on…