Question Number 84570 by msup trace by abdo last updated on 14/Mar/20 $${calculate}\:\int_{\mathrm{1}} ^{+\infty} \:\frac{{arctan}\left(\frac{\mathrm{3}}{{x}}\right)}{{x}^{\mathrm{2}} }{dx} \\ $$ Commented by mathmax by abdo last updated…
Question Number 84571 by msup trace by abdo last updated on 14/Mar/20 $${calculate}\:{S}_{{n}} =\sum_{{k}=\mathrm{1}} ^{{n}} \:\frac{\left(−\mathrm{1}\right)^{{k}} }{\:\sqrt{{k}}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 84568 by jagoll last updated on 14/Mar/20 $$\mathrm{without}\:\mathrm{L}'\mathrm{hopital} \\ $$$$\underset{{x}\rightarrow−\frac{\mathrm{1}}{\mathrm{2}}} {\mathrm{lim}}\:\frac{\mathrm{2x}^{\mathrm{3}} +\mathrm{3x}^{\mathrm{2}} −\sqrt{\mathrm{a}+\mathrm{bx}}}{\mathrm{4x}^{\mathrm{2}} −\mathrm{1}}\:=\:−\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\mathrm{find}\:\mathrm{a}+\mathrm{b} \\ $$ Commented by john santu last…
Question Number 19033 by Bruce Lee last updated on 03/Aug/17 Commented by Bruce Lee last updated on 03/Aug/17 $$\boldsymbol{{Help}}\:\boldsymbol{{me}},\:\boldsymbol{{by}}\:\boldsymbol{{no}}\:\boldsymbol{{Lhopital}} \\ $$ Answered by ajfour last…
Question Number 84569 by msup trace by abdo last updated on 14/Mar/20 $${find}\:\:\int\:\:\:\:\frac{{dx}}{\mathrm{1}+{tan}^{\mathrm{4}} {x}} \\ $$ Answered by M±th+et£s last updated on 14/Mar/20 $$\int\frac{{sec}^{\mathrm{2}} \left({x}\right)}{\left(\mathrm{1}+{tan}^{\mathrm{2}}…
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Question Number 150103 by mnjuly1970 last updated on 09/Aug/21 $$\:\Omega\:=\:\int_{\mathrm{0}} ^{\:\pi} {sin}^{\:\frac{\mathrm{1}}{\mathrm{2}}} \left({x}\right).\:\mathrm{ln}\left(\:{sin}\:\left({x}\right)\:\right){dx}=? \\ $$$$ \\ $$ Answered by Ar Brandon last updated on 09/Aug/21…
Question Number 84564 by Rio Michael last updated on 14/Mar/20 $$\mathrm{find}\:\mathrm{arg}\left(\mathrm{z}\right)\:\mathrm{given}\:\mathrm{that}\:\:\mathrm{z}\:=\:\frac{\mathrm{1}\:+\:{i}}{\mathrm{1}−{i}} \\ $$ Commented by mr W last updated on 14/Mar/20 $${z}=\frac{\mathrm{1}+{i}}{\mathrm{1}−{i}}=\frac{\left(\mathrm{1}+{i}\right)\left(\mathrm{1}+{i}\right)}{\mathrm{1}−{i}^{\mathrm{2}} }=\frac{\mathrm{1}+\mathrm{2}{i}+{i}^{\mathrm{2}} }{\mathrm{2}}={i} \\…
Question Number 150097 by mathdanisur last updated on 09/Aug/21 Answered by Kamel last updated on 09/Aug/21 $${u}_{{n}} =\underset{{p}=\mathrm{0}} {\overset{{m}} {\prod}}\gamma_{{n}+{p}} =\left(\gamma+\frac{\mathrm{1}}{\mathrm{2}{n}}\right)^{{m}+\mathrm{1}} +{o}\left(\frac{\mathrm{1}}{{n}}\right)=\gamma^{{m}+\mathrm{1}} +\left({m}+\mathrm{1}\right)\frac{\gamma^{{m}} }{\mathrm{2}{n}}+{o}\left(\frac{\mathrm{1}}{{n}}\right) \\…
Question Number 19025 by aplus last updated on 03/Aug/17 Terms of Service Privacy Policy Contact: info@tinkutara.com