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Author: Tinku Tara

a-full-deck-of-52-cards-contains-13-hearts-Pick-8-cards-from-the-deck-at-random-without-replacement-what-is-the-probability-that-you-get-no-heart-

Question Number 149981 by jlewis last updated on 08/Aug/21 $$\mathrm{a}\:\mathrm{full}\:\mathrm{deck}\:\mathrm{of}\:\mathrm{52}\:\mathrm{cards}\:\mathrm{contains}\:\mathrm{13} \\ $$$$\:\mathrm{hearts}.\:\mathrm{Pick}\:\mathrm{8}\:\mathrm{cards}\:\mathrm{from}\:\mathrm{the}\:\mathrm{deck} \\ $$$$\mathrm{at}\:\mathrm{random}\:\mathrm{without}\:\mathrm{replacement}. \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{you}\:\mathrm{get} \\ $$$$\mathrm{no}\:\mathrm{heart}? \\ $$$$ \\ $$ Answered by mr…

Why-Does-A-B-ABSin-

Question Number 18908 by Nayon last updated on 01/Aug/17 $${Why}\:{Does} \\ $$$$\mid\overset{\rightarrow} {{A}}×\overset{\rightarrow} {{B}}\mid={ABSin}\theta\:? \\ $$ Commented by mrW1 last updated on 02/Aug/17 $$\mathrm{You}\:\mathrm{can}\:\mathrm{not}\:\mathrm{ask}\:\mathrm{why}\:\mathrm{to}\:\mathrm{a}\:\mathrm{definition}. \\…

Question-84442

Question Number 84442 by Power last updated on 13/Mar/20 Answered by john santu last updated on 13/Mar/20 $$\mathrm{let}\:\mathrm{y}\:=\:\mathrm{x}^{\mathrm{3x}^{\mathrm{5x}} } \:\Rightarrow\mathrm{ln}\left(\mathrm{y}\right)=\:\mathrm{ln}\left(\mathrm{x}^{\mathrm{3x}^{\mathrm{5x}} } \right) \\ $$$$\mathrm{let}\:\mathrm{3x}^{\mathrm{5x}} \:=\:\mathrm{g}\left(\mathrm{x}\right)…

calculate-dy-dx-where-y-cos-1-a-b-cosx-b-a-cosx-b-gt-a-

Question Number 18906 by Arnab Maiti last updated on 01/Aug/17 $$\mathrm{calculate}\:\frac{\mathrm{dy}}{\mathrm{dx}}\:\:\:\mathrm{where}\: \\ $$$$\mathrm{y}=\mathrm{cos}^{−\mathrm{1}} \frac{\mathrm{a}+\mathrm{b}\:\mathrm{cosx}}{\mathrm{b}+\mathrm{a}\:\mathrm{cosx}}\:\left(\mathrm{b}>\mathrm{a}\right) \\ $$ Answered by ajfour last updated on 01/Aug/17 $$\:\mathrm{y}=\mathrm{cos}^{−\mathrm{1}} \left(\frac{\mathrm{a}+\mathrm{bcos}\:\mathrm{x}}{\mathrm{b}+\mathrm{acos}\:\mathrm{x}}\right)…

prove-that-the-differentiation-of-1-x-2-1-x-2-1-x-2-1-x-2-with-respect-to-1-x-4-is-1-x-4-x-6-

Question Number 18905 by Arnab Maiti last updated on 01/Aug/17 $$\mathrm{prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{differentiation} \\ $$$$\mathrm{of}\frac{\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }−\sqrt{\mathrm{1}−\mathrm{x}^{\mathrm{2}} }}{\:\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }+\sqrt{\mathrm{1}−\mathrm{x}^{\mathrm{2}} }}\:\:\mathrm{with}\:\mathrm{respect} \\ $$$$\mathrm{to}\:\sqrt{\mathrm{1}−\mathrm{x}^{\mathrm{4}} }\:\:\mathrm{is}\:\:\frac{\sqrt{\mathrm{1}−\mathrm{x}^{\mathrm{4}} }}{\mathrm{x}^{\mathrm{6}} } \\ $$ Terms…