Question Number 149247 by saly last updated on 04/Aug/21 Commented by saly last updated on 04/Aug/21 $$\:\:{do}\:{you}\:{help}\:\:{me}? \\ $$ Commented by john_santu last updated on…
Question Number 149241 by john_santu last updated on 04/Aug/21 Answered by ajfour last updated on 04/Aug/21 $${s}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{x}^{\mathrm{3}} {dx}}{\left({x}−\mathrm{1}\right)^{\mathrm{3}} +\left(\mathrm{3}−{h}\right)\left({x}−\mathrm{1}\right)+{hx}} \\ $$$$\mathrm{3}−{h}=\mathrm{5}\:\:\:\Rightarrow\:\:{h}=−\mathrm{2} \\ $$$${s}_{\mathrm{1}}…
Question Number 83706 by jagoll last updated on 05/Mar/20 $$\mathrm{4}^{\mathrm{x}} \:+\:\mathrm{10}^{\mathrm{x}} \:=\:\mathrm{25}^{\mathrm{x}} \\ $$$$\mathrm{x}\:=\:? \\ $$ Answered by john santu last updated on 05/Mar/20 Terms…
Question Number 149240 by john_santu last updated on 04/Aug/21 $$\:\:\mathrm{solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{number}\: \\ $$$$\:\mathrm{x}^{\mathrm{4}} −\mathrm{3x}^{\mathrm{2}} +\mathrm{1}\:=\sqrt{\frac{\mathrm{4}}{\mathrm{4}−\mathrm{x}^{\mathrm{2}} }\:−\mathrm{1}} \\ $$$$\:\: \\ $$ Answered by MJS_new last updated on…
Question Number 149237 by mathdanisur last updated on 03/Aug/21 Answered by Mokmokhi last updated on 04/Aug/21 $$\mathrm{9} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 18167 by ajfour last updated on 16/Jul/17 Commented by ajfour last updated on 16/Jul/17 $$\mathrm{just}\:\mathrm{for}\:\mathrm{fun}. \\ $$ Commented by mrW1 last updated on…
Question Number 149239 by john_santu last updated on 04/Aug/21 $$\:\:\:\underset{{x}\rightarrow\mathrm{a}^{+} } {\mathrm{lim}}\:\frac{\sqrt{\mathrm{x}}−\sqrt{\mathrm{a}}\:−\sqrt{\mathrm{x}−\mathrm{a}}}{\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{a}^{\mathrm{2}} }}\:=?\: \\ $$ Answered by EDWIN88 last updated on 04/Aug/21 $$\:\underset{{x}\rightarrow{a}^{+} }…
Question Number 149238 by ajfour last updated on 04/Aug/21 $${z}^{\mathrm{3}} −{z}={c} \\ $$$${z}^{\mathrm{4}} −{z}^{\mathrm{2}} ={cz} \\ $$$${let}\:\:{z}={x}+{q} \\ $$$${x}^{\mathrm{4}} +\mathrm{4}{qx}^{\mathrm{3}} +\mathrm{6}{q}^{\mathrm{2}} {x}^{\mathrm{2}} +\mathrm{4}{q}^{\mathrm{3}} {x}+{q}^{\mathrm{4}} \\…
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Question Number 149234 by mathdanisur last updated on 03/Aug/21 $$\frac{{x}}{\mathrm{2}}\:+\:{log}_{\mathrm{2}} \left({x}\:+\:\mathrm{12}\right)\:=\:\mathrm{6} \\ $$$$\Rightarrow\:\boldsymbol{{x}}\:=\:? \\ $$ Answered by JDamian last updated on 03/Aug/21 $$\mathrm{4} \\ $$…