Question Number 149040 by mathdanisur last updated on 02/Aug/21 $$\begin{cases}{{x}^{\mathrm{2}} +{xy}=\mathrm{4}{x}}\\{{y}^{\mathrm{2}} +{xy}=\mathrm{4}{y}}\end{cases}\:\:\:\Rightarrow\:\:{log}_{\mathrm{16}} ^{\left(\boldsymbol{{x}}_{\mathrm{1}} +\boldsymbol{{y}}_{\mathrm{1}} +\boldsymbol{{x}}_{\mathrm{2}} +\boldsymbol{{y}}_{\mathrm{2}} \right)} \:=\:? \\ $$ Answered by bramlexs22 last updated…
Question Number 17970 by tawa tawa last updated on 13/Jul/17 Answered by 42 last updated on 13/Jul/17 $$\mathrm{C}_{\mathrm{3}} \mathrm{H}_{\mathrm{8}} \:+\:\mathrm{5O}_{\mathrm{2}} \:\rightarrow\:\mathrm{3CO}_{\mathrm{2}} \:+\:\mathrm{4H}_{\mathrm{2}} \mathrm{O} \\ $$…
Question Number 149043 by Tawa11 last updated on 02/Aug/21 Commented by EDWIN88 last updated on 02/Aug/21 $${x}=\mathrm{2} \\ $$ Commented by Tawa11 last updated on…
Question Number 17969 by tawa tawa last updated on 13/Jul/17 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 149042 by mathdanisur last updated on 02/Aug/21 $$\mathrm{100}\boldsymbol{{x}}^{\boldsymbol{{lg}}\left(\boldsymbol{{x}}\right)} \:=\:\boldsymbol{{x}}^{\mathrm{3}} \:\:\:\Rightarrow\:\:\:\boldsymbol{{x}}\:=\:? \\ $$ Answered by bramlexs22 last updated on 02/Aug/21 $$\Rightarrow\mathrm{100x}^{\mathrm{log}\:_{\mathrm{10}} \left(\mathrm{x}\right)} =\:\mathrm{x}^{\mathrm{3}} \\…
Question Number 149036 by mathdanisur last updated on 02/Aug/21 $${if}\:\:\:{x};{y};{z}>\mathrm{0}\:\:\:{and}\:\:\:{xyz}=\mathrm{8}\:\:\:{prove}\:{that}: \\ $$$$\frac{\mathrm{1}}{{x}^{\mathrm{2}} \:+\:\mathrm{8}}\:+\:\frac{\mathrm{1}}{{y}^{\mathrm{2}} \:+\:\mathrm{8}}\:+\:\frac{\mathrm{1}}{{z}^{\mathrm{2}} \:+\:\mathrm{8}}\:\leqslant\:\frac{\mathrm{1}}{\mathrm{4}} \\ $$ Answered by dumitrel last updated on 02/Aug/21 $${p}^{\mathrm{3}}…
Question Number 83500 by 20092104 last updated on 03/Mar/20 $$\frac{{d}}{{dx}}\left(\left({a}+{bx}\right)^{{c}+{dx}} \right) \\ $$ Answered by john santu last updated on 03/Mar/20 $$\mathrm{let}\:\mathrm{y}\:=\:\left(\mathrm{a}+\mathrm{bx}\right)^{\mathrm{c}+\mathrm{dx}} \\ $$$$\mathrm{ln}\:\mathrm{y}\:=\:\left(\mathrm{c}+\mathrm{dx}\right)\:\mathrm{ln}\:\left(\mathrm{a}+\mathrm{bx}\right) \\…
Question Number 17963 by ajfour last updated on 13/Jul/17 Commented by ajfour last updated on 13/Jul/17 $$\mathrm{AB}=\mathrm{2a}\:\:,\:\:\mathrm{CD}=\mathrm{2b} \\ $$$$\mathrm{Find}\:\boldsymbol{\mathrm{r}}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:\:\:\mathrm{a},\mathrm{b},\phi,\:\mathrm{and}\:\mathrm{R}. \\ $$$$\mathrm{Hence}\:\mathrm{find}\:\mathrm{AP}^{\mathrm{2}} +\mathrm{BP}^{\mathrm{2}} +\mathrm{CP}^{\mathrm{2}} +\mathrm{DP}^{\mathrm{2}} .…
Question Number 17961 by ketto last updated on 13/Jul/17 Answered by alex041103 last updated on 13/Jul/17 $${Let}\:{the}\:{total}\:{amount}\:{of}\:{money}\:{be}\:{M}. \\ $$$${And}\:{the}\:{money}\:{Lightness}\:{got}\:−\:{x} \\ $$$${Then} \\ $$$${M}=\frac{\mathrm{5}}{\mathrm{11}}{M}\:+\:\left(\mathrm{1}−\frac{\mathrm{5}}{\mathrm{11}}\right)\frac{\mathrm{7}}{\mathrm{12}}{M}\:+\:{x} \\ $$$$\Rightarrow{M}=\frac{\mathrm{5}}{\mathrm{11}}{M}+\frac{\mathrm{7}}{\mathrm{22}}{M}+{x}…
Question Number 17959 by tawa tawa last updated on 13/Jul/17 Answered by alex041103 last updated on 13/Jul/17 $${Because}\:{j}=\sqrt{−\mathrm{1}}={i}\:{we}\:{can}\:{use} \\ $$$${Euler}'{s}\:{formula} \\ $$$${e}^{{ix}} ={cos}\:{x}\:+\:{isin}\:{x} \\ $$$${z}={e}^{\mathrm{1}+{i}\frac{\pi}{\mathrm{2}}}…