Question Number 148932 by vvvv last updated on 01/Aug/21 $$\frac{\left(\boldsymbol{{b}}+\boldsymbol{{c}}\right)^{\mathrm{2}} }{\boldsymbol{{bc}}}\boldsymbol{{l}}_{\boldsymbol{{a}}} ^{\mathrm{2}} +\frac{\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)^{\mathrm{2}} }{\boldsymbol{{ab}}}\boldsymbol{{l}}_{\boldsymbol{{c}}} ^{\mathrm{2}} +\frac{\left(\boldsymbol{{a}}+\boldsymbol{{c}}\right)^{\mathrm{2}} }{\boldsymbol{{ac}}}\boldsymbol{{l}}_{\boldsymbol{{b}}} ^{\mathrm{2}} =\left(\boldsymbol{{a}}+\boldsymbol{{b}}+\boldsymbol{{c}}\right)^{\mathrm{2}} \\ $$$$\boldsymbol{{l}}_{\boldsymbol{{b}}} ,\boldsymbol{{l}}_{\boldsymbol{{a}}} ,\boldsymbol{{l}}_{\boldsymbol{{c}}} −\boldsymbol{{bissekterissa}} \\…
Question Number 83395 by Rio Michael last updated on 01/Mar/20 $$\mathrm{Let}\:\mathrm{R}\:\mathrm{be}\:\mathrm{a}\:\mathrm{relation}\:\mathrm{such}\:\mathrm{that}\: \\ $$$$\mathrm{R}\:=\:\left\{\mathrm{3},\mathrm{6},\mathrm{12},\mathrm{24}\right\} \\ $$$$\mathrm{prove}\:\mathrm{that}\:\mathrm{R}\:\mathrm{is}\:\mathrm{a}\:\mathrm{strict}\:\mathrm{order} \\ $$$$\mathrm{relation}.\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 17852 by Tinkutara last updated on 11/Jul/17 $$\mathrm{A}\:\mathrm{particle}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line} \\ $$$$\left({x}-\mathrm{axis}\right)\:\mathrm{with}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{shown}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{figure}.\:\mathrm{Knowing}\:\mathrm{that}\:{x}\:=\:−\mathrm{16}\:\mathrm{m}\:\mathrm{at} \\ $$$${t}\:=\:\mathrm{0},\:\mathrm{draw}\:\mathrm{the}\:{a}-{t}\:\mathrm{and}\:{x}-{t}\:\mathrm{curves}\:\mathrm{for} \\ $$$$\mathrm{the}\:\mathrm{interval}\:\mathrm{0}\:<\:{t}\:<\:\mathrm{40}\:\mathrm{s}\:\mathrm{and}\:\mathrm{determine} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Maximum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{position} \\ $$$$\mathrm{coordinate}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}. \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{The}\:\mathrm{values}\:\mathrm{of}\:{t}\:\mathrm{for}\:\mathrm{which}\:\mathrm{the} \\…
Question Number 148923 by BHOOPENDRA last updated on 01/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 83385 by M±th+et£s last updated on 01/Mar/20 $$\int\frac{\mathrm{1}+{ae}^{−\left({a}+\mathrm{1}\right){x}} +\left({a}+\mathrm{1}\right){e}^{−{ax}} }{{x}^{\mathrm{2}} }\:{dx},\:\:{a}\in{z}^{+} \\ $$ Commented by M±th+et£s last updated on 01/Mar/20 $${typo}\: \\ $$$$\int_{\mathrm{0}}…
Question Number 148917 by DELETED last updated on 01/Aug/21 Answered by DELETED last updated on 01/Aug/21 $$\mathrm{R}_{\mathrm{s2}} =\mathrm{16}+\mathrm{4}+\mathrm{5}=\mathrm{25}\:\Omega \\ $$$$\mathrm{i}_{\mathrm{total}} =\frac{\mathrm{V}}{\mathrm{R}_{\mathrm{s2}} }=\frac{\mathrm{12}.\mathrm{5}}{\mathrm{25}}\:=\:\mathrm{0}.\mathrm{5}\:\mathrm{A} \\ $$$$\mathrm{i}_{\mathrm{total}} =\mathrm{i}_{\mathrm{p}}…
Question Number 83383 by mhmd last updated on 01/Mar/20 $${find}\:\int_{\mathrm{0}} ^{\mathrm{2}} \int_{\mathrm{0}} ^{\sqrt{\mathrm{4}−{x}^{\mathrm{2}} }} \int_{\mathrm{0}} ^{\mathrm{2}−{z}} {zdxdydz} \\ $$$${pleas}\:{help}\:{me}\:{sir} \\ $$ Answered by mr W…
Question Number 83381 by Rio Michael last updated on 01/Mar/20 $$\mathrm{Given}\:\mathrm{that}\:\mathrm{the}\:\mathrm{function}\:{f}\left({x}\right)\:=\:{x}^{\mathrm{3}} \:\mathrm{is}\: \\ $$$$\mathrm{differentiable}\:\mathrm{in}\:\mathrm{the}\:\mathrm{interval}\:\left(−\mathrm{2},\mathrm{2}\right)\:\mathrm{us}\:\mathrm{the}\:\mathrm{mean} \\ $$$$\mathrm{value}\:\mathrm{theorem}\:\mathrm{to}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{x}\:\mathrm{for}\:\mathrm{which}\:\mathrm{the}\: \\ $$$$\mathrm{tangent}\:\mathrm{to}\:\mathrm{the}\:\mathrm{curve}\:\mathrm{is}\:\mathrm{parrallel}\:\mathrm{to}\:\mathrm{the}\:\mathrm{chord}\: \\ $$$$\mathrm{through}\:\mathrm{the}\:\mathrm{points}\:\left(−\mathrm{2},\mathrm{8}\right)\:\mathrm{and}\:\left(\mathrm{2},\mathrm{8}\right). \\ $$ Terms of Service…
Question Number 83378 by M±th+et£s last updated on 01/Mar/20 $${x}+{y}+{z}=\mathrm{1} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\mathrm{2} \\ $$$${x}^{\mathrm{3}} +{y}^{\mathrm{3}} +{z}^{\mathrm{3}} =\mathrm{3} \\ $$$${find} \\ $$$${x}^{\mathrm{4}} +{y}^{\mathrm{4}}…
Question Number 148915 by DELETED last updated on 01/Aug/21 Answered by DELETED last updated on 01/Aug/21 $$\frac{\mathrm{1}}{\mathrm{Rp}}\:=\:\frac{\mathrm{1}}{\mathrm{8}}+\frac{\mathrm{1}}{\mathrm{8}}=\frac{\mathrm{2}}{\mathrm{8}}=\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\mathrm{Rp}=\mathrm{4}\:\Omega \\ $$$$ \\ $$$$\mathrm{V}_{\mathrm{p}} =\mathrm{V}_{\mathrm{rs1}} =\mathrm{2}\:\mathrm{Vol}…