Question Number 82871 by abdomathmax last updated on 25/Feb/20 $${find}\:\int\int_{\left[\mathrm{0},\mathrm{1}\right]^{\mathrm{2}} } \:\:\:\mid{x}^{\mathrm{2}} −{y}^{\mathrm{2}} \mid{dxdy} \\ $$ Commented by mathmax by abdo last updated on 25/Feb/20…
Question Number 82867 by mind is power last updated on 24/Feb/20 $${hello}\:{prove}\:{that}\:\int_{\mathrm{0}} ^{+\infty} {sin}\left({x}^{\mathrm{4}} \right){dx}={sin}\left(\frac{\pi}{\mathrm{8}}\right)\int_{\mathrm{0}} ^{+\infty} {e}^{−{x}^{\mathrm{4}} } {dx}? \\ $$$${verry}\:{nice}\:{day}\:{Good}\:{Bless}\:{You} \\ $$ Commented by…
Question Number 148403 by Jonathanwaweh last updated on 27/Jul/21 Answered by Olaf_Thorendsen last updated on 27/Jul/21 $$\mathrm{Soit}\:\mathrm{G}\:\mathrm{un}\:\mathrm{point}\:\mathrm{du}\:\mathrm{plan}\:\mathrm{contenant} \\ $$$$\mathrm{A}\:\mathrm{et}\:\mathrm{B}.\:\mathrm{Alors}\:\mathrm{G}\:\mathrm{est}\:\mathrm{le}\:\mathrm{barycentre}\:\mathrm{des} \\ $$$$\mathrm{points}\:\mathrm{A}\:\mathrm{et}\:\mathrm{B}\:\mathrm{affecte}\:\mathrm{respectivement} \\ $$$$\mathrm{des}\:\mathrm{coefficients}\:{a}\:\mathrm{et}\:{b}\:\mathrm{de}\:\mathrm{somme}\:\mathrm{non} \\ $$$$\mathrm{nulle}\:{a}+{b}\:\neq\:\mathrm{0}\:\mathrm{si},\:\mathrm{par}\:\mathrm{definition}\:\mathrm{du}…
Question Number 17328 by tawa tawa last updated on 04/Jul/17 Commented by tawa tawa last updated on 04/Jul/17 $$\mathrm{Please}\:\mathrm{my}\:\mathrm{main}\:\mathrm{problem}\:\mathrm{is}\:\mathrm{the}\:\left(\mathrm{c}\right) \\ $$$$\mathrm{with}\:\mathrm{my}\:\mathrm{understanding},\:\mathrm{i}\:\mathrm{thought}\:\mathrm{the}\:\left(\mathrm{c}\right)\:\mathrm{is}\:\mathrm{the}\:\mathrm{same}\:\mathrm{thing}\:\mathrm{as}\:\mathrm{the}\:\mathrm{volumetric}\: \\ $$$$\mathrm{analysis}\:\mathrm{given}.\: \\ $$$$\mathrm{do}\:\mathrm{i}\:\mathrm{need}\:\mathrm{to}\:\mathrm{calculate}\:\mathrm{anything}\:\mathrm{or}\:\mathrm{am}\:\mathrm{not}\:\mathrm{getting}\:\mathrm{it}…
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Question Number 148398 by puissant last updated on 27/Jul/21 Answered by Olaf_Thorendsen last updated on 27/Jul/21 $$\mathrm{1}.\:\mathrm{C}_{\mathrm{1}} \:=\:\mathrm{7}{l}\:\mathrm{et}\:\mathrm{C}_{\mathrm{2}} \:=\:\mathrm{4}{l} \\ $$$$ \\ $$$$\bullet\:\mathrm{Etape}\:\mathrm{1}. \\ $$$$\mathrm{Je}\:\mathrm{remplis}\:\mathrm{C}_{\mathrm{1}}…
Question Number 17323 by tawa tawa last updated on 04/Jul/17 $$\mathrm{Solve}:\:\:\:\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{2cos}\left(\mathrm{2x}\right)}{\mathrm{3}\:−\:\mathrm{2y}}\:\:\:\:\:\:\:\:\:\:\:\mathrm{with}\:\:\:\:\mathrm{y}\left(\mathrm{0}\right)\:=\:−\mathrm{1} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{for}\:\mathrm{what}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:>\:\mathrm{0}\:\mathrm{does}\:\mathrm{the}\:\mathrm{situation}\:\mathrm{exist} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{for}\:\mathrm{what}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:\mathrm{is}\:\mathrm{y}\left(\mathrm{x}\right)\:\mathrm{maximum} \\ $$ Answered by Tinkutara last updated on 04/Jul/17 $$\left(\mathrm{3}\:−\:\mathrm{2}{y}\right)\:{dy}\:=\:\mathrm{2}\:\mathrm{cos}\:\mathrm{2}{x}\:{dx}…
Question Number 17322 by tawa tawa last updated on 04/Jul/17 $$\mathrm{Solve}:\:\:\:\frac{\mathrm{dy}}{\mathrm{dx}}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{y}\:=\:\frac{\mathrm{3}}{\mathrm{2}}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{with}\:\:\:\mathrm{y}\left(\mathrm{0}\right)\:=\:\mathrm{4} \\ $$ Answered by mrW1 last updated on 04/Jul/17 $$\mathrm{2}\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{3}−\mathrm{y} \\ $$$$−\frac{\mathrm{dy}}{\mathrm{y}−\mathrm{3}}=\frac{\mathrm{dx}}{\mathrm{2}} \\ $$$$\int\frac{\mathrm{dy}}{\mathrm{y}−\mathrm{3}}=−\int\frac{\mathrm{dx}}{\mathrm{2}}…
Question Number 148395 by mathdanisur last updated on 27/Jul/21 $$\boldsymbol{{x}}^{\boldsymbol{{x}}} \:=\:\mathrm{64} \\ $$$$\Rightarrow\:\boldsymbol{{x}}\:=\:? \\ $$ Answered by Math_Freak last updated on 27/Jul/21 $${if}\:{x}>\mathrm{0} \\ $$$${xlnx}\:=\:{ln}\mathrm{64}…
Question Number 148388 by mathdanisur last updated on 27/Jul/21 $${cos}\mathrm{40}°\left(\mathrm{1}\:-\:\mathrm{2}{cos}\mathrm{80}°\right)\:=\:? \\ $$ Answered by liberty last updated on 27/Jul/21 $$\mathrm{cos}\:\mathrm{40}°\left(\mathrm{1}−\mathrm{2}\left(\mathrm{2cos}\:^{\mathrm{2}} \mathrm{40}°−\mathrm{1}\right)\right) \\ $$$$=\:\mathrm{cos}\:\mathrm{40}°\left(\mathrm{3}−\mathrm{4cos}\:^{\mathrm{2}} \mathrm{40}°\right) \\…