Question Number 82608 by arthur.kangdani@gmail.com last updated on 23/Feb/20 Commented by jagoll last updated on 23/Feb/20 $$=\:\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 17073 by Kunal kumar shukla last updated on 30/Jun/17 Commented by Kunal kumar shukla last updated on 30/Jun/17 $${wrong}\:{answer} \\ $$ Commented by…
Question Number 82609 by arthur.kangdani@gmail.com last updated on 23/Feb/20 Commented by jagoll last updated on 23/Feb/20 $$=\:\mathrm{0}\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 82607 by arthur.kangdani@gmail.com last updated on 23/Feb/20 Commented by jagoll last updated on 23/Feb/20 $$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{\mathrm{4}−{x}^{\mathrm{2}} }{\mathrm{4}−{x}^{\mathrm{2}} }\:×\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\mathrm{3}+\sqrt{{x}^{\mathrm{2}} +\mathrm{5}}\:=\:\mathrm{1}×\mathrm{6}\:=\:\mathrm{6} \\ $$ Commented…
Question Number 82604 by jagoll last updated on 23/Feb/20 $$\int\:\frac{\mathrm{cos}\:\left(\mathrm{5}{x}\right)+\mathrm{cos}\:\left(\mathrm{4}{x}\right)\:{dx}}{\mathrm{1}−\mathrm{2cos}\:\left(\mathrm{3}{x}\right)}\:=\: \\ $$ Answered by john santu last updated on 23/Feb/20 $$\int\:\:\frac{\left\{\mathrm{cos}\:\left(\mathrm{5}{x}\right)+\mathrm{cos}\:\left(\mathrm{4}{x}\right)\right\}\mathrm{sin}\:\left(\mathrm{3}{x}\right)}{\mathrm{sin}\:\left(\mathrm{3}{x}\right)−\mathrm{sin}\:\left(\mathrm{6}{x}\right)}\:{dx} \\ $$$$=\mathrm{2}\int\:\frac{\left\{\mathrm{cos}\:\left(\frac{\mathrm{9}{x}}{\mathrm{2}}\right)\mathrm{cos}\:\left(\frac{{x}}{\mathrm{2}}\right)\right\}\mathrm{sin}\:\left(\mathrm{3}{x}\right)}{\mathrm{2cos}\:\left(\frac{\mathrm{9}{x}}{\mathrm{2}}\right)\mathrm{sin}\:\left(−\frac{\mathrm{3}{x}}{\mathrm{2}}\right)}\:{dx} \\ $$$$=\:−\:\int\:\frac{\mathrm{sin}\:\left(\mathrm{3}{x}\right)\mathrm{cos}\:\left(\frac{{x}}{\mathrm{2}}\right)}{\mathrm{sin}\:\left(\frac{\mathrm{3}{x}}{\mathrm{2}}\right)}\:{dx}\:…
Question Number 17068 by chux last updated on 30/Jun/17 $$\mathrm{prove}\:\mathrm{that}\: \\ $$$$ \\ $$$$\mathrm{4tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{5}}\right)−\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{239}}\right)\:=\pi/\mathrm{4} \\ $$ Answered by ajfour last updated on 30/Jun/17…
Question Number 148137 by Willson last updated on 25/Jul/21 $$\int\:\:\frac{\mathrm{3}{cos}^{\mathrm{2}} \left({x}\right)+\mathrm{1}}{{sin}^{\mathrm{5}} \left({x}\right)}{dx}\:=\:??? \\ $$ Answered by puissant last updated on 25/Jul/21 $$=\int\frac{\mathrm{4cos}^{\mathrm{2}} \left(\mathrm{x}\right)+\mathrm{sin}^{\mathrm{2}} \left(\mathrm{x}\right)}{\mathrm{sin}^{\mathrm{5}} \left(\mathrm{x}\right)}\mathrm{dx}=\int\frac{\mathrm{4}+\mathrm{tan}^{\mathrm{2}}…
Question Number 17065 by mrW1 last updated on 30/Jun/17 $$\mathrm{if}\:\mathrm{y}=\mathrm{x}^{\mathrm{x}} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:\mathrm{this}\:\mathrm{function}? \\ $$ Commented by ajfour last updated on 30/Jun/17 $$\mathrm{y}\in\left[\mathrm{e}^{−\mathrm{1}/\mathrm{e}} ,\infty\right). \\ $$…
Question Number 148132 by Jonathanwaweh last updated on 25/Jul/21 Answered by Olaf_Thorendsen last updated on 25/Jul/21 $$\mathrm{1}. \\ $$$$\mathrm{ABCD}\:\mathrm{est}\:\mathrm{un}\:\mathrm{rectangle}\:\mathrm{et}\:\mathrm{possede} \\ $$$$\mathrm{donc}\:\mathrm{4}\:\mathrm{angles}\:\mathrm{droits}\:\mathrm{que}\:\mathrm{les} \\ $$$$\mathrm{bissectrices}\:\mathrm{divisent}\:\mathrm{a}\:\mathrm{45}°. \\ $$$$\mathrm{On}\:\mathrm{a}\:\mathrm{donc}\::…
Question Number 82596 by peter frank last updated on 22/Feb/20 Commented by mr W last updated on 23/Feb/20 $$\left({a}\right) \\ $$$${i}\:{think}\:{the}\:{beam}\:{will}\:{stay}\:{in}\:{water}. \\ $$$$\left({b}\right) \\ $$$${the}\:{beam}\:{will}\:{be}\:{partially}\:{reflected}…