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Question Number 148042 by mathdanisur last updated on 25/Jul/21 $$\sqrt{\mathrm{17}\:−\:\mathrm{4}\sqrt{\mathrm{15}}}\:−\:\sqrt[{\mathrm{4}}]{\mathrm{144}}\:=\:? \\ $$ Answered by Olaf_Thorendsen last updated on 25/Jul/21 $$\mathrm{X}\:=\:\sqrt{\mathrm{17}−\mathrm{4}\sqrt{\mathrm{15}}}−\sqrt[{\mathrm{4}}]{\mathrm{144}} \\ $$$$\mathrm{X}\:=\:\sqrt{\left(\mathrm{2}\sqrt{\mathrm{3}}−\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }−\sqrt[{\mathrm{4}}]{\mathrm{12}^{\mathrm{2}} } \\…
Question Number 148033 by iloveisrael last updated on 25/Jul/21 Commented by iloveisrael last updated on 25/Jul/21 $$\:\frac{\mathrm{2}^{\mathrm{2020}} +\mathrm{1}}{\mathrm{2}^{\mathrm{2018}} +\mathrm{1}}\:+\:\frac{\mathrm{3}^{\mathrm{2020}} +\mathrm{1}}{\mathrm{3}^{\mathrm{2018}} +\mathrm{1}}\:+\frac{\mathrm{4}^{\mathrm{2020}} +\mathrm{1}}{\mathrm{4}^{\mathrm{2018}} +\mathrm{1}}\:+\frac{\mathrm{5}^{\mathrm{2020}} +\mathrm{1}}{\mathrm{5}^{\mathrm{2018}} +\mathrm{1}}\:+\frac{\mathrm{6}^{\mathrm{2020}}…
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Question Number 82499 by Maclaurin Stickket last updated on 21/Feb/20 Commented by Maclaurin Stickket last updated on 21/Feb/20 $${ABCD}\:{is}\:{a}\:{square}\:{with}\:{side}\:\mathrm{1}. \\ $$$${The}\:{circles}\:{are}\:{congruent}. \\ $$$${AC}\:{is}\:{the}\:{diagonal}\:{of}\:{square}. \\ $$$${Find}\:{the}\:{radius}\:{r}.…
Question Number 148035 by mathdanisur last updated on 25/Jul/21 $${if}\:\:\:{f}\left({g}\left({x}\right)\right)\:=\:\mathrm{2}{x}\:-\:\mathrm{5}\:\:{and}\:\:{f}\left({x}\right)\:=\:{x}\:+\:\mathrm{2} \\ $$$${find}\:\:\:{g}\left({x}\right)\:=\:? \\ $$ Commented by prakash jain last updated on 25/Jul/21 $${f}\left({x}\right)={x}+\mathrm{2} \\ $$$${f}\left({g}\left({x}\right)\right)={g}\left({x}\right)+\mathrm{2}…
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Question Number 82494 by niroj last updated on 21/Feb/20 $$\:\: \\ $$$$\:\:\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{limit}} \\ $$$$\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{0}} {\overset{\boldsymbol{\mathrm{lim}}} {\:}}\:\left(\frac{\boldsymbol{\mathrm{tan}}\:\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{x}}}\right)^{\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}^{\:\mathrm{2}} }} \\ $$ Commented by abdomathmax last updated on…
Question Number 16958 by Tinkutara last updated on 28/Jun/17 $$\mathrm{Let}\:{ABCD}\:\mathrm{be}\:\mathrm{a}\:\mathrm{quadrilateral}\:\mathrm{with}\:\mathrm{an} \\ $$$$\mathrm{inscribed}\:\mathrm{circle}.\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{circles} \\ $$$$\mathrm{inscribed}\:\mathrm{in}\:\mathrm{triangles}\:{ABC}\:\mathrm{and}\:{ADC} \\ $$$$\mathrm{are}\:\mathrm{tangent}\:\mathrm{to}\:\mathrm{each}\:\mathrm{other}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 148027 by mathdanisur last updated on 25/Jul/21 $${if}\:\:\:\mathrm{2}{x}^{\mathrm{3}} \:+\:\mathrm{3}{y}^{\mathrm{3}} \:=\:\mathrm{200}\:\:\Rightarrow\:\:\left({x}^{\mathrm{2}} {y}^{\mathrm{2}} \right)_{\boldsymbol{{max}}} \:=\:? \\ $$ Commented by mr W last updated on 25/Jul/21…