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Question Number 82426 by zainal tanjung last updated on 21/Feb/20 $$\mathrm{Lim}\:\frac{\mathrm{e}^{\mathrm{x}} −\mathrm{1}−\mathrm{x}^{\mathrm{2}} }{\mathrm{x}^{\mathrm{4}} +\mathrm{x}^{\mathrm{3}} +\mathrm{x}^{\mathrm{2}} }\:=\:… \\ $$$$\mathrm{x}\rightarrow\mathrm{0} \\ $$ Commented by jagoll last updated…
Question Number 82425 by zainal tanjung last updated on 21/Feb/20 $$\mathrm{Lim}\:\left(\frac{\mathrm{1}}{\mathrm{ex}}\right)^{\mathrm{6x}} =….. \\ $$$$\mathrm{x}\rightarrow\mathrm{0} \\ $$ Commented by abdomathmax last updated on 21/Feb/20 $${let}\:{f}\left({x}\right)=\left(\frac{\mathrm{1}}{{ex}}\right)^{\mathrm{6}{x}} \:\Rightarrow{f}\left({x}\right)={e}^{−\mathrm{6}{xln}\left({ex}\right)}…
Question Number 82421 by M±th+et£s last updated on 21/Feb/20 Answered by mind is power last updated on 21/Feb/20 $${let}\:{y}\in\left[{a},{b}\right]\:{such}\:{sup}\:{f}={f}\left({y}\right) \\ $$$${let}\:{z}\in\left[{a},{b}\right]\:{such}\:{sup}\:{g}={g}\left({z}\right) \\ $$$${if}\:{z}={y}\Rightarrow{c}={y}\Rightarrow{f}\left({c}\right)={g}\left({c}\right) \\ $$$${if}\:{z}#{y}\:{assum}\:{z}<{y}…
Question Number 16882 by RasheedSoomro last updated on 27/Jun/17 $$\:^{\bullet} \mathrm{In}\:\mathrm{plane}\:\mathrm{parallel}\:\mathrm{lines}\:\mathrm{are}\:\mathrm{the}\:\mathrm{lines} \\ $$$$\mathrm{which}\:\mathrm{don}'\mathrm{t}\:\mathrm{meet}\:\mathrm{each}\:\mathrm{other}. \\ $$$$ \\ $$$$\:^{\bullet} \mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{condition}\:\mathrm{in}\:\mathrm{space} \\ $$$$\mathrm{that}\:\mathrm{two}\:\mathrm{lines}\:\mathrm{be}\:\mathrm{parallel}? \\ $$ Commented by prakash…
Question Number 82416 by TawaTawa last updated on 21/Feb/20 Commented by TawaTawa last updated on 21/Feb/20 $$\mathrm{Please}\:\mathrm{help}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 16881 by Tinkutara last updated on 27/Jun/17 $$\mathrm{The}\:\mathrm{quadratic}\:\mathrm{polynomials} \\ $$$${p}\left({x}\right)\:=\:{a}\left({x}\:−\:\mathrm{3}\right)^{\mathrm{2}} \:+\:{bx}\:+\:\mathrm{1}\:\mathrm{and} \\ $$$${q}\left({x}\right)\:=\:\mathrm{2}{x}^{\mathrm{2}} \:+\:{c}\left({x}\:−\:\mathrm{2}\right)\:+\:\mathrm{13}\:\mathrm{are}\:\mathrm{equal} \\ $$$$\mathrm{for}\:\mathrm{all}\:\mathrm{values}\:\mathrm{of}\:{x}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:{a}, \\ $$$${b},\:\mathrm{and}\:{c}. \\ $$ Answered by RasheedSoomro…
Question Number 16880 by Tinkutara last updated on 27/Jun/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{positive}\:\mathrm{integers} \\ $$$$\mathrm{less}\:\mathrm{than}\:\mathrm{or}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{300}\:\mathrm{that}\:\mathrm{are} \\ $$$$\mathrm{multiples}\:\mathrm{of}\:\mathrm{3}\:\mathrm{or}\:\mathrm{5},\:\mathrm{but}\:\mathrm{are}\:\mathrm{not} \\ $$$$\mathrm{multiples}\:\mathrm{of}\:\mathrm{10}\:\mathrm{or}\:\mathrm{15}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 16879 by Tinkutara last updated on 27/Jun/17 $$\mathrm{Let}\:{ABCD}\:\mathrm{be}\:\mathrm{a}\:\mathrm{parallelogram}.\:\mathrm{The} \\ $$$$\mathrm{points}\:{M},\:{N}\:\mathrm{and}\:{P}\:\mathrm{are}\:\mathrm{chosen}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{segments}\:{BD},\:{BC}\:\mathrm{and}\:{CD}, \\ $$$$\mathrm{respectively},\:\mathrm{so}\:\mathrm{that}\:{CNMP}\:\mathrm{is}\:\mathrm{a} \\ $$$$\mathrm{parallelogram}.\:\mathrm{Let}\:{E}\:=\:{AN}\:\cap\:{BD}\:\mathrm{and} \\ $$$${F}\:=\:{AP}\:\cap\:{BD}.\:\mathrm{Prove}\:\mathrm{that} \\ $$$$\left[{AEF}\right]\:=\:\left[{DFP}\right]\:+\:\left[{BEN}\right]. \\ $$ Terms…
Question Number 147948 by tabata last updated on 24/Jul/21 Commented by tabata last updated on 24/Jul/21 $${Msr}\:{olaf}\:{help}\:{me}\:{please}\:? \\ $$ Answered by Olaf_Thorendsen last updated on…