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Author: Tinku Tara

x-2-6x-3-0-2x-2-3-6-x-2-

Question Number 147941 by mathdanisur last updated on 24/Jul/21 $${x}^{\mathrm{2}} \:-\:\mathrm{6}{x}\:+\:\mathrm{3}\:=\:\mathrm{0}\:\:\:\Rightarrow\:\:\:\frac{\mathrm{2}{x}^{\mathrm{2}} }{\mathrm{3}}\:+\:\frac{\mathrm{6}}{{x}^{\mathrm{2}} }\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated on 24/Jul/21 $${x}^{\mathrm{2}} \:-\:\mathrm{6}{x}\:+\:\mathrm{3}\:=\:\mathrm{0}\Rightarrow{x}^{\mathrm{2}} =\mathrm{6}{x}−\mathrm{3}…

x-2-x-2-x-1-

Question Number 147943 by mathdanisur last updated on 24/Jul/21 $$\int\:\frac{\left({x}^{\mathrm{2}} \:+\:{x}\right)^{\mathrm{2}} }{{x}\:+\:\mathrm{1}}\:=\:? \\ $$ Commented by tabata last updated on 24/Jul/21 $$=\int\:\frac{{x}^{\mathrm{2}} \left({x}+\mathrm{1}\right)^{\mathrm{2}} }{\left({x}+\mathrm{1}\right)}{dx}=\int\:{x}^{\mathrm{2}} \left({x}+\mathrm{1}\right){dx}=\frac{{x}^{\mathrm{4}}…

if-f-x-f-x-4-8-and-f-2-4-find-f-10-

Question Number 147942 by mathdanisur last updated on 24/Jul/21 $${if}\:\:\:{f}\left({x}\right)={f}\left({x}−\mathrm{4}\right)+\mathrm{8}\:\:\:{and}\:\:\:{f}\left(\mathrm{2}\right)=\mathrm{4} \\ $$$${find}\:\:\:{f}\left(\mathrm{10}\right)=? \\ $$ Answered by Olaf_Thorendsen last updated on 24/Jul/21 $${f}\left({x}\right)\:=\:{f}\left({x}−\mathrm{4}\right)+\mathrm{8} \\ $$$$ \\…

In-how-many-ways-can-the-letters-of-the-word-EVERMORE-be-arrange-if-the-word-must-begin-with-i-R-ii-E-

Question Number 16868 by tawa tawa last updated on 27/Jun/17 $$\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{the}\:\mathrm{letters}\:\mathrm{of}\:\mathrm{the}\:\mathrm{word}.\:\mathrm{EVERMORE}\:\mathrm{be}\:\mathrm{arrange} \\ $$$$\mathrm{if}\:\mathrm{the}\:\mathrm{word}\:\mathrm{must}\:\mathrm{begin}\:\mathrm{with}\: \\ $$$$\left(\mathrm{i}\right)\:\mathrm{R} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{E} \\ $$ Answered by mrW1 last updated on…

Solve-the-inequality-pi-3-2sin2x-pi-3-2-

Question Number 147936 by mathdanisur last updated on 24/Jul/21 $${Solve}\:{the}\:{inequality} \\ $$$$\left(\pi\:-\:\mathrm{3}\right)^{\mathrm{2}\boldsymbol{{sin}}\mathrm{2}\boldsymbol{{x}}} \:\leqslant\:\left(\pi\:-\:\mathrm{3}\right)^{\mathrm{2}} \\ $$ Answered by iloveisrael last updated on 24/Jul/21 $$\Rightarrow\pi−\mathrm{3}\:>\mathrm{1}\:\mathrm{then}\:\mathrm{2sin}\:\mathrm{2x}\:\leqslant\mathrm{2} \\ $$$$\Rightarrow\mathrm{sin}\:\mathrm{2x}\:\leqslant\mathrm{1}\:…

Simplify-1-1-cos2x-1-1-cos4x-1-1-cos8x-

Question Number 147933 by mathdanisur last updated on 24/Jul/21 $${Simplify} \\ $$$$\left(\mathrm{1}+\:\frac{\mathrm{1}}{{cos}\mathrm{2}{x}}\right)\centerdot\left(\mathrm{1}+\frac{\mathrm{1}}{{cos}\mathrm{4}{x}}\right)\centerdot\left(\mathrm{1}+\frac{\mathrm{1}}{{cos}\mathrm{8}{x}}\right)=? \\ $$ Answered by som(math1967) last updated on 24/Jul/21 $$\frac{{tanx}}{{tanx}}\left(\mathrm{1}+\frac{\mathrm{1}+{tan}^{\mathrm{2}} {x}}{\mathrm{1}−{tan}^{\mathrm{2}} {x}}\right)\left(\mathrm{1}+\frac{\mathrm{1}+{tan}^{\mathrm{2}} \mathrm{2}{x}}{\mathrm{1}−{tan}^{\mathrm{2}}…

if-1-sin2x-1-sin2x-17-12-2-find-sinx-cosx-cosx-sinx-

Question Number 147932 by mathdanisur last updated on 24/Jul/21 $${if}\:\:\:\frac{\mathrm{1}−{sin}\mathrm{2}{x}}{\mathrm{1}\:+\:{sin}\mathrm{2}{x}}\:=\:\sqrt{\mathrm{17}\:+\:\mathrm{12}\sqrt{\mathrm{2}}} \\ $$$${find}\:\:\:\mid\frac{{sinx}\:+\:{cosx}}{{cosx}\:-\:{sinx}}\mid\:=\:? \\ $$ Answered by iloveisrael last updated on 24/Jul/21 $$\mid\mathrm{x}\mid=\sqrt{\mathrm{x}^{\mathrm{2}} } \\ $$$$\mid\frac{\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}}{\mathrm{cos}\:\mathrm{x}−\mathrm{sin}\:\mathrm{x}}\mid\:=\sqrt{\frac{\mathrm{1}+\mathrm{sin}\:\mathrm{2x}}{\mathrm{1}−\mathrm{sin}\:\mathrm{2x}}}\:…