Question Number 147893 by mathdanisur last updated on 24/Jul/21 $${x}\:+\:\mathrm{1}\:+\:\frac{\mathrm{1}}{{x}}\:=\:\mathrm{4}\:\:\Rightarrow\:\:{x}\:+\:\mathrm{1}\:-\:\frac{\mathrm{1}}{{x}}\:=\:? \\ $$ Commented by aliibrahim1 last updated on 24/Jul/21 $${x}+\frac{\mathrm{1}}{{x}}=\mathrm{3}\Rrightarrow\:\:\:\:\:\left({x}+\frac{\mathrm{1}}{{x}}\right)^{\mathrm{2}} =\mathrm{3}^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} +\frac{\mathrm{1}}{{x}^{\mathrm{2}} }+\mathrm{2}=\mathrm{9}…
Question Number 82358 by TawaTawa last updated on 20/Feb/20 $$\mathrm{Show}\:\mathrm{that}:\:\:\:\:\:\:\:\mathrm{a}_{\mathrm{n}} \:\:=\:\:−\:\mathrm{r}\omega^{\mathrm{2}} \:,\:\:\:\mathrm{show}\:\mathrm{clearly}\:\mathrm{how}\:\mathrm{you}\:\mathrm{arrive} \\ $$$$\mathrm{at}\:\mathrm{your}\:\mathrm{result}. \\ $$ Commented by TawaTawa last updated on 20/Feb/20 $$\mathrm{Please}\:\mathrm{help} \\…
Question Number 16823 by tawa tawa last updated on 26/Jun/17 $$\mathrm{solve}\:\mathrm{for}\:\mathrm{g}. \\ $$$$\mathrm{6}\left(\mathrm{4}^{\mathrm{x}} \:+\:\mathrm{g}^{\mathrm{x}} \right)\:=\:\mathrm{13}.\mathrm{6}^{\mathrm{x}} \\ $$ Commented by mrW1 last updated on 26/Jun/17 $$\mathrm{x}\neq\mathrm{0}…
Question Number 147892 by mathdanisur last updated on 24/Jul/21 $${if}\:\:\:{x};{y};{z}>\mathrm{1}\:\:\:{then}: \\ $$$$\sqrt{\frac{\left({x}−\mathrm{1}\right)\left({y}−\mathrm{1}\right)\left({z}−\mathrm{1}\right)}{\left({x}+\mathrm{1}\right)\left({y}+\mathrm{1}\right)\left({z}+\mathrm{1}\right)}\:}\:<\:\frac{{xyz}}{\mathrm{8}} \\ $$ Answered by mindispower last updated on 24/Jul/21 $$\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}<\frac{{x}^{\mathrm{2}} }{\mathrm{4}}…?\:\forall{x}>\mathrm{1} \\ $$$$\Leftrightarrow\mathrm{4}\left({x}−\mathrm{1}\right)<{x}^{\mathrm{2}}…
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Question Number 82356 by M±th+et£s last updated on 20/Feb/20 Commented by M±th+et£s last updated on 20/Feb/20 $${show}\:{that} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 147894 by mathdanisur last updated on 24/Jul/21 $${x}^{\mathrm{2}} \:-\:\mathrm{3}{x}\:+\:\mathrm{4}\:=\:\mathrm{0}\:\:\Rightarrow\:\:{x}^{\mathrm{2}} \:+\:\frac{\mathrm{16}}{{x}^{\mathrm{2}} }\:=\:? \\ $$ Answered by mindispower last updated on 24/Jul/21 $$\Leftrightarrow{x}+\frac{\mathrm{4}}{{x}}=\mathrm{3} \\ $$$$\Rightarrow{x}^{\mathrm{2}}…
Question Number 82350 by jagoll last updated on 20/Feb/20 $$\mathrm{2}{y}''\:+\mathrm{5}{y}'\:−\mathrm{3}{y}=\mathrm{0} \\ $$$${general}\:{and}\:{particular}\:{solution} \\ $$$${when}\:{x}\:=\mathrm{0}\:,\:{y}\:=\:\mathrm{4}\:{and}\:\frac{{dy}}{{dx}}\:=\:\mathrm{9}? \\ $$ Commented by jagoll last updated on 20/Feb/20 Terms of…
Question Number 147884 by ArielVyny last updated on 24/Jul/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {e}^{−{x}} {x}^{{a}} {dx}\:\:{a}>\mathrm{0} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 82349 by Tony Lin last updated on 20/Feb/20 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{{n}^{\mathrm{2}} +\mathrm{1}}=? \\ $$ Answered by mind is power last updated on 21/Feb/20…