Question Number 147688 by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{find}\:\mathrm{lim}_{\mathrm{n}\rightarrow+\infty} \int_{\frac{\mathrm{1}}{\mathrm{n}}} ^{\sqrt{\mathrm{n}}} \:\:\:\mathrm{xe}^{−\mathrm{x}^{\mathrm{2}} } \mathrm{arctan}\left(\mathrm{nx}\right)\mathrm{dx} \\ $$ Answered by ArielVyny last updated on…
Question Number 16616 by Tinkutara last updated on 24/Jun/17 $$\mathrm{A}\:\mathrm{particle}\:\mathrm{starts}\:\mathrm{from}\:\mathrm{the}\:\mathrm{origin}\:\mathrm{with} \\ $$$$\mathrm{velocity}\:\sqrt{\mathrm{44}}\:\mathrm{ms}^{−\mathrm{1}} \:\mathrm{on}\:\mathrm{a}\:\mathrm{straight} \\ $$$$\mathrm{horizontal}\:\mathrm{road}.\:\mathrm{Its}\:\mathrm{acceleration}\:\mathrm{varies} \\ $$$$\mathrm{with}\:\mathrm{displacement}\:\mathrm{as}\:\mathrm{shown}.\:\mathrm{The} \\ $$$$\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{as}\:\mathrm{it}\:\mathrm{passes} \\ $$$$\mathrm{through}\:\mathrm{the}\:\mathrm{position}\:{x}\:=\:\mathrm{0}.\mathrm{2}\:\mathrm{km}\:\mathrm{is} \\ $$$$\left[\mathrm{Answer}:\:\mathrm{18}\:\mathrm{ms}^{−\mathrm{1}} \right] \\…
Question Number 147685 by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{calculate}\:\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{0}} \:\frac{\mathrm{sin}\left(\mathrm{2sinx}\right)}{\mathrm{x}^{\mathrm{2}} } \\ $$ Answered by liberty last updated on 23/Jul/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sin}\:\left(\mathrm{2sin}\:{x}\right)}{{x}^{\mathrm{2}}…
Question Number 147684 by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{decompse}\:\mathrm{F}\left(\mathrm{x}\right)=\frac{\mathrm{x}^{\mathrm{3}} }{\left(\mathrm{x}^{\mathrm{2}} \:+\mathrm{1}\right)^{\mathrm{4}} }\:\:\:\mathrm{inside}\:\mathrm{C}\left(\mathrm{x}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 147687 by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{calculate}\:\mathrm{lim}_{\mathrm{n}\rightarrow\mathrm{0}} \:\frac{\mathrm{e}^{−\mathrm{nx}^{\mathrm{2}} } −\mathrm{nx}−\mathrm{1}}{\mathrm{x}^{\mathrm{3}} } \\ $$ Answered by ArielVyny last updated on 23/Jul/21…
Question Number 16613 by ajfour last updated on 24/Jun/17 Commented by ajfour last updated on 24/Jun/17 $$\mathrm{From}\:\mathrm{the}\:\mathrm{endpoint}\:\mathrm{of}\:\mathrm{a}\:\mathrm{diameter} \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{sphere}\:\mathrm{draw}\:\mathrm{a}\:\mathrm{chord}\:\mathrm{so}\:\mathrm{that} \\ $$$$\mathrm{the}\:\mathrm{surface}\:\mathrm{generated}\:\mathrm{by}\:\mathrm{a}\:\mathrm{rotation} \\ $$$$\mathrm{about}\:\mathrm{this}\:\mathrm{diameter}\:\mathrm{divides}\:\mathrm{the} \\ $$$$\mathrm{volume}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sphere}\:\mathrm{into}\:\mathrm{two}…
Question Number 147686 by 0731619 last updated on 22/Jul/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 82149 by TawaTawa last updated on 18/Feb/20 $$\mathrm{Evaluate}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{coefficient}\:\mathrm{of}\:\:\:\:\left(\mathrm{7}\:−\:\mathrm{5x}\right)^{−\:\mathrm{3}} \\ $$ Commented by TawaTawa last updated on 18/Feb/20 $$\mathrm{Please}\:\mathrm{working}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}. \\ $$ Answered by mr…
Question Number 147680 by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{find}\:\mathrm{by}\:\mathrm{residus}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{\mathrm{cos}\left(\mathrm{2x}\right)}{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{x}+\mathrm{1}\right)^{\mathrm{3}} }\mathrm{dx} \\ $$ Commented by mathmax by abdo last updated…
Question Number 147683 by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{let}\:\mathrm{F}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{5}} \left(\mathrm{2x}−\mathrm{3}\right)^{\mathrm{4}} } \\ $$$$\left.\mathrm{1}\right)\:\mathrm{find}\:\int\:\mathrm{F}\left(\mathrm{x}\right)\mathrm{dx} \\ $$$$\left.\mathrm{2}\right)\mathrm{en}\:\mathrm{deduire}\:\mathrm{la}\:\mathrm{decomposition}\:\mathrm{de}\:\mathrm{F}\:\mathrm{en}\:\mathrm{element}\:\mathrm{simples} \\ $$ Answered by mathmax by abdo…