Question Number 147635 by tabata last updated on 22/Jul/21 $${find}\:{the}\:{taylor}\:{series}\:{f}\left({z}\right)={cosz}\:\:,{z}=\frac{\pi}{\mathrm{4}} \\ $$$$ \\ $$$$ \\ $$ Commented by mathmax by abdo last updated on 22/Jul/21…
Question Number 147624 by jlewis last updated on 15/Aug/21 $$\mathrm{The}\:\mathrm{current}\:\mathrm{in}\:\mathrm{the}\:\mathrm{windings}\:\mathrm{on}\:\mathrm{a}\: \\ $$$$\mathrm{toroid}\:\mathrm{is}\:\mathrm{2}.\mathrm{0A}.\mathrm{There}\:\mathrm{are}\:\mathrm{400}\:\mathrm{turns} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{circumferential}\:\mathrm{length} \\ $$$$\mathrm{is}\:\mathrm{40cm}.\mathrm{With}\:\mathrm{the}\:\mathrm{aid}\:\mathrm{of}\:\mathrm{a}\:\mathrm{search} \\ $$$$\:\mathrm{coil}\:\mathrm{and}\:\mathrm{charge}\:\mathrm{measuring}\:\mathrm{instrument} \\ $$$$\mathrm{the}\:\mathrm{magnetic}\:\mathrm{field}\:\mathrm{is}\:\mathrm{found}\:\mathrm{to}\:\mathrm{be} \\ $$$$\mathrm{1}.\mathrm{0T}.\mathrm{calculate}: \\ $$$$\left.\mathrm{i}\left.\right)\mathrm{magnetic}\:\mathrm{density}\:\mathrm{ii}\right)\mathrm{magnetization} \\…
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Question Number 147626 by mathdanisur last updated on 22/Jul/21 $$\underset{\:\mathrm{0}} {\overset{\:\mathrm{3}} {\int}}\:\frac{{dx}}{\mathrm{2}\:+\:{cosx}}\:=\:? \\ $$ Answered by mathmax by abdo last updated on 22/Jul/21 $$\mathrm{I}=\int_{\mathrm{0}} ^{\mathrm{3}}…
Question Number 147621 by mathdanisur last updated on 22/Jul/21 $${Find}\:{the}\:{general}\:{solution}\:{for}: \\ $$$$\frac{{dy}}{{dx}}\:=\:\left(\mathrm{3}{x}\:+\:\mathrm{2}{y}\:+\:\mathrm{1}\right)^{\mathrm{2}} \\ $$ Answered by gsk2684 last updated on 22/Jul/21 $${put}\:{u}=\mathrm{3}{x}+\mathrm{2}{y}+\mathrm{1}\Rightarrow\frac{{du}}{{dx}}=\mathrm{3}+\mathrm{2}\frac{{dy}}{{dx}} \\ $$$$\frac{{du}}{{dx}}=\mathrm{3}+\mathrm{2}{u}^{\mathrm{2}} \\…
Question Number 147623 by mari last updated on 22/Jul/21 Commented by tabata last updated on 22/Jul/21 $$\left(\mathrm{2}\right)\:{it}\:{is}\:{clearley}\:\:{that}\:\:{f}\left({z}\right)=\frac{\mathrm{1}}{{z}−\mathrm{1}}−\frac{\mathrm{1}}{{z}−\mathrm{2}} \\ $$$$ \\ $$$$\left({a}\right)\:\mid{z}\mid<\mathrm{1} \\ $$$$ \\ $$$${f}\left({z}\right)=−\frac{\mathrm{1}}{\mathrm{1}−{z}}+\frac{\mathrm{1}}{\mathrm{2}}.\frac{\mathrm{1}}{\left(\mathrm{1}−\frac{{z}}{\mathrm{2}}\right)}=−\underset{{n}=\mathrm{0}}…
Question Number 82084 by oyemi kemewari last updated on 18/Feb/20 Commented by john santu last updated on 18/Feb/20 $$\frac{\mathrm{1}}{\mathrm{2}\left(\mathrm{2}^{\mathrm{2}} −\mathrm{1}\right)}+\frac{\mathrm{1}}{\mathrm{3}\left(\mathrm{3}^{\mathrm{2}} −\mathrm{1}\right)}+\frac{\mathrm{1}}{\mathrm{4}\left(\mathrm{4}^{\mathrm{2}} −\mathrm{1}\right)}+… \\ $$$$\underset{{k}=\mathrm{2}} {\overset{\infty}…
Question Number 147622 by mari last updated on 22/Jul/21 Commented by Sozan last updated on 22/Jul/21 $$??????? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 82082 by TawaTawa last updated on 18/Feb/20 $$\mathrm{Evaluate}:\:\:\:\:\:\:\left(\frac{\sqrt{\mathrm{30}\:+\:\sqrt{\mathrm{8}}\:+\:\sqrt{\mathrm{5}}}}{\:\sqrt{\mathrm{8}}\:+\:\sqrt{\mathrm{5}}}\right)^{\mathrm{1}/\mathrm{4}} \\ $$ Commented by MJS last updated on 18/Feb/20 $$\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{expand}\:\mathrm{or}\:\mathrm{factorise}\:\sqrt{\mathrm{30}+\sqrt{\mathrm{8}}+\sqrt{\mathrm{5}}}\: \\ $$$$\Rightarrow\:\mathrm{we}\:\mathrm{can}\:\mathrm{only}\:\mathrm{use}\:\mathrm{a}\:\mathrm{calculator} \\ $$ Commented…
Question Number 16547 by Sai dadon. last updated on 23/Jun/17 $${solve} \\ $$$${dy}/{dx}\:+\:{xy}={y}^{\mathrm{2}} {e}^{\mathrm{1}/\mathrm{2}{x}^{\mathrm{2}} } {logx} \\ $$ Commented by Sai dadon. last updated on…