Question Number 16546 by Sai dadon. last updated on 23/Jun/17 $${dv}/{dt}=−\left({kv}+{bt}\right)\:{where}\:{k}\:{and}\:{b}\:{are}\:{constants} \\ $$$${solve}\:{the}\:{equation}\:{of}\:{v}\:{given} \\ $$$${v}={u}\:{when}\:{t}=\mathrm{0} \\ $$ Answered by mrW1 last updated on 23/Jun/17 $$\frac{\mathrm{dv}}{\mathrm{dt}}+\mathrm{kv}=−\mathrm{bt}…
Question Number 82078 by jagoll last updated on 18/Feb/20 $${f}\left(\mathrm{10}^{{x}} \right)\:=\:\sqrt{{x}}\: \\ $$$${what}\:{is}\:{f}^{−\mathrm{1}} \left({x}\right)=? \\ $$ Commented by john santu last updated on 18/Feb/20 $${hahaha}..{i}\:{think}\:{you}\:{can}\:{solve}\:{this}…
Question Number 147612 by ZiYangLee last updated on 22/Jul/21 $$\mathrm{Given}\:\mathrm{that}\:{f}\left({x}\right)=\frac{\left({x}^{\mathrm{3}} +\mathrm{1}\right)^{\mathrm{2}} \sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{\mathrm{1}+\sqrt{{x}}}. \\ $$$$\mathrm{By}\:\mathrm{using}\:\mathrm{logarithmatic}\:\mathrm{differentiation}, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{f}\:'\left(\mathrm{1}\right). \\ $$ Answered by mathmax by abdo last…
Question Number 16542 by gourav~ last updated on 23/Jun/17 $${if}\:\frac{{a}}{\mid{Z}_{\mathrm{2}} −{Z}_{\mathrm{3}} \mid}=\frac{{b}}{\mid{Z}_{\mathrm{3}} −{Z}_{\mathrm{1}} \mid}=\frac{{c}}{\mid{Z}_{\mathrm{1}} −{Z}_{\mathrm{2}} \mid}\:\:{Then}.. \\ $$$${find}..\:\frac{{a}^{\mathrm{2}} }{{Z}_{\mathrm{2}} −{Z}_{\mathrm{3}} }\:+\:\frac{{b}^{\mathrm{2}} }{{Z}_{\mathrm{3}} −{Z}_{\mathrm{1}} }\:+\:\frac{{c}^{\mathrm{2}} }{{Z}_{\mathrm{1}}…
Question Number 16540 by gourav~ last updated on 23/Jun/17 $${if}\:\mid{Z}\mid=\mathrm{1}\:{Then}\:\frac{\mathrm{1}+{Z}}{\mathrm{1}+\bar {{Z}}}\:\:{is}\:{equal}\:{to}… \\ $$$$\left.{a}\right)\:{Z}\:\: \\ $$$$\left.{b}\right)\:\:\bar {{Z}} \\ $$$$\left.{c}\right)\:{Z}+\bar {{Z}} \\ $$$$\left.{d}\right)\:{N}.{O}.{T} \\ $$ Answered by…
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Question Number 147611 by mathdanisur last updated on 22/Jul/21 $$\left(\mathrm{111}\right)_{\mathrm{10}} \:=\:\left({x}\right)_{\mathrm{5}} \\ $$$$\Rightarrow\:{x}\:=\:? \\ $$ Answered by bobhans last updated on 22/Jul/21 $$\left(\mathrm{111}\right)_{\mathrm{10}} =\:\mathrm{1}×\mathrm{10}^{\mathrm{2}} +\mathrm{1}×\mathrm{10}^{\mathrm{1}}…
Question Number 82073 by TawaTawa last updated on 18/Feb/20 $$\mathrm{Show}\:\mathrm{that}:\:\:\:\:\mathrm{j}_{\mathrm{3}/\mathrm{2}} \left(\mathrm{x}\right)\:\:=\:\:\frac{\sqrt{\mathrm{2}}}{\pi\mathrm{x}}\:\left(\frac{\mathrm{sin}\:\mathrm{x}}{\mathrm{x}}\:−\:\mathrm{cos}\:\mathrm{x}\right) \\ $$ Commented by jagoll last updated on 18/Feb/20 $${what}\:{is}\:{j}_{\frac{\mathrm{3}}{\mathrm{2}}} ? \\ $$ Commented…
Question Number 82071 by jagoll last updated on 18/Feb/20 $${x}\neq\:{y}\:\neq{z}\:\neq\:\mathrm{0} \\ $$$${xy}\:+\:{xz}\:+\:{yz}\:=\:\mathrm{0} \\ $$$${prove}\:{that}\:\frac{{x}+{y}}{{z}}+\frac{{x}+{z}}{{y}}+\frac{{y}+{z}}{{x}}\:=\:−\mathrm{3} \\ $$$$ \\ $$ Answered by TANMAY PANACEA last updated on…
Question Number 147606 by vvvv last updated on 22/Jul/21 $$\frac{\boldsymbol{\mathrm{R}}}{\boldsymbol{{r}}}=\frac{\mathrm{5}}{\mathrm{2}}\:\:\Rightarrow\:\boldsymbol{{a}}:\boldsymbol{{b}}:\boldsymbol{{c}}=\mathrm{3}:\mathrm{4}:\mathrm{5} \\ $$$$\boldsymbol{\mathrm{prove}}\:\: \\ $$$$\boldsymbol{\mathrm{R}},\boldsymbol{{r}}−\:\boldsymbol{\mathrm{radius}} \\ $$$$\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{a}}} :\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{b}}} :\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{c}}} =\frac{\mathrm{1}}{\boldsymbol{{a}}}:\frac{\mathrm{1}}{\boldsymbol{{b}}}:\frac{\mathrm{1}}{\boldsymbol{{c}}}=\boldsymbol{{bc}}:\boldsymbol{{ac}}:\boldsymbol{{ab}} \\ $$$$\boldsymbol{{prove}} \\ $$ Terms of…