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Author: Tinku Tara

1-find-dx-x-1-3-x-2-1-2-2-calculate-0-dx-x-1-3-x-2-1-2-

Question Number 81851 by abdomathmax last updated on 16/Feb/20 $$\left.\mathrm{1}\right){find}\:\int\:\:\:\:\frac{{dx}}{\left({x}+\mathrm{1}\right)^{\mathrm{3}} \left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} } \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{dx}}{\left({x}+\mathrm{1}\right)^{\mathrm{3}} \left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Terms of Service…

On-pose-H-n-k-1-n-1-sin-2n-kpi-n-a-montrer-que-0-2-n-1-H-n-sin-2-sin-2n-b-Calculer-lim-0-H-n-c-De-duire-que-2-sin-pi-n-sin-2pi-

Question Number 147381 by puissant last updated on 20/Jul/21 $${On}\:{pose}\:{H}_{{n}} \left(\alpha\right)=\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\prod}}{sin}\left(\frac{\alpha}{\mathrm{2}{n}}+\frac{{k}\pi}{{n}}\right) \\ $$$$\left.{a}\right)\:{montrer}\:{que}\:\forall\alpha\neq\mathrm{0},\: \\ $$$$\mathrm{2}^{{n}−\mathrm{1}} {H}_{{n}} \left(\alpha\right)=\frac{{sin}\left(\frac{\alpha}{\mathrm{2}}\right)}{{sin}\left(\frac{\alpha}{\mathrm{2}{n}}\right)} \\ $$$$\left.{b}\right)\:{Calculer}\:{lim}_{\alpha\rightarrow\mathrm{0}} \:{H}_{{n}} \left(\alpha\right) \\ $$$$\left.{c}\right)\:{D}\acute…

Question-16310

Question Number 16310 by tawa tawa last updated on 20/Jun/17 Commented by tawa tawa last updated on 20/Jun/17 $$\mathrm{please}\:\mathrm{i}\:\mathrm{need}\:\mathrm{the}\:\mathrm{solutions}\:\mathrm{urgent}\:\mathrm{sirs}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{youreffort}. \\ $$$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sirs}. \\ $$ Commented by…

Related-to-Q16140-What-if-the-three-lines-d-1-d-2-d-3-are-not-parallel-but-concurrent-

Question Number 16302 by mrW1 last updated on 20/Jun/17 $$\mathrm{Related}\:\mathrm{to}\:\mathrm{Q16140} \\ $$$$\mathrm{What}\:\mathrm{if}\:\mathrm{the}\:\mathrm{three}\:\mathrm{lines}\:\mathrm{d}_{\mathrm{1}} ,\mathrm{d}_{\mathrm{2}} ,\mathrm{d}_{\mathrm{3}} \:\mathrm{are} \\ $$$$\mathrm{not}\:\mathrm{parallel},\:\mathrm{but}\:\mathrm{concurrent}? \\ $$ Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on…