Question Number 81750 by mr W last updated on 15/Feb/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 16214 by Tinkutara last updated on 19/Jun/17 $$\mathrm{In}\:\Delta{ABC},\:{r}_{\mathrm{1}} ,\:{r}_{\mathrm{2}} \:\mathrm{and}\:{r}_{\mathrm{3}} \:\mathrm{are}\:\mathrm{the}\:\mathrm{exradii} \\ $$$$\mathrm{as}\:\mathrm{shown}.\:\mathrm{Prove}\:\mathrm{that}\:{r}_{\mathrm{1}} \:=\:\frac{\Delta}{{s}\:−\:{a}}\:, \\ $$$${r}_{\mathrm{2}} \:=\:\frac{\Delta}{{s}\:−\:{b}}\:\mathrm{and}\:{r}_{\mathrm{3}} \:=\:\frac{\Delta}{{s}\:−\:{c}}\:.\:\mathrm{Here} \\ $$$${s}\:=\:\frac{{a}\:+\:{b}\:+\:{c}}{\mathrm{2}}\:. \\ $$ Commented…
Question Number 147287 by mnjuly1970 last updated on 19/Jul/21 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:…\mathrm{Advanced}\:\:\mathrm{Calculus}… \\ $$$$ \\ $$$$\:\:\:\:\:\:\mathrm{C}{alculate}\:::\:\:\:\:\begin{cases}{\:\:\mathrm{i}\:::\:\:\:\:\:\:\mathrm{I}\::=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \mathrm{ln}\left(\mathrm{x}\right).\mathrm{ln}\left(\mathrm{1}+\mathrm{x}\right)\:\mathrm{dx}}\\{\:\:\mathrm{ii}\:::\:\:\:\:\:\mathrm{J}\::=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \mathrm{Li}_{\:\mathrm{2}} \left(\:\mathrm{1}−\:\mathrm{x}^{\:\mathrm{2}} \right)\:=?}\end{cases} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{Note}::\:\:\:\mathrm{Li}_{\mathrm{2}} \:\left(\mathrm{x}\right)\:=\:\underset{{n}=\mathrm{1}}…
Question Number 147277 by Ar Brandon last updated on 19/Jul/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 147276 by Ar Brandon last updated on 19/Jul/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 81740 by peter frank last updated on 15/Feb/20 Commented by mr W last updated on 15/Feb/20 $${information}\:{missing}! \\ $$$${see}\:{my}\:{comment}\:{to}\:{Q}\mathrm{81741}. \\ $$ Terms of…
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Question Number 81741 by peter frank last updated on 15/Feb/20 Commented by mr W last updated on 15/Feb/20 $${dear}\:{sir}:\:{i}'{d}\:{like}\:{to}\:{ask}\:{you}\:{not}\:{to}\:{post} \\ $$$${those}\:{questions}\:{which}\:{need}\:{their} \\ $$$${corresponding}\:{diagrams}.\:{but}\:{you}\:{can} \\ $$$${not}\:{supply}\:{these}\:{diagrams}.\:{you}\:{won}'{t}…
Question Number 147272 by mathdanisur last updated on 19/Jul/21 Answered by puissant last updated on 19/Jul/21 $${y}={arctan}\left({a}\right)\:\Rightarrow\:{cos}\left({arctan}\left({a}\right)\right)={cos}\left({y}\right) \\ $$$$\mathrm{1}+{tan}^{\mathrm{2}} {y}=\frac{\mathrm{1}}{{cos}^{\mathrm{2}} {y}}\:\Rightarrow\:{cos}^{\mathrm{2}} {y}=\frac{\mathrm{1}}{\mathrm{1}+{tan}^{\mathrm{2}} {y}} \\ $$$$\Rightarrow{cos}^{\mathrm{2}}…
Question Number 81739 by TANMAY PANACEA last updated on 15/Feb/20 $$\int\frac{{dx}}{{cos}^{\mathrm{3}} {x}−{sin}^{\mathrm{3}} {x}} \\ $$ Commented by abdomathmax last updated on 16/Feb/20 $${I}\:=\int\:\:\frac{{dx}}{{cos}^{\mathrm{3}} {x}−{sin}^{\mathrm{3}} {x}}\:=\int\:\frac{{dx}}{\left({cosx}−{sinx}\right)\left({cos}^{\mathrm{2}}…