Question Number 223786 by Nicholas666 last updated on 04/Aug/25 $$ \\ $$$$\:\:\:\:\boldsymbol{\mathrm{Evaluate}}\:;\:\int\:\sqrt{\:\boldsymbol{\mathrm{tan}}\:\boldsymbol{{x}}}\:\boldsymbol{\mathrm{d}{x}}\:,\:\boldsymbol{\mathrm{Using}}\:\boldsymbol{\mathrm{feynman}}'\boldsymbol{\mathrm{s}}\:\boldsymbol{\mathrm{trick}} \\ $$$$ \\ $$ Commented by Frix last updated on 05/Aug/25 $$\mathrm{I}'\mathrm{ll}\:\mathrm{do}\:\mathrm{it}\:\mathrm{but}\:\mathrm{only}\:\mathrm{if}\:\mathrm{you}\:\mathrm{solve} \\…
Question Number 223783 by mr W last updated on 04/Aug/25 Commented by mr W last updated on 04/Aug/25 $${find}\:{shaded}\:{area}\:{in}\:{rectangle}. \\ $$ Answered by fantastic last…
Question Number 223778 by wewji12 last updated on 04/Aug/25 $$\underset{{N}\rightarrow\infty} {\mathrm{lim}}\:\frac{{p}_{{N}+\mathrm{1}} }{{p}_{{N}} }=???\:\:,\:{p}_{\mathrm{1}} =\mathrm{2}\:,\:{p}_{\mathrm{2}} =\mathrm{3}\:,{p}_{\mathrm{3}} =\mathrm{5}\:…. \\ $$ Answered by mr W last updated on…
Question Number 223779 by MASANJAJJ last updated on 04/Aug/25 Answered by parthasc last updated on 04/Aug/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 223724 by fantastic last updated on 03/Aug/25 $$\: \\ $$$$\mathrm{A}\:\mathrm{rubber}\:\mathrm{ball}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{m}\: \\ $$$$\mathrm{radius}\:\mathrm{R}\:\mathrm{and}\:\mathrm{density}\rho\:\mathrm{is}\:\mathrm{released}\:\mathrm{from}\:\mathrm{a} \\ $$$$\mathrm{depth}\:\mathrm{h}\:\mathrm{under}\:\mathrm{a}\:\mathrm{fluid}\:\mathrm{of}\:\mathrm{density}\:\sigma\left(\sigma>\rho\right) \\ $$$$\left.\mathrm{i}\right) \\ $$$$\:\mathrm{How}\:\mathrm{high}\:\mathrm{will}\:\mathrm{the}\:\mathrm{ball}\:\mathrm{bounce}\:\mathrm{on} \\ $$$$\mathrm{the}\:\mathrm{the}\:\mathrm{fluid}\:?\mathrm{Ignore}\:\mathrm{any} \\ $$$$\mathrm{obstacles} \\…
Question Number 223741 by mr W last updated on 04/Aug/25 Commented by mr W last updated on 03/Aug/25 $${as}\:{Q}\mathrm{223720},\:{but}\:{the}\:{question}\:{is}: \\ $$$$\underline{{after}\:{what}\:{time}}\:{will}\:{the}\:{mass}\:{M}\: \\ $$$${hit}\:{the}\:{wall}? \\ $$…
Question Number 223720 by fantastic last updated on 03/Aug/25 $$ \\ $$$$\mathrm{One}\:\mathrm{end}\:\mathrm{of}\:\mathrm{a}\:\mathrm{string}\:\mathrm{is} \\ $$$$\mathrm{attached}\:\mathrm{to}\:\mathrm{a}\:\mathrm{solid}\:\mathrm{wall}\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{other}\:\mathrm{end}\:\mathrm{is}\:\mathrm{hanging}\:\mathrm{from}\:\mathrm{a} \\ $$$$\mathrm{smooth}\:\mathrm{pulley}\:\mathrm{2}\:\mathrm{m}\:\mathrm{away}\: \\ $$$$\mathrm{fromthe}\:\mathrm{wall}.\:\mathrm{A}\:\mathrm{point}\:\mathrm{mass}\: \\ $$$$\mathrm{M}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{2}\:\mathrm{kg}\:\mathrm{is}\:\mathrm{attached}\:\mathrm{to} \\ $$$$\mathrm{the}\:\mathrm{string}\:\mathrm{1}\:\mathrm{m}\:\mathrm{away}\:\mathrm{from}\:\mathrm{the} \\…
Question Number 223734 by behi834171 last updated on 03/Aug/25 Answered by Ghisom last updated on 03/Aug/25 $$\mathrm{we}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$$\mathrm{all}\:\mathrm{paths}\:\mathrm{lead}\:\mathrm{to}\:\mathrm{polynomials}\:\mathrm{of}\:\mathrm{degree}\:\mathrm{8} \\ $$$$\mathrm{I}\:\mathrm{also}\:\mathrm{tried}\:\mathrm{to}\:\mathrm{substitute} \\ $$$${x}=\sqrt{\mathrm{3}}\mathrm{cos}\:\mathrm{2}\theta \\ $$$$\mathrm{which}\:\mathrm{leads}\:\mathrm{to}\:\mathrm{the}\:\mathrm{nice}\:\mathrm{looking}…
Question Number 223735 by Nicholas666 last updated on 03/Aug/25 $$\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{all}}\:\:{n}\:\in\:\mathbb{Z}\:, \\ $$$$\:\:\:\:\:\boldsymbol{\mathrm{Show}}\:\boldsymbol{\mathrm{that}}\:\tau\:\left(\:\varphi\:\left(\:{n}\:\right)\right)\:\geqslant\:\varphi\:\left(\tau\:\left({n}\:\right)\right) \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 223728 by Nicholas666 last updated on 03/Aug/25 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}_{\:} } ^{\mathrm{1}} \:\frac{\mathrm{ln}\left(\mathrm{1}+\sqrt{{x}}\right)\centerdot\mathrm{ln}\left(\mathrm{1}+{x}\right)}{\mathrm{1}+\sqrt{{x}}}\:\mathrm{d}{x} \\ $$ Answered by Tawa11 last updated on 14/Aug/25 $$\mathrm{Finally}:…