Question Number 11475 by tawa last updated on 26/Mar/17 Answered by sm3l2996 last updated on 26/Mar/17 $$\mathrm{Question}\:\mathrm{105}:\left(\mathrm{B}\right) \\ $$$$\mathrm{Question}\:\mathrm{106}: \\ $$$$\Delta\mathrm{AFD}=\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}=\frac{\mathrm{25}}{\mathrm{2}}=\mathrm{12}.\mathrm{5}\:\left(\mathrm{C}\right) \\ $$ Commented…
Question Number 11474 by tawa last updated on 26/Mar/17 Answered by sm3l2996 last updated on 26/Mar/17 $$\left(\mathrm{E}\right) \\ $$ Commented by tawa last updated on…
Question Number 11473 by tawa last updated on 26/Mar/17 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{graph}\:\mathrm{of}\:\:\mathrm{y}\:=\:\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{2x}^{\mathrm{2}} \:+\:\mathrm{x}\:+\:\mathrm{1}\:,\:\mathrm{between}\:\mathrm{x}\:=\:−\:\mathrm{1}\:\mathrm{and}\:\mathrm{x}\:=\:\mathrm{2} \\ $$$$\mathrm{lies}\:\mathrm{entirely}\:\mathrm{above}\:\mathrm{the}\:\mathrm{x}\:−\:\mathrm{axis} \\ $$ Commented by prakash jain last updated on 28/Mar/17 $${y}={x}^{\mathrm{3}}…
Question Number 142546 by cesarL last updated on 02/Jun/21 $${i}\:{need}\:{help} \\ $$ Commented by cesarL last updated on 02/Jun/21 Terms of Service Privacy Policy Contact:…
Question Number 77009 by Master last updated on 02/Jan/20 Commented by Master last updated on 02/Jan/20 $$\mathrm{lose}\:\mathrm{x}\:\mathrm{from}\:\mathrm{the}\:\mathrm{system}\left(\mathrm{find}\:\mathrm{the}\:\mathrm{connection}\:\mathrm{between}\:\mathrm{a}\:\mathrm{and}\:\mathrm{c}\right) \\ $$ Commented by MJS last updated on…
Question Number 142537 by mathocean1 last updated on 01/Jun/21 $$\mathrm{Given}: \\ $$$$\mathrm{z}_{\mathrm{1}} =\mathrm{e}^{\mathrm{i}\frac{\pi}{\mathrm{3}}} \left(\mathrm{z}+\mathrm{3}\right)−\mathrm{3}\:\mathrm{and}\:\mathrm{z}_{\mathrm{2}} =\mathrm{e}^{−\mathrm{i}\frac{\mathrm{2}\pi}{\mathrm{3}}} \left(\mathrm{z}−\mathrm{3}\right)+\mathrm{3}. \\ $$$$\mathrm{Show}\:\mathrm{that}\: \\ $$$$\frac{\mathrm{z}_{\mathrm{2}} −\mathrm{z}}{\mathrm{z}_{\mathrm{1}} −\mathrm{z}}=\mathrm{i}\sqrt{\mathrm{3}}\frac{\mathrm{z}−\mathrm{3}}{\mathrm{z}+\mathrm{3}} \\ $$ Terms…
Question Number 77002 by jagoll last updated on 02/Jan/20 $$ \\ $$$${calculate}\:\int\:\frac{{dt}}{\mathrm{cos}\:\left(\mathrm{2}{t}+{a}\right)\mathrm{cos}\:\left(\mathrm{2}{t}−{a}\right)} \\ $$ Commented by turbo msup by abdo last updated on 03/Jan/20 $${we}\:{have}\:…
Question Number 77000 by vishalbhardwaj last updated on 02/Jan/20 $$\mathrm{One}\:\mathrm{vertex}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equalateral}\:\mathrm{triangle} \\ $$$$\mathrm{with}\:\mathrm{centroid}\:\mathrm{at}\:\mathrm{the}\:\mathrm{origin}\:\mathrm{and}\:\mathrm{one} \\ $$$$\mathrm{side}\:\mathrm{as}\:\mathrm{x}+\mathrm{y}−\mathrm{2}\:=\:\mathrm{0}\:\mathrm{is} \\ $$$$\left(\mathrm{a}\right)\:\:\left(−\mathrm{1},−\mathrm{1}\right)\:\:\left(\mathrm{b}\right)\:\left(\mathrm{2},\mathrm{2}\right)\:\:\left(\mathrm{c}\right)\:\left(−\mathrm{2},−\mathrm{2}\right) \\ $$$$\left(\mathrm{d}\right)\:\left(\mathrm{2},−\mathrm{2}\right) \\ $$ Commented by vishalbhardwaj last updated…
Question Number 142538 by Rankut last updated on 02/Jun/21 $$\mathrm{2}\boldsymbol{{x}}^{\mathrm{7}} +\boldsymbol{{x}}^{\mathrm{28}} =\mathrm{3}\boldsymbol{{x}}^{\mathrm{21}} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by Ar Brandon last updated on 02/Jun/21 $$\mathrm{2x}^{\mathrm{7}}…
Question Number 77001 by vishalbhardwaj last updated on 02/Jan/20 $$\mathrm{The}\:\mathrm{point}\:\left(\mathrm{4},\mathrm{1}\right)\:\mathrm{undergoes}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{two}\:\mathrm{successive}\:\mathrm{transformations} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{reflection}\:\mathrm{about}\:\mathrm{the}\:\mathrm{line}\:\mathrm{y}=\mathrm{x} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{translation}\:\mathrm{through}\:\mathrm{a}\:\mathrm{distance} \\ $$$$\mathrm{2}\:\mathrm{units}\:\mathrm{along}\:\mathrm{the}\:\mathrm{positive}\:\mathrm{x}\:\mathrm{axis} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{final}\:\mathrm{coordinates} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{point}\:???? \\ $$ Answered…