Question Number 142528 by mohammad17 last updated on 01/Jun/21 $$\int_{\mathrm{1}} ^{\:\infty} \:\frac{{dx}}{{e}^{{x}} −\mathrm{2}^{{x}} } \\ $$ Answered by mathmax by abdo last updated on 02/Jun/21…
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Question Number 142531 by mnjuly1970 last updated on 01/Jun/21 $$\: \\ $$$$\:\:{if}\:\:\:\:\boldsymbol{\phi}\:\left({q}\right):=\:\int_{\mathrm{1}} ^{\:\infty} \frac{\mathrm{1}}{\:\sqrt{{x}}\:\left({q}+{x}\right)^{{x}} }{dx} \\ $$$$\:\:\:\:{then}\:::\:\:{lim}\:_{{q}\rightarrow\mathrm{1}} \boldsymbol{\phi}\left({q}\right):=? \\ $$$$\:\:\:\:\:\: \\ $$ Terms of Service…
Question Number 11456 by Joel576 last updated on 26/Mar/17 $$\mathrm{sin}\:{x}\:−\:\mathrm{cos}\:{x}\:=\:{a},\:\:\frac{\pi}{\mathrm{4}}\:\leqslant\:{x}\:\leqslant\:\frac{\pi}{\mathrm{2}} \\ $$$$\mathrm{Which}\:\mathrm{statement}\:\mathrm{is}\:\mathrm{correct}? \\ $$$$\left(\mathrm{1}\right)\:\mathrm{sin}^{\mathrm{2}} \:{x}\:−\:\mathrm{cos}^{\mathrm{2}} \:{x}\:=\:−\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}\:+\:\mathrm{2}{a}^{\mathrm{2}} \:−\:{a}^{\mathrm{4}} } \\ $$$$\left(\mathrm{2}\right)\:\mathrm{sin}^{\mathrm{4}} \:{x}\:+\:\mathrm{cos}^{\mathrm{4}} \:{x}\:=\:\frac{\mathrm{1}}{\mathrm{8}}\left(−\mathrm{3}{a}^{\mathrm{4}} \:+\:\mathrm{6}{a}^{\mathrm{2}} \:+\:\mathrm{5}\right) \\…
Question Number 76991 by liki last updated on 02/Jan/20 Commented by liki last updated on 02/Jan/20 $$….\boldsymbol{{i}}\:\boldsymbol{{need}}\:\boldsymbol{{help}}\:\boldsymbol{{plz}}. \\ $$ Answered by MJS last updated on…
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Question Number 142516 by ArielVyny last updated on 01/Jun/21 $$\int\frac{{dx}}{\left(−{lnx}\right)^{\frac{\mathrm{1}}{{x}}} }\:\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 11444 by Joel576 last updated on 26/Mar/17 $$\mathrm{If}\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{{px}\:+\:{q}}\:−\:\mathrm{2}}{{x}}\:=\:\mathrm{1} \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:{p}\:+\:{q}\:? \\ $$ Answered by ajfour last updated on 26/Mar/17 $$\mathrm{then}\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{q}}\left(\mathrm{1}+\mathrm{px}/\mathrm{q}\right)^{\mathrm{1}/\mathrm{2}} \:−\mathrm{2}}{\mathrm{x}}\:=\mathrm{1}…
Question Number 142514 by mnjuly1970 last updated on 01/Jun/21 $$\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:…..\:{number}\:\:{theory}….. \\ $$$$\:\:\:\:\:\:\:{Solve}\:{in}\:\mathbb{Z}\:: \\ $$$$\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{y}}+\frac{\mathrm{1}}{{xy}}\:=\frac{\mathrm{1}}{\mathrm{4}}\:….? \\ $$$$\:\:\:\:\:……… \\ $$ Answered by ArielVyny last updated…