Menu Close

Author: Tinku Tara

lim-x-0-1-tan-x-1-sin-x-x-3-

Question Number 11364 by Joel576 last updated on 22/Mar/17 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\frac{\sqrt{\mathrm{1}\:+\:\mathrm{tan}\:{x}}\:−\:\sqrt{\mathrm{1}\:+\:\mathrm{sin}\:{x}}}{{x}^{\mathrm{3}} } \\ $$ Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 22/Mar/17 $$\frac{\sqrt{\mathrm{1}+{tgx}}−\sqrt{\mathrm{1}+{sinx}}}{{x}^{\mathrm{3}} }=\frac{\left(\mathrm{1}+{tgx}\right)−\left(\mathrm{1}+{sinx}\right)}{\left(\sqrt{\mathrm{1}+{tgx}}+\sqrt{\mathrm{1}+{sinx}}\right).{x}^{\mathrm{3}} }= \\…