Question Number 76353 by mathmax by abdo last updated on 26/Dec/19 $${find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left({sin}\left(\pi{x}^{\mathrm{2}} \right)\right)}{{x}^{\mathrm{2}} \:+\pi^{\mathrm{2}} }{dx} \\ $$ Commented by mathmax by abdo last…
Question Number 141885 by mnjuly1970 last updated on 24/May/21 $$\:\:\: \\ $$$$\:\:\:\:\:\:{easy}\:\:{question}: \\ $$$$\:\:\:\:{if}\:\:\:{lim}_{{x}\rightarrow\mathrm{0}} \frac{\mathrm{1}−{cos}\left(\mathrm{1}−{cos}\left(\mathrm{1}−{cos}\left({x}\right)\right)\right)}{{x}^{\mathrm{8}} }\:=\mathrm{2}^{\:{a}} \\ $$$$\:\:\:\:\:\:\:\:{then}\:\:\:{a}=??\:\: \\ $$ Answered by Dwaipayan Shikari last…
Question Number 76350 by mathmax by abdo last updated on 26/Dec/19 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left({e}^{{x}^{\mathrm{2}} } \right)}{{x}^{\mathrm{2}} \:+\mathrm{4}}{dx} \\ $$ Commented by mathmax by abdo last…
Question Number 10815 by fariraihmudzengerere75@gmail.c last updated on 26/Feb/17 $${Evalute}\:\:\int\left({x}^{\mathrm{2}\:} \:\:+\:\mathrm{9}\right)^{\mathrm{9}} \:{dx}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141884 by MeghRajBasnet last updated on 24/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 76351 by mathmax by abdo last updated on 26/Dec/19 $${calculate}\:{U}_{{n}} =\int_{\frac{\mathrm{1}}{{n}}} ^{\mathrm{1}} \:\Gamma\left({x}\right){dx}\:\:{and}\:{find}\:{lim}_{{n}\rightarrow+\infty} \:{U}_{{n}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 76346 by Maclaurin Stickker last updated on 26/Dec/19 Commented by Maclaurin Stickker last updated on 26/Dec/19 $$\mathrm{1}.\:{Find}\:{x}\:{as}\:{a}\:{function}\:{of}\:{b}\:{and}\:{c}. \\ $$$$\mathrm{2}.\:{Under}\:{what}\:{conditions}\:{does}\:{the} \\ $$$${problem}\:{admit}\:{a}\:{solution}? \\ $$…
Question Number 10807 by Saham last updated on 25/Feb/17 Commented by ridwan balatif last updated on 26/Feb/17 $$\mathrm{19}.\mathrm{13}\:\:\epsilon=\mathrm{1}\left(\mathrm{because}\:\mathrm{like}\:\mathrm{act}\:\mathrm{blackbody}\right),\:\mathrm{A}=\mathrm{1cm}^{\mathrm{2}} =\mathrm{10}^{−\mathrm{4}} \mathrm{m}^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\sigma\left(\mathrm{Boltzman}\:\mathrm{constant}\right)=\mathrm{5}.\mathrm{67}×\mathrm{10}^{−\mathrm{8}} \mathrm{Wm}^{−\mathrm{2}} \mathrm{K}^{−\mathrm{4}} ,\:\mathrm{T}=\mathrm{1727}^{\mathrm{o}}…
Question Number 76340 by Master last updated on 26/Dec/19 Commented by behi83417@gmail.com last updated on 26/Dec/19 $$\mathrm{x}=−\mathrm{1},\mathrm{0} \\ $$ Answered by behi83417@gmail.com last updated on…
Question Number 76341 by liki last updated on 26/Dec/19 Commented by liki last updated on 26/Dec/19 $$..\boldsymbol{{Help}}\:\boldsymbol{{me}}\:\boldsymbol{{qn}}\:\mathrm{1}\left(\boldsymbol{{b}}\right)\:\boldsymbol{{plz}}.. \\ $$ Terms of Service Privacy Policy Contact:…