Question Number 205092 by BaliramKumar last updated on 08/Mar/24 Answered by A5T last updated on 08/Mar/24 $${n}^{\mathrm{2}} +\mathrm{19}{n}+\mathrm{92}−{x}^{\mathrm{2}} =\mathrm{0} \\ $$$${n}=\frac{−\mathrm{19}\underset{−} {+}\sqrt{\mathrm{361}−\mathrm{4}\left(\mathrm{92}−{x}^{\mathrm{2}} \right)}}{\mathrm{2}}=\frac{−\mathrm{19}\underset{−} {+}\sqrt{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{7}}}{\mathrm{2}}…
Question Number 205106 by mr W last updated on 08/Mar/24 Commented by mr W last updated on 10/Mar/24 https://youtu.be/FUHkTs-Ipfg?si=59bDLBxJIY5Zk5cY Answered by mr W last updated…
Question Number 205107 by mnjuly1970 last updated on 08/Mar/24 $$ \\ $$$$\:\:\:\:{y}\:=\:{log}_{\mathrm{2}} \left({sin}\left({x}\right)+{cos}\left({x}\right)\right) \\ $$$$\:\:\:\Rightarrow\:\:{R}_{{y}} \:=\:?\left({Range}\:\right) \\ $$$$ \\ $$ Commented by mr W last…
Question Number 205091 by TonyCWX08 last updated on 08/Mar/24 $${f}:{z}\:\Rightarrow\:{z} \\ $$$${f}:{z}\:\Rightarrow\:{z}_{{n}} \\ $$$${f}:{z}_{{n}} \Rightarrow\:{z}_{{n}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 205070 by dimentri last updated on 07/Mar/24 $$\:\:\:\mathrm{Given}\:\begin{cases}{\mathrm{A}\cap\mathrm{B}=\:\left\{\:\mathrm{a},\:\mathrm{b}\right\}}\\{\mathrm{A}\cap\mathrm{C}\:=\:\left\{\:\mathrm{b},\:\mathrm{c}\right\}\:}\\{\mathrm{B}\cap\mathrm{C}=\:\left\{\:\mathrm{b}\:,\mathrm{d}\:\right\}}\end{cases} \\ $$$$\:\:\:\:\mathrm{then}\:\left(\mathrm{A}\cap\mathrm{C}\right)\:+\:\left(\mathrm{A}\cap\mathrm{B}\right)\:+\:\left(\mathrm{B}\cap\mathrm{C}\right) \\ $$ Commented by JDamian last updated on 07/Mar/24 $${Do}\:{you}\:{mean}\:\:\left(\mathrm{A}\cap\mathrm{C}\right)\:\cup\:\left(\mathrm{A}\cap\mathrm{B}\right)\:\cup\:\left(\mathrm{B}\cap\mathrm{C}\right)\:\:? \\ $$ Commented…
Question Number 205083 by BaliramKumar last updated on 07/Mar/24 Answered by A5T last updated on 07/Mar/24 $$\mathrm{1}×\mathrm{1}×\mathrm{30};\mathrm{1}×\mathrm{2}×\mathrm{15};\mathrm{1}×\mathrm{3}×\mathrm{10};\mathrm{1}×\mathrm{5}×\mathrm{6}; \\ $$$$\mathrm{2}×\mathrm{3}×\mathrm{5};\:{There}\:{are}\:\mathrm{5}\:{ways}\:{upto}\:{permutation} \\ $$$${but}\:{if}\:{order}\:{matters}\:{there}\:{are},\:\mathrm{4}×\mathrm{3}!+\frac{\mathrm{3}!}{\mathrm{2}!}=\mathrm{27} \\ $$ Commented by…
Question Number 205062 by BaliramKumar last updated on 07/Mar/24 Answered by cortano12 last updated on 07/Mar/24 $$\:\:\mathrm{P}_{\mathrm{max}} \:=\:\mathrm{240}\: \\ $$ Commented by BaliramKumar last updated…
Question Number 205063 by BaliramKumar last updated on 07/Mar/24 $$\mathrm{a}^{\mathrm{3}} \:+\:\mathrm{b}^{\mathrm{3}} \:+\:\mathrm{c}^{\mathrm{3}} \:=\:\mathrm{d}^{\mathrm{3}} \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a},\:\mathrm{b},\:\mathrm{c},\:\mathrm{d}\:\in\:\boldsymbol{\mathrm{N}} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{3}^{\mathrm{3}} \:+\:\mathrm{4}^{\mathrm{3}} \:+\:\mathrm{5}^{\mathrm{3}} \:=\:\mathrm{6}^{\mathrm{3}} \:\:\:\:\:\:\:\:\:\:\:\:\mathrm{HCF}\left(\mathrm{3},\:\mathrm{4},\:\mathrm{5}\right)\:=\:\mathrm{1} \\ $$$$\mathrm{other}\:\mathrm{example}\:……….. \\ $$ Commented…
Question Number 205073 by mr W last updated on 07/Mar/24 $${if}\:{a},\:{b},\:{c}\:{are}\:{the}\:{roots}\:{of} \\ $$$${f}\left({x}\right)={x}^{\mathrm{3}} −\mathrm{2024}{x}^{\mathrm{2}} +\mathrm{2024}{x}+\mathrm{2024} \\ $$$${find}\:\frac{\mathrm{1}}{\mathrm{1}−{a}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{1}−{b}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{1}−{c}^{\mathrm{2}} }=? \\ $$ Answered by cortano12…
Question Number 205053 by Abdullahrussell last updated on 06/Mar/24 Commented by Frix last updated on 08/Mar/24 $${x}=\mathrm{3} \\ $$$${y}=\frac{\mathrm{3}}{\mathrm{2}}+\frac{\sqrt{\mathrm{11}}}{\mathrm{2}}\mathrm{i} \\ $$$${z}=\frac{\mathrm{3}}{\mathrm{2}}−\frac{\sqrt{\mathrm{11}}}{\mathrm{2}}\mathrm{i} \\ $$$${x}+{y}+{z}=\mathrm{6} \\ $$…