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Author: Tinku Tara

Give-the-velocity-field-v-6-2xy-t-2-i-xy-2-10t-j-25k-what-is-the-acceleration-of-the-particle-at-3-0-2-at-time-t-1-

Question Number 10528 by Saham last updated on 16/Feb/17 $$\mathrm{Give}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{field} \\ $$$$\mathrm{v}\:=\:\left(\mathrm{6}\:+\:\mathrm{2xy}\:+\:\mathrm{t}^{\mathrm{2}} \right)\mathrm{i}\:−\:\left(\mathrm{xy}^{\mathrm{2}} \:+\:\mathrm{10t}\right)\mathrm{j}\:+\:\mathrm{25k} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{at}\:\left(\mathrm{3},\:\mathrm{0},\:\mathrm{2}\right) \\ $$$$\mathrm{at}\:\mathrm{time}\:\mathrm{t}\:=\:\mathrm{1}. \\ $$ Answered by robocop last updated…

Question-141598

Question Number 141598 by Gbenga last updated on 20/May/21 Answered by TheSupreme last updated on 21/May/21 $$\frac{{A}}{{x}+\mathrm{3}}+\frac{{B}}{{x}+\mathrm{2}}=\frac{−\mathrm{2021}}{\left({x}+\mathrm{3}\right)\left({x}+\mathrm{2}\right)}=\frac{{Ax}+\mathrm{2}{A}+{Bx}+\mathrm{3}{B}}{\left({x}+\mathrm{3}\right)\left({x}+\mathrm{2}\right)} \\ $$$${A}+{B}=\mathrm{0} \\ $$$$\mathrm{2}{A}+\mathrm{3}{B}=−\mathrm{2021} \\ $$$${A}=\mathrm{2021} \\ $$$${B}=−\mathrm{2021}…

What-s-the-minimum-value-of-13a-13b-2c-2a-2b-24a-b-13c-2b-2c-a-24b-13c-2a-2c-a-b-c-are-positive-numbers-I-think-nobody-can-solve-this-

Question Number 76061 by tw000001 last updated on 23/Dec/19 $$\mathrm{What}'\mathrm{s}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of} \\ $$$$\frac{\mathrm{13}{a}+\mathrm{13}{b}+\mathrm{2}{c}}{\mathrm{2}{a}+\mathrm{2}{b}}+\frac{\mathrm{24}{a}−{b}+\mathrm{13}{c}}{\mathrm{2}{b}+\mathrm{2}{c}}+\frac{−{a}+\mathrm{24}{b}+\mathrm{13}{c}}{\mathrm{2}{a}+\mathrm{2}{c}}? \\ $$$$\left({a},{b},{c}\:\mathrm{are}\:\mathrm{positive}\:\mathrm{numbers}.\right) \\ $$$$\mathrm{I}\:\mathrm{think}\:\mathrm{nobody}\:\mathrm{can}\:\mathrm{solve}\:\mathrm{this}. \\ $$ Answered by MJS last updated on 23/Dec/19…