Question Number 10364 by Joel575 last updated on 05/Feb/17 $$\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}+\mathrm{6}+\mathrm{7}+\mathrm{8}+\mathrm{9}+\mathrm{10}+\mathrm{11}\:=\:{x}^{{y}} \\ $$$$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{possible}\:\mathrm{solutions}\:\mathrm{of}\:{x}\:\mathrm{and}\:{y}\:\mathrm{is}\:… \\ $$ Answered by mrW1 last updated on 05/Feb/17 $$\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}+\mathrm{6}+\mathrm{7}+\mathrm{8}+\mathrm{9}+\mathrm{10}+\mathrm{11}=\frac{\mathrm{11}×\mathrm{12}}{\mathrm{2}}=\mathrm{66} \\ $$$${x}^{{y}} =\mathrm{66}…
Question Number 10363 by Joel575 last updated on 05/Feb/17 $$\Delta{ABC}\:\mathrm{with}\:{AB}\:=\:\mathrm{5},\:{BC}\:=\:\mathrm{7},\:{CA}\:=\:\mathrm{8} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\left(\mathrm{sin}\:{A}\:+\:\mathrm{sin}\:{B}\:+\:\mathrm{sin}\:{C}\right)\:.\:\left(\mathrm{cot}\:\frac{{A}}{\mathrm{2}}\:+\:\mathrm{cot}\:\frac{{B}}{\mathrm{2}}\:+\:\mathrm{cot}\:\frac{{C}}{\mathrm{2}}\right) \\ $$ Answered by mrW1 last updated on 06/Feb/17 $${a}={BC}=\mathrm{7} \\…
Question Number 10362 by Tawakalitu ayo mi last updated on 05/Feb/17 $$\mathrm{An}\:\mathrm{helium}\:\mathrm{atom}\:\mathrm{has}\:\mathrm{a}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{6}.\mathrm{64}\:×\:\mathrm{10}^{−\mathrm{27}} \mathrm{kg}\:\mathrm{and}\:\mathrm{a}\:\mathrm{charge} \\ $$$$\mathrm{Q}\:\mathrm{is}\:+\mathrm{2}\:\mathrm{electon}.\:\mathrm{Compare}\:\mathrm{the}\:\mathrm{magnitude}\:\mathrm{of}\:\mathrm{the}\:\mathrm{electric}\: \\ $$$$\mathrm{repulsion}\:\mathrm{to}\:\mathrm{that}\:\mathrm{of}\:\mathrm{the}\:\mathrm{gravitational}\:\mathrm{attraction}\:\mathrm{between}\:\mathrm{them}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 141435 by physicstutes last updated on 18/May/21 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{arraangment}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{letters} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{word}\:\mathrm{SYLLABUSES}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{each}\:\mathrm{word}\:\mathrm{contains}\:\mathrm{the}\:\mathrm{word}\:\mathrm{BUS}. \\ $$ Answered by mr W last updated on 19/May/21 $$\mathrm{SYLLABUSES}…
Question Number 10360 by Tawakalitu ayo mi last updated on 05/Feb/17 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}\:\mathrm{in}\:\mathrm{the}\:\mathrm{equation}. \\ $$$$\mathrm{3}^{\mathrm{x}} \:+\:\mathrm{4}^{\mathrm{x}} \:+\:\mathrm{5}^{\mathrm{x}} \:=\:\mathrm{6}^{\mathrm{x}} \\ $$ Answered by mrW1 last updated on…
Question Number 141431 by mohammad17 last updated on 18/May/21 $$\mathrm{2}\int_{\mathrm{0}} ^{\:\mathrm{1}} \int_{\mathrm{0}} ^{\:\mathrm{2}} \left({x}+\mathrm{2}{y}\right)^{\mathrm{8}} \:{dxdy} \\ $$ Answered by mathmax by abdo last updated on…
Question Number 75890 by abdomathmax last updated on 19/Dec/19 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left(\mathrm{2}{x}+\mathrm{3}\right)}{{x}^{\mathrm{2}} +\mathrm{4}}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10355 by Tawakalitu ayo mi last updated on 05/Feb/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{escape}\:\mathrm{velocity}\:\mathrm{from}\:\mathrm{the}\:\mathrm{surface} \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{planet}\:\mathrm{with}\:\mathrm{two}\:\mathrm{third}\:\mathrm{of}\:\mathrm{the}\:\mathrm{earth}'\mathrm{s} \\ $$$$\mathrm{gravity}\:\mathrm{but}\:\mathrm{the}\:\mathrm{same}\:\mathrm{radius}. \\ $$ Commented by Tawakalitu ayo mi last updated…
Question Number 75888 by abdomathmax last updated on 19/Dec/19 $${find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{\mathrm{1}+{x}^{\mathrm{4}} }{dx} \\ $$ Commented by 21042004 last updated on 20/Dec/19 $$\mathrm{this}\:\mathrm{equation}\:\mathrm{is}\:\mathrm{so}\:\mathrm{long} \\ $$$$\frac{\sqrt{\mathrm{2}}+\mathrm{2}\sqrt[{\mathrm{4}}]{−\mathrm{1}}\mathrm{F}\left(\mathrm{1}−\frac{{i}}{\mathrm{arcsinh}\left(\sqrt[{\mathrm{4}}]{−\mathrm{1}}\right)}\right)+\mathrm{2}\sqrt[{\mathrm{4}}]{−\mathrm{1}}{F}\left({i}\centerdot\mathrm{arcsinh}^{−\mathrm{1}}…
Question Number 10353 by j.masanja06@gmail.com last updated on 05/Feb/17 $$\mathrm{show}\:\mathrm{that}\:\alpha^{\mathrm{4}} =−\mathrm{3h}\alpha^{\mathrm{2}} −\mathrm{g}\alpha\:\mathrm{and}\:\mathrm{deduce} \\ $$$$\mathrm{that}\:\Sigma\alpha^{\mathrm{4}} =−\mathrm{3h}\Sigma\alpha^{\mathrm{2}} −\mathrm{g}\Sigma\alpha\:\mathrm{and}\:\mathrm{find}\: \\ $$$$\Sigma\alpha^{\mathrm{2}} ,\Sigma\alpha^{\mathrm{3}} ,\Sigma\alpha^{\mathrm{4}} \:\:\mathrm{in}\:\mathrm{term}\:\mathrm{of}\:\mathrm{g}\:\mathrm{and}\:\mathrm{h}. \\ $$ Terms of…