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Author: Tinku Tara

3-3-4-4-12-12-

Question Number 10290 by konen last updated on 02/Feb/17 $$\mathrm{3}×\mathrm{3}!+\mathrm{4}×\mathrm{4}!+…+\mathrm{12}×\mathrm{12}!=? \\ $$ Answered by ridwan balatif last updated on 02/Feb/17 $$\mathrm{3}×\mathrm{3}!+\mathrm{4}×\mathrm{4}!+…+\mathrm{12}×\mathrm{12}! \\ $$$$\left(\mathrm{4}−\mathrm{1}\right)×\mathrm{3}!+\left(\mathrm{5}−\mathrm{1}\right)×\mathrm{4}!+\left(\mathrm{6}−\mathrm{1}\right)×\mathrm{5}!+…+\left(\mathrm{13}−\mathrm{1}\right)×\mathrm{12}! \\ $$$$\mathrm{4}×\mathrm{3}!−\mathrm{1}×\mathrm{3}!+\mathrm{5}×\mathrm{4}!−\mathrm{1}×\mathrm{4}!+\mathrm{6}×\mathrm{5}!−\mathrm{1}×\mathrm{5}!+…+\mathrm{13}×\mathrm{12}!−\mathrm{1}×\mathrm{12}!…

9-x-2-x-3-x-3-3-x-

Question Number 10289 by konen last updated on 02/Feb/17 $$\frac{\mathrm{9}−\mathrm{x}^{\mathrm{2}} }{\mathrm{x}}+\mathrm{3}=\frac{\mathrm{x}−\mathrm{3}}{\mathrm{3}}\Rightarrow\Sigma\mathrm{x}=? \\ $$$$ \\ $$ Answered by ridwan balatif last updated on 02/Feb/17 $$\frac{\mathrm{9}−\mathrm{x}^{\mathrm{2}} }{\mathrm{x}}+\mathrm{3}=\frac{\mathrm{x}−\mathrm{3}}{\mathrm{3}}…

sen-2-cos-4-2-d-

Question Number 141362 by cesarL last updated on 17/May/21 $$\int{sen}\left(\mathrm{2}\theta\right){cos}^{\mathrm{4}} \left(\mathrm{2}\theta\right){d}\theta \\ $$ Answered by bemath last updated on 17/May/21 $$\int\:\mathrm{cos}\:^{\mathrm{4}} \left(\mathrm{2}\theta\right)\:\mathrm{sin}\:\left(\mathrm{2}\theta\right)\:{d}\theta= \\ $$$$−\frac{\mathrm{1}}{\mathrm{2}}\int\:\mathrm{cos}\:^{\mathrm{4}} \left(\mathrm{2}\theta\right)\:{d}\left(\mathrm{cos}\:\mathrm{2}\theta\right)\:=…

lim-x-x-1-x-2-1-1-

Question Number 141356 by physicstutes last updated on 17/May/21 $$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\left(\frac{{x}+\mathrm{1}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}}\:−\mathrm{1}\right) \\ $$ Answered by bemath last updated on 18/May/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\frac{{x}+\mathrm{1}−\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}}\right)=…

2000g-of-water-at-100-C-is-poured-into-a-copper-calorimeter-150g-of-water-at-10-C-The-temperature-of-the-mixture-is-45-C-Calculate-the-thermal-capaity-of-tbe-vessel-specific-heat-capacity-of-coppe

Question Number 10286 by Tawakalitu ayo mi last updated on 02/Feb/17 $$\mathrm{2000g}\:\mathrm{of}\:\mathrm{water}\:\mathrm{at}\:\mathrm{100}°\mathrm{C}\:\mathrm{is}\:\mathrm{poured}\:\mathrm{into}\:\mathrm{a}\: \\ $$$$\mathrm{copper}\:\mathrm{calorimeter}\:\mathrm{150g}\:\mathrm{of}\:\mathrm{water}\:\mathrm{at}\:\mathrm{10}°\mathrm{C}. \\ $$$$\mathrm{The}\:\mathrm{temperature}\:\mathrm{of}\:\mathrm{the}\:\mathrm{mixture}\:\mathrm{is}\:\mathrm{45}°\mathrm{C}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{thermal}\:\mathrm{capaity}\:\mathrm{of}\:\mathrm{tbe}\:\mathrm{vessel}. \\ $$$$\mathrm{specific}\:\mathrm{heat}\:\mathrm{capacity}\:\mathrm{of}\:\mathrm{copper}\:=\:\mathrm{400} \\ $$$$\mathrm{specific}\:\mathrm{heat}\:\mathrm{capacity}\:\mathrm{of}\:\mathrm{water}\:=\:\mathrm{4200} \\ $$ Answered…