Question Number 75818 by naka3546 last updated on 18/Dec/19 $${Given}\:\:{the}\:\:{increasing}\:\:{sequence}\:: \\ $$$$\mathrm{1},\:\mathrm{4},\:\mathrm{8},\:\mathrm{13},\:… \\ $$$${a}.\:{Find}\:\:{U}_{\mathrm{2019}} \\ $$$${b}.\:{Find}\:\:{S}_{\mathrm{2019}} \\ $$$${U}_{{n}} \:\:{is}\:\:{nth}−{term}\:\:{of}\:\:{the}\:\:{sequence} \\ $$$${S}_{{n}} \:\:{is}\:\:{sum}\:\:{of}\:\:{n}\:−\:{term}\:\:{of}\:\:{the}\:\:{sequence} \\ $$$${Arithmetic}\:\:{Sequence}\:\:{Degree}\:\:{Two} \\…
Question Number 141352 by mathdanisur last updated on 17/May/21 Answered by Rasheed.Sindhi last updated on 18/May/21 $${If}\:{P}\left({x}\right)\:{is}\:{divided}\:{by}\:{D}\left({x}\right)\:{giving} \\ $$$${quotient}\:{Q}\left({x}\right)\:\&\:{remainder}\:{R}\left({x}\right) \\ $$$${then} \\ $$$${P}\left({x}\right)={D}\left({x}\right).{Q}\left({x}\right)+{R}\left({x}\right) \\ $$$${x}^{\mathrm{999}}…
Question Number 10282 by Tawakalitu ayo mi last updated on 02/Feb/17 $$\mathrm{210}\:\mathrm{cm}^{\mathrm{3}} \:\mathrm{of}\:\mathrm{Nitrogen}\:\mathrm{at}\:\mathrm{a}\:\mathrm{pressure}\:\mathrm{of}\:\mathrm{400}\:\mathrm{mmHg} \\ $$$$\mathrm{and}\:\mathrm{100}\:\mathrm{cm}^{\mathrm{3}} \:\mathrm{of}\:\mathrm{carbon}\left(\mathrm{iv}\right)\mathrm{oxide}\:\mathrm{at}\:\mathrm{a}\:\mathrm{pressure}\: \\ $$$$\mathrm{of}\:\mathrm{350}\:\mathrm{mmHg}\:\mathrm{were}\:\mathrm{introduce}\:\mathrm{into}\:\mathrm{a}\:\mathrm{200}\:\mathrm{cm}^{\mathrm{3}} \\ $$$$\mathrm{vessel}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{total}\:\mathrm{pressure}\:\mathrm{in}\:\mathrm{the}\:\mathrm{vessel}. \\ $$ Commented by Tawakalitu…
Question Number 75814 by Master last updated on 18/Dec/19 Commented by Master last updated on 18/Dec/19 $$\mathrm{xyz}=? \\ $$ Answered by mr W last updated…
Question Number 10277 by Tawakalitu ayo mi last updated on 01/Feb/17 $$\mathrm{How}\:\mathrm{can}\:\mathrm{kerosine}\:\mathrm{be}\:\mathrm{heated}\:???.\: \\ $$$$\mathrm{please}\:\mathrm{give}\:\mathrm{reasons}. \\ $$ Answered by ridwan balatif last updated on 01/Feb/17 $$\mathrm{i}\:\mathrm{think}\:\mathrm{because}\:\mathrm{kerosine}\:\mathrm{has}\:\mathrm{short}\:\mathrm{carbon}\:\mathrm{chain}…
Question Number 141345 by Dwaipayan Shikari last updated on 17/May/21 $$\frac{{log}\left(\zeta\left({s}\right)\right)}{{s}}=\int_{\mathrm{1}} ^{\infty} {J}\left({x}\right){x}^{−{s}−\mathrm{1}} {dx}\:\left(\:{Prove}\:{that}\right) \\ $$$${Here}\:\:{J}\left({x}\right)=\pi\left({x}\right)+\frac{\mathrm{1}}{\mathrm{2}}\pi\left(\sqrt{{x}}\right)+\frac{\mathrm{1}}{\mathrm{3}}\pi\left(\sqrt[{\mathrm{3}}]{{x}}\right)+… \\ $$$$\pi\left({x}\right):=\boldsymbol{\mathrm{P}{rime}}\:\boldsymbol{{counting}}\:\boldsymbol{{function}} \\ $$ Terms of Service Privacy Policy…
Question Number 141346 by mnjuly1970 last updated on 17/May/21 Answered by qaz last updated on 17/May/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{ln}^{\mathrm{2}} {x}}{\mathrm{1}−{x}^{\mathrm{2}} }{dx} \\ $$$$=\int_{\mathrm{0}} ^{\infty} \frac{{y}^{\mathrm{2}}…
Question Number 75809 by aliesam last updated on 17/Dec/19 Commented by kaivan.ahmadi last updated on 19/Dec/19 $$\int_{\mathrm{0}} ^{\mathrm{3}} \int_{\mathrm{0}} ^{\frac{{x}}{\mathrm{3}}} {e}^{{x}^{\mathrm{2}} } {dydx}=\int_{\mathrm{0}} ^{\mathrm{3}} {e}^{{x}^{\mathrm{2}}…
Question Number 141340 by physicstutes last updated on 17/May/21 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{function}\:{f}\:\mathrm{defined}\:\mathrm{by} \\ $$$$\:{f}\left({x}\right)\:=\:\begin{cases}{\frac{\mathrm{2}{e}^{{x}} }{{e}^{{x}} −\mathrm{1}},{x}\neq\:\mathrm{0}}\\{\mathrm{0},\:{x}\:=\:\mathrm{0}}\end{cases} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{study}\:\mathrm{the}\:\mathrm{differentiability}\:\mathrm{of}\:{f}\:\mathrm{at}\:{x}\:=\:\mathrm{0}. \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{point}\:\left(\mathrm{0},\mathrm{1}\right)\:\mathrm{is}\:\mathrm{the}\:\mathrm{centre}\:\mathrm{of}\:\mathrm{symetry}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{curve}\:\mathrm{of}\:{f}. \\ $$ Terms of Service…
Question Number 10268 by j.masanja06@gmail.com last updated on 01/Feb/17 Answered by sandy_suhendra last updated on 01/Feb/17 $$\left(\mathrm{x}−\mathrm{3}\right)\left(\mathrm{x}+\mathrm{5}\right)\left(\mathrm{x}−\mathrm{1}\right)+\mathrm{6}+\mathrm{42}−\mathrm{6}\left(\mathrm{x}+\mathrm{5}\right)+\mathrm{6}\left(\mathrm{x}−\mathrm{3}\right)+\mathrm{7}\left(\mathrm{x}−\mathrm{1}\right)=\mathrm{0} \\ $$$$\mathrm{x}^{\mathrm{3}} +\mathrm{x}^{\mathrm{2}} −\mathrm{10x}+\mathrm{8}=\mathrm{0} \\ $$$$\left(\mathrm{x}−\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{8}\right)=\mathrm{0} \\…