Question Number 10222 by Tawakalitu ayo mi last updated on 30/Jan/17 $$\mathrm{solve}\:\mathrm{simultaneously}. \\ $$$$\mathrm{m}^{\mathrm{4}} \:+\:\mathrm{n}^{\mathrm{4}} \:=\:\mathrm{9m}^{\mathrm{2}} \mathrm{n}^{\mathrm{2}} \:+\:\mathrm{1}\:\:\:\:\:\:\:……\:\left(\mathrm{i}\right) \\ $$$$\mathrm{m}\:+\:\mathrm{n}\:=\:\mathrm{4}\:……..\:\left(\mathrm{ii}\right) \\ $$ Commented by prakash…
Question Number 75756 by 21042004 last updated on 16/Dec/19 $$\underset{{x}=\mathrm{1}} {\overset{\mathrm{99}} {\sum}}\left(\frac{\mathrm{1}}{\mathrm{2}{x}+\mathrm{1}}\right) \\ $$ Commented by mr W last updated on 17/Dec/19 Terms of Service…
Question Number 141294 by bemath last updated on 17/May/21 $${Find}\:{max}\:\&\:{min}\:{value}\:{of} \\ $$$$\:{f}\left({x}\right)=\frac{{x}}{{x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{9}}. \\ $$ Answered by MJS_new last updated on 17/May/21 $$\frac{{df}}{{dx}}=\frac{−{x}^{\mathrm{2}} +\mathrm{9}}{\left({x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{9}\right)^{\mathrm{2}}…
Question Number 141289 by ajfour last updated on 17/May/21 Commented by ajfour last updated on 17/May/21 $$\:\:{x}^{\mathrm{3}} −{x}−{c}=\mathrm{0}\:.\:{To}\:{find}\:{excess}! \\ $$ Answered by ajfour last updated…
Question Number 141291 by mr W last updated on 17/May/21 Commented by mr W last updated on 17/May/21 $${OB}=\sqrt{\left({R}−{r}\right)^{\mathrm{2}} −{r}^{\mathrm{2}} }=\sqrt{{R}^{\mathrm{2}} −\mathrm{2}{Rr}} \\ $$$${AB}={R}+\sqrt{{R}^{\mathrm{2}} −\mathrm{2}{Rr}}=\frac{{r}}{\mathrm{tan}\:\mathrm{22}.\mathrm{5}°}…
Question Number 75753 by Emmanuel_N last updated on 16/Dec/19 $$\left(\frac{\left(\mathrm{x}^{\mathrm{1}/\mathrm{3}} +\mathrm{x}^{−\mathrm{1}/\mathrm{3}} \right)^{\mathrm{2}} −\mathrm{2}}{\left(\mathrm{x}^{\mathrm{1}/\mathrm{3}} +\mathrm{x}^{−\mathrm{1}/\mathrm{3}} \right)^{\mathrm{2}} +\mathrm{2}}−\mathrm{x}\right)^{\mathrm{3}/\mathrm{4}} \\ $$ Answered by $@ty@m123 last updated on 16/Dec/19…
Question Number 10216 by konen last updated on 30/Jan/17 $$\frac{\sqrt{\mathrm{2}}\:+\sqrt{\mathrm{4}}+…+\sqrt{\mathrm{28}}}{\:\sqrt{\mathrm{3}}+\sqrt{\mathrm{6}}+…+\sqrt{\mathrm{42}}}=\sqrt{\mathrm{x}}\:\Rightarrow\mathrm{x}=? \\ $$ Answered by nume1114 last updated on 30/Jan/17 $${LHS}=\frac{\underset{{n}=\mathrm{1}} {\overset{\mathrm{14}} {\sum}}\sqrt{\mathrm{2}{n}}}{\underset{{n}=\mathrm{1}} {\overset{\mathrm{14}} {\sum}}\sqrt{\mathrm{3}{n}}} \\…
Question Number 75750 by rajesh4661kumar@gmail.com last updated on 16/Dec/19 Commented by MJS last updated on 16/Dec/19 $$\mathrm{this}\:\mathrm{cannot}\:\mathrm{be}\:\mathrm{solved}\:\mathrm{using}\:\mathrm{elementary} \\ $$$$\mathrm{calculus} \\ $$$$\mathrm{a}\:\mathrm{solution}\:\mathrm{was}\:\mathrm{posted}\:\mathrm{on}\:\mathrm{this}\:\mathrm{forum}\:\mathrm{some} \\ $$$$\mathrm{time}\:\mathrm{ago} \\ $$…
Question Number 75751 by aguy last updated on 16/Dec/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10214 by Tawakalitu ayo mi last updated on 30/Jan/17 $$\mathrm{How}\:\mathrm{many}\:\mathrm{moles}\:\mathrm{of}\:\mathrm{oxygen}\:\mathrm{atom}\:\mathrm{are}\:\mathrm{in} \\ $$$$\mathrm{0}.\mathrm{50}\:\mathrm{mol}\:\mathrm{of}\:\mathrm{Ca}\left(\mathrm{ClO3}\right)\mathrm{2} \\ $$ Commented by sandy_suhendra last updated on 31/Jan/17 $$\mathrm{moles}\:\mathrm{of}\:\mathrm{oxygen}=\mathrm{6}×\mathrm{0}.\mathrm{50}\:\mathrm{mol}=\mathrm{3}\:\mathrm{mol} \\…