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Author: Tinku Tara

Question-10078

Question Number 10078 by ridwan balatif last updated on 23/Jan/17 Commented by ridwan balatif last updated on 23/Jan/17 $$\mathrm{x}_{\mathrm{1}} ^{\mathrm{2011}} +\mathrm{x}_{\mathrm{2}} ^{\mathrm{2011}} =\mathrm{A}\:\mathrm{and}\:\mathrm{x}_{\mathrm{1}} ^{\mathrm{2012}} +\mathrm{x}_{\mathrm{2}}…

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Question Number 141150 by jlewis last updated on 16/May/21 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{concentration}\:\mathrm{of}\left[\mathrm{OH}^{−} \right]\: \\ $$$$\mathrm{in}\:\mathrm{0}.\mathrm{4M}\:\mathrm{NH}_{\mathrm{4}} \mathrm{OH}\:\mathrm{solution}\:\mathrm{having}\: \\ $$$$\mathrm{5}.\mathrm{35g}\:\mathrm{NH}_{\mathrm{4}} \mathrm{Cl}\:\mathrm{in}\:\mathrm{a}\:\mathrm{one}\left(\mathrm{1}\right)\:\mathrm{litre}\:\mathrm{solution}. \\ $$$$\left(\mathrm{k}_{\mathrm{b}} =\mathrm{1}.\mathrm{8}×\mathrm{10}^{−\mathrm{5}} ,\mathrm{N}=\mathrm{14},\mathrm{H}=\mathrm{1},\mathrm{Cl}=\mathrm{35}.\mathrm{5}\right) \\ $$$$ \\ $$…

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Question Number 10076 by konen last updated on 23/Jan/17 $$\mathrm{3a}=\mathrm{4b}=\mathrm{5c} \\ $$$$\mathrm{2a}+\mathrm{3b}−\mathrm{c}=\mathrm{146} \\ $$$$\Rightarrow\mathrm{c}=? \\ $$ Answered by ridwan balatif last updated on 23/Jan/17 $$\mathrm{3a}=\mathrm{5c}\rightarrow\mathrm{a}=\frac{\mathrm{5}}{\mathrm{3}}\mathrm{c}…

Question-75606

Question Number 75606 by liki last updated on 13/Dec/19 Commented by mathmax by abdo last updated on 15/Dec/19 $$\begin{cases}{{x}−{y}=\mathrm{3}}\\{\mathrm{2}{x}−\mathrm{2}{y}\:={k}\:\:\:\:\:{we}\:{have}\:\Delta_{{s}} =\begin{vmatrix}{\mathrm{1}\:\:\:\:\:\:−\mathrm{1}}\\{\mathrm{2}\:\:\:\:\:\:\:\:\:−\mathrm{2}}\end{vmatrix}}\end{cases}=−\mathrm{2}+\mathrm{2}=\mathrm{0} \\ $$$$\Delta_{{x}} =\begin{vmatrix}{\mathrm{3}\:\:\:\:\:\:\:\:\:−\mathrm{1}}\\{{k}\:\:\:\:\:\:\:\:\:\:\:\:−\mathrm{2}}\end{vmatrix}=−\mathrm{6}+{k} \\ $$$$\Delta_{{y}}…

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Question Number 10069 by Tawakalitu ayo mi last updated on 23/Jan/17 $$\mathrm{A}\:\mathrm{man}\:\mathrm{can}\:\mathrm{row}\:\mathrm{a}\:\mathrm{boat}\:\mathrm{at}\:\mathrm{4}\:\mathrm{km}/\mathrm{hr}\:\mathrm{in}\:\mathrm{still}\:\mathrm{water}. \\ $$$$\mathrm{He}\:\mathrm{row}\:\mathrm{the}\:\mathrm{boat}\:\mathrm{2km}\:\mathrm{upstream}\:\mathrm{and}\:\mathrm{2km}\:\mathrm{back} \\ $$$$\mathrm{to}\:\mathrm{his}\:\mathrm{starting}\:\mathrm{place}\:\mathrm{in}\:\mathrm{2}\:\mathrm{hours}.\:\mathrm{How}\:\mathrm{fast}\:\mathrm{is}\: \\ $$$$\mathrm{the}\:\mathrm{stream}\:\mathrm{flowing}. \\ $$ Commented by ridwan balatif last…

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Question Number 10067 by konen last updated on 22/Jan/17 $$\frac{\mathrm{a}×\mathrm{b}×\mathrm{c}}{\mathrm{a}+\mathrm{b}}=−\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\frac{\mathrm{a}×\mathrm{b}×\mathrm{c}}{\mathrm{b}+\mathrm{c}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\frac{\mathrm{a}×\mathrm{b}×\mathrm{c}}{\mathrm{a}+\mathrm{c}}=\mathrm{1} \\ $$$$\Rightarrow\mathrm{a}×\mathrm{b}×\mathrm{c}=? \\ $$$$ \\ $$$$ \\ $$ Answered by mrW1…