Question Number 141045 by BHOOPENDRA last updated on 15/May/21 Commented by mr W last updated on 15/May/21 $${search}\:{your}\:{own}\:{posts}\:{using}\:“{my}\:{posts}'', \\ $$$${you}\:{will}\:{find}\:{the}\:{old}\:{post}. \\ $$ Commented by mr…
Question Number 9975 by Tawakalitu ayo mi last updated on 19/Jan/17 $$\int_{\:−\mathrm{2}\:} ^{\:−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:\mathrm{dx} \\ $$ Commented by prakash jain last updated on 20/Jan/17 $$\int\frac{\mathrm{1}}{{x}}{dx}=\mathrm{ln}\:{x}…
Question Number 75509 by ~blr237~ last updated on 12/Dec/19 $$\mathrm{Give}\:\mathrm{the}\:\mathrm{exponentional}\:\mathrm{form}\:\mathrm{of}\: \\ $$$$\mathrm{the}\:\mathrm{complex}\:\mathrm{Z}=\frac{\mathrm{1}−\mathrm{cos}\theta+\mathrm{itan}\theta}{\mathrm{1}+\mathrm{cos}\theta−\mathrm{isin}\theta} \\ $$ Answered by MJS last updated on 12/Dec/19 $$\frac{\mathrm{1}−{c}+\mathrm{i}{t}}{\mathrm{1}+{c}−\mathrm{i}{s}}=\frac{{c}^{\mathrm{2}} −\mathrm{2}{c}−{st}+\mathrm{1}}{{c}^{\mathrm{2}} −\mathrm{2}{c}+{s}^{\mathrm{2}} +\mathrm{1}}−\frac{{cs}+{ct}−{s}−{t}}{{c}^{\mathrm{2}}…
Question Number 9970 by Tawakalitu ayo mi last updated on 19/Jan/17 Answered by mrW1 last updated on 19/Jan/17 $${the}\:{result}\:{is}\:{a}\:{zero}\:{vector}\:{or}\:{null}\:{vector}\:\left(\overset{\rightarrow} {\mathrm{0}}\right). \\ $$$${a}\:{zero}\:{or}\:{null}\:{vector}\:{has}\:{no}\:{magnitude}. \\ $$ Commented…
Question Number 75504 by mathocean1 last updated on 12/Dec/19 $$\mathrm{please}\:\mathrm{sirs}\:\mathrm{i}\:\mathrm{would}\:\mathrm{like}\:\mathrm{that}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me}\:\mathrm{to} \\ $$$$\mathrm{show}\:\mathrm{this}: \\ $$$$\mathrm{sin}\left(\frac{\pi}{\mathrm{3}}+\mathrm{x}\right)\mathrm{sin}\left(\frac{\pi}{\mathrm{3}\:}−\mathrm{x}\right)=\frac{\mathrm{3}}{\mathrm{4}}−\mathrm{sin}^{\mathrm{2}} \mathrm{x} \\ $$ Answered by som(math1967) last updated on 12/Dec/19 $${sin}\left(\frac{\pi}{\mathrm{3}}\:+{x}\right){sin}\left(\frac{\pi}{\mathrm{3}}−{x}\right)…
Question Number 9969 by Tawakalitu ayo mi last updated on 20/Jan/17 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{viscosity}\:\mathrm{of}\:\mathrm{water}\:\mathrm{flowing}\:\mathrm{steadily} \\ $$$$\mathrm{between}\:\mathrm{two}\:\mathrm{parallel}\:\mathrm{plane}.\:\mathrm{The}\:\mathrm{distance}\: \\ $$$$\mathrm{between}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{1}.\mathrm{9km},\:\mathrm{the}\:\mathrm{third}\:\mathrm{plane} \\ $$$$\mathrm{has}\:\mathrm{a}\:\mathrm{constant}\:\mathrm{viscosity}\:\mathrm{of}\:\mathrm{20}\:\mathrm{cm}/\mathrm{sec}\:\mathrm{when}\:\mathrm{a} \\ $$$$\mathrm{force}\:\mathrm{square}\:\mathrm{300N}/\mathrm{m}^{\mathrm{3}} \:\mathrm{is}\:\mathrm{applied}. \\ $$ Terms of…
Question Number 75505 by naka3546 last updated on 12/Dec/19 Commented by mr W last updated on 12/Dec/19 $${i}\:{don}'{t}\:{think}\:{such}\:{m}\:{and}\:{n}\:{exist}. \\ $$$${the}\:{last}\:{digit}\:{from}\:{right}\:{of}\:\mathrm{2019}^{{m}} \\ $$$${is}\:\mathrm{1}\:{or}\:\mathrm{9}.\:\mathrm{5}\:{times}\:{of}\:{it}\:{is}\:{always}\:\mathrm{5}, \\ $$$${but}\:{this}\:{can}\:{not}\:{be}\:\mathrm{2019}^{{n}} ,\:{since}…
Question Number 75502 by mathocean1 last updated on 12/Dec/19 $$\left.\mathrm{S}\left.\mathrm{olve}\:\mathrm{it}\:\mathrm{in}\:\right]−\pi;\pi\right] \\ $$$$\mathrm{sin}\left(\mathrm{2x}\right)=\mathrm{cos}\left(\mathrm{x}\right) \\ $$ Commented by mathmax by abdo last updated on 12/Dec/19 $${sin}\left(\mathrm{2}{x}\right)={cosx}\:\Leftrightarrow\:{sin}\left(\mathrm{2}{x}\right)={sin}\left(\frac{\pi}{\mathrm{2}}−{x}\right)\:\Leftrightarrow\mathrm{2}{x}=\frac{\pi}{\mathrm{2}}−{x}+\mathrm{2}{k}\pi\:{or} \\…
Question Number 9962 by konen last updated on 19/Jan/17 $$\mathrm{a},\mathrm{b}\:\in\mathrm{Z}^{+} \\ $$$$\mathrm{b}^{\mathrm{2}} −\mathrm{a}^{\mathrm{2}} =\mathrm{2b}+\mathrm{7a}+\mathrm{4} \\ $$$$\Rightarrow\:\mathrm{a}+\mathrm{b}=? \\ $$ Commented by prakash jain last updated on…
Question Number 141034 by jahar last updated on 15/May/21 $${I}\:{don}'{t}\:{recover}\:{my}\:{old}\:{phone}\:{documents}. \\ $$$${please}\:{advise}\:{me}\:{in}\:{briefly}\:{how}\:{to}\:{restore} \\ $$$$\:{my}\:{old}\:{phone}\:{documents}\:{in}\:{my}\:{new} \\ $$$$\:{phone}. \\ $$$$ \\ $$$${plese}\:{help}\:{me}. \\ $$ Commented by Tinku…