Question Number 204890 by mr W last updated on 29/Feb/24 Commented by mr W last updated on 29/Feb/24 $${ABCD}\:{is}\:{a}\:{square}\:{with}\:{side}\:{length}\:\mathrm{2}. \\ $$$${E}\:{is}\:{midpoint}\:{of}\:{CD},\:{F}\:{is}\:{midpoint} \\ $$$${of}\:{AD}.\:{find}\:{AP}. \\ $$…
Question Number 204885 by Tawa11 last updated on 29/Feb/24 The density of a gas is 1.775kgm³ at 29°c and 10⁵N/m² pressure, its specific heat capacity…
Question Number 204869 by BaliramKumar last updated on 29/Feb/24 $$\mathrm{How}\:\mathrm{many}\:\mathrm{distinct}\:\mathrm{positive}\:\mathrm{integer}\:\mathrm{valued}\:\mathrm{solution}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\mathrm{exist}\:\mathrm{the}\:\mathrm{equation}\:\left({x}^{\mathrm{2}} \:−\:\mathrm{7}{x}\:+\:\mathrm{11}\right)^{\left({x}^{\mathrm{2}} \:−\mathrm{13}{x}\:+\:\mathrm{42}\right)} \:=\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\left(\mathrm{a}\right)\:\mathrm{2}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{b}\right)\:\mathrm{4}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{c}\right)\:\mathrm{6}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{d}\right)\:\mathrm{8} \\ $$ Answered by A5T last updated on…
Question Number 204853 by depressiveshrek last updated on 29/Feb/24 $${f}\left({x}\right)=\sqrt{\mathrm{1}−\mathrm{log}_{\left(\mathrm{2}{x}+\mathrm{5}\right)} \left(\left({x}+\mathrm{1}\right)^{\mathrm{2}} \right)} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{domain}\:\mathrm{of}\:\mathrm{this}\:\mathrm{function} \\ $$ Answered by Frix last updated on 29/Feb/24 $$−\frac{\mathrm{5}}{\mathrm{2}}<{x}\leqslant\mathrm{2}\wedge{x}\neq−\mathrm{2}\wedge{x}\neq−\mathrm{1} \\…
Question Number 204866 by mathlove last updated on 29/Feb/24 $$\int\:\frac{{x}+\mathrm{3}}{{x}^{\mathrm{2}} \sqrt{\mathrm{2}{x}+\mathrm{3}}}\:{dx}=? \\ $$ Answered by Frix last updated on 29/Feb/24 $$\int\frac{{x}+\mathrm{3}}{{x}^{\mathrm{2}} \sqrt{\mathrm{2}{x}+\mathrm{3}}}{dx}\:\overset{{t}=\frac{\sqrt{\mathrm{2}{x}+\mathrm{3}}}{{x}}} {=}−\int{dt}=−{t}=−\frac{\sqrt{\mathrm{2}{x}+\mathrm{3}}}{{x}}+{C} \\ $$…
Question Number 204826 by necx122 last updated on 28/Feb/24 $${A}\:{rectangular}\:{enclosure}\:{is}\:{to}\:{be}\:{made} \\ $$$${against}\:{a}\:{straight}\:{wall}\:{using}\:{three} \\ $$$${lengths}\:{of}\:{fencing}.\:{The}\:{total}\:{length}\:{of} \\ $$$${the}\:{fencing}\:{available}\:{is}\:\mathrm{50}{m}.\:{Show} \\ $$$${that}\:{the}\:{area}\:{of}\:{the}\:{enclosure}\:{is} \\ $$$$\mathrm{50}{x}\:−\:\mathrm{2}{x}^{\mathrm{2}} ,\:{where}\:{x}\:{is}\:{the}\:{length}\:{of}\:{the} \\ $$$${sides}\:{perpendicular}\:{to}\:{the}\:{wall}.\:{Hence} \\ $$$${find}\:{the}\:{maximum}\:{area}\:{of}\:{the}…
Question Number 204852 by ibrahimabdullayev last updated on 28/Feb/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 204851 by ibrahimabdullayev last updated on 28/Feb/24 Answered by A5T last updated on 29/Feb/24 $$\mathrm{5}^{\mathrm{2}} =\mathrm{6}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} −\mathrm{2}×\mathrm{6}×\mathrm{5}{cos}\angle{ACB}\Rightarrow{cos}\angle{ACB}=\frac{\mathrm{3}}{\mathrm{5}} \\ $$$$\mathrm{6}^{\mathrm{2}} =\mathrm{5}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} −\mathrm{2}×\mathrm{5}×\mathrm{5}{cos}\angle{ABC}\Rightarrow{cos}\angle{ABC}=\frac{\mathrm{7}}{\mathrm{25}}…
Question Number 204844 by mr W last updated on 28/Feb/24 $${find}\:\lfloor\underset{{n}=\mathrm{1}} {\overset{\mathrm{80}} {\sum}}\frac{\mathrm{1}}{\:\sqrt{{n}}}\rfloor=? \\ $$ Commented by Frix last updated on 28/Feb/24 $$\mathrm{16} \\ $$…
Question Number 204845 by LuisTony last updated on 28/Feb/24 Answered by TonyCWX08 last updated on 29/Feb/24 $${Altura}\:{del}\:{arbol} \\ $$$$=\:\mathrm{95}\left(\mathrm{sin}\:\mathrm{25}\right) \\ $$$$\approx\:\mathrm{40}.\mathrm{15}{m} \\ $$$${Distancia}\:{de}\:{la}\:{cometa}\:{al}\:{suelo} \\ $$$$\approx\mathrm{40}.\mathrm{15}{m}…