Question Number 9908 by ridwan balatif last updated on 15/Jan/17 Commented by ridwan balatif last updated on 15/Jan/17 $$\:\mathrm{x}\:\mathrm{maximum}\:=…? \\ $$ Answered by mrW1 last…
Question Number 140977 by Mathspace last updated on 14/May/21 $${find}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{e}^{−{t}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)} }{\mathrm{1}+{x}^{\mathrm{2}} }{dx}\:\:{with}\:{t}\geqslant\mathrm{0} \\ $$ Answered by mathmax by abdo last updated on…
Question Number 9907 by amir last updated on 15/Jan/17 Commented by RasheedSoomro last updated on 15/Jan/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{meant}\:\mathrm{by}\:\mathrm{h}_{{a}} ? \\ $$ Commented by amir last updated…
Question Number 140976 by Mathspace last updated on 14/May/21 $${find}\:\int_{\mathrm{0}} ^{\pi} \:\frac{{dx}}{\left(\mathrm{2}−{cosx}−{sinx}\right)^{\mathrm{2}} } \\ $$$$ \\ $$ Answered by Ar Brandon last updated on 14/May/21…
Question Number 75440 by aliesam last updated on 11/Dec/19 Commented by MJS last updated on 11/Dec/19 $$\mathrm{I}'\mathrm{m}\:\mathrm{not}\:\mathrm{good}\:\mathrm{at}\:\mathrm{this}\:\mathrm{but}\:\mathrm{it}\:\mathrm{should}\:\mathrm{be}\:\mathrm{true} \\ $$$$\mathrm{for}\:\mathrm{any}\:{x}\:\mathrm{at}\:\mathrm{least}\:{x}\geqslant\mathrm{1} \\ $$$$\underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{k}} \mathrm{e}^{−\left(\mathrm{2}{k}−\mathrm{1}\right){x}} }{\left(\mathrm{2}{k}−\mathrm{1}\right)\left(\mathrm{1}−\mathrm{e}^{−\mathrm{2}{x}}…
Question Number 140978 by Mathspace last updated on 14/May/21 $${calculate}\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{\mathrm{1}}{\left({n}!\right)^{\mathrm{2}} } \\ $$ Answered by Dwaipayan Shikari last updated on 14/May/21 $$\underset{{n}=\mathrm{0}} {\overset{\infty}…
Question Number 140973 by EnterUsername last updated on 14/May/21 $$\mathrm{If}\:\alpha\:\mathrm{and}\:\beta\:\mathrm{are}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{2x}^{\mathrm{2}} +{a}\mathrm{x}+{b}=\mathrm{0}, \\ $$$$\mathrm{then}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{2}\left(\alpha\mathrm{x}+\beta\right)^{\mathrm{2}} + \\ $$$${a}\left(\alpha\mathrm{x}+\beta\right)+{b}=\mathrm{0}\:\mathrm{is} \\ $$$$\left(\mathrm{A}\right)\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:\frac{\alpha+\mathrm{2}{b}}{\alpha^{\mathrm{2}} } \\ $$$$\left(\mathrm{C}\right)\:\frac{{a}\alpha+{b}}{\mathrm{2}\alpha^{\mathrm{2}} }\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\frac{{a}\alpha−\mathrm{2}{b}}{\mathrm{2}\alpha^{\mathrm{2}} } \\ $$…
Question Number 75439 by otchereabdullai@gmail.com last updated on 11/Dec/19 $$\mathrm{A}\:\mathrm{man}\:\mathrm{left}\:\mathrm{his}\:\mathrm{office}\:\mathrm{in}\:\mathrm{a}\:\mathrm{car}\:\mathrm{at}\:\mathrm{10am} \\ $$$$\mathrm{to}\:\mathrm{restaurant}\:\mathrm{30km}\:\mathrm{away}.\:\mathrm{He}\:\mathrm{expected} \\ $$$$\mathrm{to}\:\mathrm{arrive}\:\mathrm{at}\:\mathrm{11}:\mathrm{10am}\:\mathrm{but}\:\mathrm{had}\:\mathrm{to}\:\mathrm{stop}\: \\ $$$$\mathrm{15km}\:\mathrm{from}\:\mathrm{the}\:\mathrm{office}\:\mathrm{for}\:\mathrm{15}\:\mathrm{minutes}\:. \\ $$$$\mathrm{He}\:\mathrm{arrived}\:\mathrm{at}\:\mathrm{the}\:\mathrm{restaurant}\:\mathrm{5}\:\mathrm{minutes}\: \\ $$$$\mathrm{late}. \\ $$$$\mathrm{a}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{initial}\:\mathrm{speed} \\ $$$$\mathrm{b}.\:\mathrm{Draw}\:\mathrm{a}\:\mathrm{travel}\:\mathrm{graph}\:\mathrm{for}\:\mathrm{the}\:\mathrm{whole}\:\mathrm{journey} \\…
Question Number 9902 by sahidraja786md@gmail.com last updated on 14/Jan/17 $${x}+\mathrm{3}{y}=\mathrm{6}, \\ $$$$\mathrm{2}{x}−\mathrm{3}{y}=\mathrm{12} \\ $$ Answered by ridwan balatif last updated on 14/Jan/17 $$\mathrm{x}+\mathrm{3y}=\mathrm{6} \\ $$$$\mathrm{2x}−\mathrm{3y}=\mathrm{12}…
Question Number 140974 by EnterUsername last updated on 14/May/21 $$\mathrm{If}\:\mathrm{the}\:\mathrm{equations}\:\mathrm{x}^{\mathrm{2}} −\mathrm{3x}+{a}=\mathrm{0}\:\mathrm{and}\:\mathrm{x}^{\mathrm{2}} +{a}\mathrm{x}−\mathrm{3}=\mathrm{0} \\ $$$$\mathrm{have}\:\mathrm{a}\:\mathrm{common}\:\mathrm{root},\:\mathrm{then}\:\mathrm{a}\:\mathrm{possible}\:\mathrm{value}\:\mathrm{of}\:{a}\:\mathrm{is} \\ $$$$\left(\mathrm{A}\right)\:\mathrm{3}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{C}\right)\:−\mathrm{2}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\mathrm{2} \\ $$ Commented by mohammad17 last updated on 14/May/21…