Question Number 75437 by Master last updated on 11/Dec/19 Commented by Master last updated on 11/Dec/19 $$\mathrm{sir}\:\boldsymbol{\mathrm{mind}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{power}}\:\:\mathrm{please}\: \\ $$ Commented by Master last updated on…
Question Number 140969 by EnterUsername last updated on 14/May/21 $$\mathrm{The}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{x}^{\mathrm{2}} −\left({m}−\mathrm{3}\right)\mathrm{x}+{m}=\mathrm{0}\:\mathrm{are} \\ $$$$\mathrm{such}\:\mathrm{that}\:\mathrm{exactly}\:\mathrm{one}\:\mathrm{of}\:\mathrm{them}\:\mathrm{lies}\:\mathrm{in}\:\mathrm{the}\:\mathrm{interval} \\ $$$$\left(\mathrm{1},\:\mathrm{2}\right).\:\mathrm{Then} \\ $$$$\left(\mathrm{A}\right)\:\mathrm{5}<{m}<\mathrm{7}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:{m}<\mathrm{10} \\ $$$$\left(\mathrm{C}\right)\:\mathrm{2}<{m}<\mathrm{5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:{m}>\mathrm{10} \\ $$ Terms of Service Privacy…
Question Number 75435 by Crabby89p13 last updated on 11/Dec/19 $${solve}\:{the}\:{integral}\:{with}\:{Residue}\:{theorem}. \\ $$$$\underset{\mathrm{0}} {\overset{\mathrm{2}\pi} {\int}}\frac{\mathrm{3}\:{d}\theta}{\mathrm{9}\:+\mathrm{sin}^{\mathrm{2}} \theta} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 140971 by bekzodjumayev last updated on 14/May/21 Commented by bekzodjumayev last updated on 14/May/21 $${Please}\:{help}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 9896 by caleb last updated on 13/Jan/17 $${l}^{−\mathrm{1}} \left\{\frac{\mathrm{5}{s}^{\mathrm{2}} −\mathrm{21}{s}+\mathrm{30}}{\left({s}−\mathrm{3}\right)\left({s}^{\mathrm{2}} +\mathrm{4}\right)}\right\}\:\:\:{pls}\:{help}\:{solve}\:{this} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140965 by EnterUsername last updated on 14/May/21 $$\mathrm{If}\:{a}\neq\mathrm{0}\:\mathrm{and}\:{a}\left({l}+{m}\right)^{\mathrm{2}} +\mathrm{2}{blm}+{c}=\mathrm{0}\:\mathrm{and}\:{a}\left({l}+{n}\right)^{\mathrm{2}} + \\ $$$$\mathrm{2}{bln}+{c}=\mathrm{0},\:\mathrm{then} \\ $$$$\left(\mathrm{A}\right)\:{mn}={l}^{\mathrm{2}} +{c}/{a}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:{lm}={n}^{\mathrm{2}} +{c}/{a} \\ $$$$\left(\mathrm{C}\right)\:{ln}={m}^{\mathrm{2}} +{c}/{a}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:{mn}={l}^{\mathrm{2}} +{bc}/{a} \\ $$ Terms…
Question Number 9895 by caleb last updated on 13/Jan/17 $${pls}\:{help}\:{me}\:{solve}\:{dis}\:{questiom}\:{it}\:{is}\: \\ $$$${laplace} \\ $$$$ \\ $$$${l}^{−\mathrm{1}} \left\{\frac{\mathrm{4}{s}^{\mathrm{2}} −\mathrm{17}{s}−\mathrm{24}}{\mathrm{5}\left({s}+\mathrm{3}\right)\left({s}−\mathrm{4}\right)}\right\} \\ $$ Terms of Service Privacy Policy…
Question Number 9894 by caleb last updated on 13/Jan/17 $${pls}\:{help}\:{me}\:{solve}\:{dis}\:{questiom}\:{it}\:{is}\: \\ $$$${laplace} \\ $$$$ \\ $$$${l}^{−\mathrm{1}} \left\{\frac{\mathrm{4}{s}^{\mathrm{2}} −\mathrm{17}{s}−\mathrm{24}}{\mathrm{5}\left({s}+\mathrm{3}\right)\left({s}−\mathrm{4}\right)}\right\} \\ $$ Terms of Service Privacy Policy…
Question Number 9893 by caleb last updated on 13/Jan/17 $${pls}\:{help}\:{me}\:{solve}\:{dis}\:{questiom}\:{it}\:{is}\: \\ $$$${laplace} \\ $$$$ \\ $$$${l}^{−\mathrm{1}} \left\{\frac{\mathrm{4}{s}^{\mathrm{2}} −\mathrm{17}{s}−\mathrm{24}}{\mathrm{5}\left({s}+\mathrm{3}\right)\left({s}−\mathrm{4}\right)}\right\} \\ $$ Terms of Service Privacy Policy…
Question Number 140966 by mnjuly1970 last updated on 14/May/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…….{nice}……{calculus}….. \\ $$$$\:\:\:\:\:{if}\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\sqrt{{cos}\:\left({n}\pi\right)}\:}{\left(\mathrm{2}{n}\right)!!}\:=\:\omega \\ $$$$\:\:\:\:\:\:\:{then}\:\:\:{Re}\left(\omega\right):=?? \\ $$ Answered by Dwaipayan Shikari last updated on…