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Author: Tinku Tara

find-value-in-2-4-13-0-

Question Number 9861 by Raja Naik last updated on 09/Jan/17 $$\mathrm{find}\:\:\lambda\:\mathrm{value}\:\mathrm{in}\:\lambda^{\mathrm{2}} −\mathrm{4}\lambda−\mathrm{13}=\mathrm{0} \\ $$ Answered by FilupSmith last updated on 09/Jan/17 $$\lambda=\frac{\mathrm{4}\pm\sqrt{\mathrm{16}+\mathrm{4}\left(\mathrm{13}\right)}}{\mathrm{2}} \\ $$$$\lambda=\frac{\mathrm{4}\pm\sqrt{\mathrm{68}}}{\mathrm{2}} \\…

0-pi-dx-2-cos-x-

Question Number 140930 by bramlexs22 last updated on 14/May/21 $$\underset{\mathrm{0}} {\overset{\pi} {\int}}\:\frac{\mathrm{dx}}{\:\sqrt{\mathrm{2}}\:−\mathrm{cos}\:\mathrm{x}} \\ $$ Answered by Dwaipayan Shikari last updated on 14/May/21 $$\mathrm{2}\int_{\mathrm{0}} ^{\infty} \frac{{dt}}{\:\sqrt{\mathrm{2}}−\frac{\mathrm{1}−{t}^{\mathrm{2}}…