Question Number 9097 by sandipkd@ last updated on 17/Nov/16 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9096 by tawakalitu last updated on 17/Nov/16 Answered by mrW last updated on 19/Nov/16 $${let}\:{R}_{\mathrm{1}} \:{and}\:{R}_{\mathrm{2}} \:{be}\:{the}\:{rent}\:{of}\:{the}\:{first} \\ $$$${and}\:{second}\:{house}\:{last}\:{year}. \\ $$$$\frac{{R}_{\mathrm{1}} }{{R}_{\mathrm{2}} }=\frac{\mathrm{16}}{\mathrm{23}}…
Question Number 140166 by mathdanisur last updated on 04/May/21 $$\frac{\mathrm{7}−\mathrm{8}\sqrt{\mathrm{7}}{cos}\left(\frac{{arcsin}\left(\frac{\mathrm{3}\sqrt{\mathrm{21}}}{\mathrm{14}}\right)+\mathrm{4}\pi}{\mathrm{3}}\right)}{\mathrm{3}}\:+\:\mathrm{8}{cos}\left(\frac{\mathrm{4}\pi}{\mathrm{7}}\right)=\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 74622 by Raxreedoroid last updated on 27/Nov/19 $$\mathrm{Expand} \\ $$$$\mathrm{1}+\frac{\mathrm{2}}{\mathrm{3}}\centerdot\left(\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\sum}}\left[{cos}\left(\frac{\mathrm{2}\pi}{\mathrm{3}}{x}\right)\right]+\mathrm{2}{n}−\mathrm{2}\right) \\ $$ Commented by Raxreedoroid last updated on 28/Nov/19 $$\mathrm{No}\:\mathrm{its}\:\mathrm{just}\:\mathrm{to}\:\mathrm{clarify}\:\mathrm{whats}\:\mathrm{inside}\:\mathrm{sigma} \\…
Question Number 9087 by sandipkd@ last updated on 17/Nov/16 Commented by 123456 last updated on 17/Nov/16 $$\frac{\partial{w}}{\partial{x}}=\mathrm{4}{cx}+\mathrm{4}+{y} \\ $$$$\frac{\partial{w}}{\partial{y}}=\mathrm{3}{ab}+{x} \\ $$ Terms of Service Privacy…
Question Number 74623 by liki last updated on 27/Nov/19 Commented by liki last updated on 27/Nov/19 $$….\:{I}\:{need}\:{help}\:{plz}… \\ $$ Answered by mr W last updated…
Question Number 9086 by tawakalitu last updated on 17/Nov/16 $$\mathrm{Prove}\:\mathrm{the}\:\mathrm{limit}.,\:\:\:\frac{\mathrm{sin}\left(\theta/\mathrm{2}\right)}{\left(\theta/\mathrm{2}\right)}\:=\:\mathrm{1} \\ $$ Commented by 123456 last updated on 17/Nov/16 $$\underset{\theta\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sin}\:\theta/\mathrm{2}}{\theta/\mathrm{2}}=\underset{\alpha\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sin}\:\alpha}{\alpha} \\ $$$$\alpha=\theta/\mathrm{2} \\…
Question Number 74620 by aliesam last updated on 27/Nov/19 Answered by mind is power last updated on 27/Nov/19 $$\mathrm{tchek}\:\mathrm{it}\:\mathrm{sir} \\ $$$$\mathrm{ther}\:\mathrm{is}\:\mathrm{somme} \\ $$$$\mathrm{problems}\:\:\:\:\mathrm{ln}\left(\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}{\mid\mathrm{cos}\left(\mathrm{x}\right)\mid}\right) \\…
Question Number 9085 by tawakalitu last updated on 17/Nov/16 Answered by mrW last updated on 17/Nov/16 $${x}^{\mathrm{2}} +\left(\mathrm{2}\frac{\mathrm{1}}{\mathrm{8}}−{x}\right)^{\mathrm{2}} =\left(\mathrm{1}\frac{\mathrm{5}}{\mathrm{8}}\right)^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} +\left(\frac{\mathrm{17}}{\mathrm{8}}−{x}\right)^{\mathrm{2}} −\left(\frac{\mathrm{13}}{\mathrm{8}}\right)^{\mathrm{2}} =\mathrm{0} \\…
Question Number 74621 by aliesam last updated on 27/Nov/19 Commented by mathmax by abdo last updated on 28/Nov/19 $${changement}\:{x}={a}\:{sh}\left({t}\right)\:\Rightarrow\int\sqrt{{x}^{\mathrm{2}} \:+{a}^{\mathrm{2}} }{dx}\:=\int\:{ach}\left({t}\right){a}\:{cht}\:{dt} \\ $$$$={a}^{\mathrm{2}} \:\int\:{ch}^{\mathrm{2}} \left({t}\right){dt}\:=\frac{{a}^{\mathrm{2}}…