Question Number 74559 by lalitchand last updated on 26/Nov/19 $$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{N}\:\mathrm{Arithmetic}\:\mathrm{means}\:\mathrm{between}\:\mathrm{two}\:\mathrm{numbers} \\ $$$$\mathrm{is}\:\mathrm{20}.\:\mathrm{If}\:\mathrm{last}\:\mathrm{mean}\:\mathrm{is}\:\mathrm{double}\:\mathrm{of}\:\mathrm{1st}\:\mathrm{mean} \\ $$$$\mathrm{and}\:\mathrm{one}\:\mathrm{is}\:\mathrm{three}\:\mathrm{times}\:\mathrm{the}\:\mathrm{another}\:\mathrm{number}.\: \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{numbers} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9021 by tawakalitu last updated on 14/Nov/16 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{when}\: \\ $$$$\left(\mathrm{13}^{\mathrm{5}} \:+\:\mathrm{14}^{\mathrm{5}} \:+\:\mathrm{15}^{\mathrm{5}} \:+\:\mathrm{16}^{\mathrm{5}} \right)\:\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{29}\:?\: \\ $$ Answered by aydnmustafa1976 last updated on 14/Nov/16…
Question Number 74557 by ajfour last updated on 26/Nov/19 Commented by ajfour last updated on 26/Nov/19 $${In}\:{a}\:{fixed}\:{frictionless}\:{crucible} \\ $$$${in}\:{the}\:{form}\:{of}\:{hollow}\:{hemisphere}, \\ $$$${radius}\:{R},\:{a}\:{small}\:{mass}\:{m}\:{is}\: \\ $$$$\:{released}\:{with}\:{a}\:{string}\:\left({length}\right. \\ $$$$\left.\:{b}\:<\:\sqrt{\mathrm{2}}\:{R}\:\right)\:{attaching}\:{it}\:{to}\:{a}\:{point}…
Question Number 9020 by tawakalitu last updated on 14/Nov/16 Commented by RasheedSoomro last updated on 20/Nov/16 $$\mathrm{By}\:\left[\frac{\mathrm{ax}^{\mathrm{2}} +\mathrm{bx}+\mathrm{c}}{\mathrm{2x}+\mathrm{b}}\right]\:\mathrm{do}\:\mathrm{you}\:\mathrm{mean}\:\mathrm{bracket}\:\mathrm{function}? \\ $$ Answered by Rasheed Soomro last…
Question Number 140089 by otchereabdullai@gmail.com last updated on 04/May/21 $$\mathrm{Given}\:\mathrm{that}\:\mathrm{log}_{\mathrm{4}} \left(\mathrm{y}−\mathrm{1}\right)+\mathrm{log}_{\mathrm{4}} \left(\frac{\mathrm{x}}{\mathrm{y}}\right)=\mathrm{k} \\ $$$$\mathrm{and}\:\mathrm{log}_{\mathrm{2}} \left(\mathrm{y}+\mathrm{1}\right)−\mathrm{log}_{\mathrm{2}} \mathrm{x}=\mathrm{k}−\mathrm{1} \\ $$$$\mathrm{Show}\:\mathrm{that}\:\mathrm{y}^{\mathrm{2}} =\mathrm{1}+\mathrm{8}^{\mathrm{k}} \\ $$$$\mathrm{Hence}\:\mathrm{deduce}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{y}\:\mathrm{and}\:\mathrm{x}\: \\ $$$$\mathrm{when}\:\mathrm{k}=\mathrm{1} \\ $$…
Question Number 74554 by shubham90412@gmail.com last updated on 26/Nov/19 $$\boldsymbol{{Find}}\:\boldsymbol{{the}}\:\boldsymbol{{superimum}}\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{set}}\:\left\{\frac{\boldsymbol{{n}}^{\mathrm{2}} }{\mathrm{2}^{\boldsymbol{{n}}} }\right\} \\ $$ Answered by MJS last updated on 26/Nov/19 $$\mathrm{trying} \\ $$$${S}=\left\{\mathrm{0},\:\frac{\mathrm{1}}{\mathrm{2}},\:\mathrm{1},\:\frac{\mathrm{9}}{\mathrm{8}},\:\mathrm{1},\:\frac{\mathrm{25}}{\mathrm{32}},\:\frac{\mathrm{9}}{\mathrm{16}},\:…\right\} \\…
Question Number 9019 by tawakalitu last updated on 14/Nov/16 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 74555 by necxxx last updated on 26/Nov/19 $${Good}\:{day}\:{friends}.{I}\:{saw}\:{a}\:{post}\:{on}\:{a} \\ $$$${group}\:{chat}\:{where}\:{someone}\:{said}\:{he}\:{needs} \\ $$$${help}\:{on}\:{functional}\:{iteration}.\:{He}\:{said} \\ $$$${he}\:{needs}\:{some}\:{solvings}\:{with}\:{overleaf} \\ $$$${and}\:{also}\:{to}\:{play}\:{the}\:{report}\:{on}\:{latex}.{He}\:{is} \\ $$$${highly}\:{willing}\:{to}\:{pay}\:{so}\:{I}\:{thought}\:{to}\:{myself} \\ $$$${to}\:{post}\:{it}\:{here}\:{just}\:{incase}\:{there}'{s} \\ $$$${someone}\:{that}\:{can}\:{pick}\:{up}\:{the}\:{offer}. \\…
Question Number 140090 by mathdanisur last updated on 04/May/21 $$\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{1}} }+\frac{\mathrm{3}}{\mathrm{2}^{\mathrm{3}} }+\frac{\mathrm{5}}{\mathrm{2}^{\mathrm{5}} }+\frac{\mathrm{7}}{\mathrm{2}^{\mathrm{7}} }+..=? \\ $$ Answered by qaz last updated on 04/May/21 $${S}=\underset{{n}=\mathrm{0}} {\overset{\infty}…
Question Number 9016 by Nicolly321 last updated on 13/Nov/16 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com