Question Number 204313 by serenity last updated on 12/Feb/24 $${lim}\frac{\mathrm{3}×^{\mathrm{2}} −\mathrm{8}×−\mathrm{16}}{\mathrm{2}×^{\mathrm{2}} \mathrm{9}×+\mathrm{4}} \\ $$$$ \\ $$ Answered by Faetmaaa last updated on 27/Feb/24 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{3}{x}^{\mathrm{2}}…
Question Number 204310 by BaliramKumar last updated on 12/Feb/24 Answered by mr W last updated on 12/Feb/24 Commented by mr W last updated on 12/Feb/24…
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Question Number 204300 by depressiveshrek last updated on 11/Feb/24 $${x}^{\mathrm{2}} \mathrm{log}_{\mathrm{3}} {x}^{\mathrm{2}} −\left(\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}\right)\mathrm{log}_{\mathrm{9}} \left(\mathrm{2}{x}+\mathrm{3}\right)=\mathrm{3log}_{\mathrm{3}} \left(\frac{{x}}{\mathrm{2}{x}+\mathrm{3}}\right) \\ $$ Answered by Rasheed.Sindhi last updated on 11/Feb/24…
Question Number 204302 by MASANJAJJ last updated on 11/Feb/24 Answered by Frix last updated on 11/Feb/24 $$\mathrm{Cuboid}\:\mathrm{length}={l}\:\mathrm{width}={w}\:\mathrm{height}={h} \\ $$$$\mathrm{Floor}\:\left(=\mathrm{ceiling}\right)\:={lw} \\ $$$$\mathrm{Lateral}\:\mathrm{surface}\:=\mathrm{2}{h}\left({l}+{w}\right) \\ $$ Terms of…
Question Number 204303 by MASANJAJJ last updated on 11/Feb/24 Answered by SWPlaysMC last updated on 12/Feb/24 $$\mathrm{Duplicate}\:\mathrm{of}\:\mathrm{Q204302} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 204293 by depressiveshrek last updated on 11/Feb/24 $$\mathrm{Prove}\:\mathrm{the}\:\mathrm{following}\:\mathrm{trig}\:\mathrm{identity}: \\ $$$$\frac{\mathrm{2sin}\alpha+\mathrm{sin3}\alpha+\mathrm{sin5}\alpha}{\mathrm{cos}\alpha−\mathrm{2cos2}\alpha+\mathrm{cos3}\alpha}=\frac{\mathrm{2cos2}\alpha}{\mathrm{tan}\frac{\alpha}{\mathrm{2}}} \\ $$ Commented by Frix last updated on 11/Feb/24 $$\mathrm{Try}. \\ $$$$\alpha=\frac{\pi}{\mathrm{6}}\:\Rightarrow\:\mathrm{lhs}=−\mathrm{5}\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)\:\:\:\:\:\mathrm{rhs}=\mathrm{2}+\sqrt{\mathrm{3}} \\…
Question Number 204278 by liuxinnan last updated on 11/Feb/24 $$\mathrm{cos}\:{x}+\mathrm{cos}\:\mathrm{3}{x}+\mathrm{cos}\:\mathrm{5}{x}=\sqrt{\mathrm{2}}+\mathrm{1} \\ $$$$\mathrm{sin}\:{x}+\mathrm{sin3}{x}+\:\mathrm{sin}\:\mathrm{5}{x}=\mathrm{1} \\ $$$$\mathrm{tan}\:\mathrm{3}{x}=? \\ $$ Commented by mr W last updated on 11/Feb/24 $${eq}.\left({i}\right)\:{and}\:{eq}.\left({ii}\right)\:{are}\:{not}\:{consistent}.…