Question Number 73679 by Tinku Tara last updated on 14/Nov/19 $$\mathrm{We}\:\mathrm{have}\:\mathrm{updated}\:\mathrm{backend}\:\mathrm{code}\:\mathrm{to}\: \\ $$$$\mathrm{disallow}\:\mathrm{delete}\:\mathrm{of}\:\mathrm{question}\:\mathrm{which}\:\mathrm{are} \\ $$$$\mathrm{already}\:\mathrm{answered}\:\mathrm{or}\:\mathrm{commented}. \\ $$$$ \\ $$ Commented by malwaan last updated on…
Question Number 8139 by sou1618 last updated on 01/Oct/16 $${is}\:{it}\:{correct}? \\ $$$${when} \\ $$$${S}_{{n}} =\left\{\right. \\ $$$$\mathrm{1}×\mathrm{2}+\mathrm{1}×\mathrm{3}+\mathrm{1}×\mathrm{4}+\mathrm{1}×\mathrm{5}+…….+\mathrm{1}×{n} \\ $$$$\:\:\:\:\:\:\:\:\:\:+\mathrm{2}×\mathrm{3}+\mathrm{2}×\mathrm{4}+\mathrm{2}×\mathrm{5}+…….+\mathrm{2}×{n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+\mathrm{3}×\mathrm{4}+\mathrm{3}×\mathrm{5}+…….+\mathrm{3}×{n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+\mathrm{4}×\mathrm{5}+…….+\mathrm{4}×{n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:….…
Question Number 73673 by ajfour last updated on 14/Nov/19 Commented by ajfour last updated on 14/Nov/19 $${Q}\:\mathrm{73503}\:\:\:\left({another}\:{way}\:\:{a}\:{try}..\right) \\ $$ Commented by ajfour last updated on…
Question Number 73671 by Tanmay chaudhury last updated on 14/Nov/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 8134 by 314159 last updated on 01/Oct/16 Answered by prakash jain last updated on 01/Oct/16 $$\mathrm{See}\:\mathrm{question}\:\mathrm{8025}. \\ $$ Terms of Service Privacy Policy…
Question Number 73668 by liki last updated on 14/Nov/19 $$\:{Qn}\:.\:\int\left({e}^{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{6}} \right){dx} \\ $$$$\:…\:{I}\:{need}\:{help}\:{plz}.. \\ $$$$ \\ $$$$ \\ $$ Answered by arkanmath7@gmail.com last updated…
Question Number 8130 by tawakalitu last updated on 01/Oct/16 $${It}\:{is}\:{desired}\:{to}\:{set}\:{the}\:{operating}\:{point}\:{at}\:\mathrm{3}.\mathrm{5}{V},\: \\ $$$$\mathrm{2}.\mathrm{2}{mA}\:{by}\:{biasing}\:{a}\:{silicon}\:{transistor}\:{with}\: \\ $$$$\left.{feedback}\:{resistor}\right).\:{if}\:\:{Beta}\:=\:\mathrm{100},\:{find}\:{the}\:{value} \\ $$$${of}\:{R}_{{b}} \:{and}\:{R}_{{c}} \:\:{taking}\:\:{V}_{{be}} \:=\:\mathrm{0}.\mathrm{7}{V} \\ $$ Terms of Service Privacy…
Question Number 8129 by Apoorva22 last updated on 01/Oct/16 $${An}\:{ellipse}\:{having}\:{focii}\:{at}\:\left(\mathrm{3}\:\mathrm{3}\right){and}\:\left(−\mathrm{4}\:\mathrm{4}\right)\:{and}\:{passing}\:{through}\:{origin}\:{has}\:{e}?? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73665 by aliesam last updated on 14/Nov/19 $${if} \\ $$$$ \\ $$$${cos}^{\mathrm{2}} \left(\theta\right)=\frac{{m}^{\mathrm{2}} −\mathrm{1}}{\mathrm{3}}\:\:,\:\:{tan}^{\mathrm{3}} \left(\frac{\theta}{\mathrm{2}}\right)={tan}\left({a}\right) \\ $$$$ \\ $$$${prove}\:{that} \\ $$$$ \\ $$$$\sqrt[{\mathrm{3}}]{{cos}^{\mathrm{2}}…
Question Number 8127 by Yozzia last updated on 30/Sep/16 $${For}\:\mid{x}\mid<\mathrm{1},\:{we}\:{have}\:{that} \\ $$$$\left(\mathrm{1}+{x}\right)^{\mathrm{1}/\mathrm{2}} =\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}{x}+\frac{\left(\frac{\mathrm{1}}{\mathrm{2}}\right)\left(\frac{\mathrm{1}}{\mathrm{2}}−\mathrm{1}\right)}{\mathrm{2}!}{x}^{\mathrm{2}} +\frac{\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{2}}−\mathrm{1}\right)\left(\frac{\mathrm{1}}{\mathrm{2}}−\mathrm{2}\right)}{\mathrm{3}!}{x}^{\mathrm{3}} +… \\ $$$$\left(\mathrm{1}+{x}\right)^{\mathrm{1}/\mathrm{2}} =\mathrm{1}+\underset{{r}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\underset{{k}=\mathrm{0}} {\overset{{r}−\mathrm{1}} {\prod}}\left(\mathrm{0}.\mathrm{5}−{k}\right)}{{r}!}{x}^{{r}} . \\ $$$${Let}\:{g}\left({r}\right)=\underset{{k}=\mathrm{0}}…