Question Number 8070 by FilupSmith last updated on 29/Sep/16 $$\mathrm{a}\:\mathrm{line}\:{L}\:\mathrm{intersec}{ts}\:\left(\mathrm{0},\:\mathrm{0}\right)\:{and}\:{the}\:{curve} \\ $$$${y}={x}^{\mathrm{2}} \:\:\:{at}\:{x}={t}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{line}? \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{area}\:\mathrm{between}\:{L}\:\mathrm{and}\:{y}\:\mathrm{from} \\ $$$${x}=\mathrm{0}\:\mathrm{to}\:{x}={t}? \\ $$ Answered by sandy_suhendra last…
Question Number 8066 by Chantria last updated on 29/Sep/16 $${calculate}\: \\ $$$$\:\underset{{n}\rightarrow\infty} {{lim}}\frac{{n}}{\mathrm{2}^{\sqrt{{n}}} } \\ $$$$ \\ $$ Answered by prakash jain last updated on…
Question Number 73595 by mr W last updated on 13/Nov/19 $${i}\:{ask}\:{all}\:{of}\:{you}\:{not}\:{to}\:{answer}\:{any} \\ $$$${question}\:{from}\:{www} \\ $$$$\left(\:=\:{amirley}\:{or}\:{something}\:{like}\:{this}\right) \\ $$$$\left(=\:{best}\right) \\ $$$$\left(={azodbek}\:{or}\:{something}\:{like}\:{this}\right) \\ $$$${this}\:{guy}\:{is}\:{not}\:{to}\:{help}!\:{he}\:{misuses} \\ $$$${your}\:{help}\:{and}\:{deletes}\:{his}\:{posts}\:{as} \\ $$$${soon}\:{as}\:{you}\:{have}\:{answered}\:{them}.…
Question Number 73590 by mhmd last updated on 13/Nov/19 $${prove}\:{that}\:\left(_{{k}} ^{{n}+\mathrm{1}} \right)=\left(_{{k}} ^{{n}} \right)+\left(_{{n}−\mathrm{1}} ^{{n}} \right) \\ $$$${pleas}\:{sir}\:{help}\:{me}\:? \\ $$ Commented by Cmr 237 last…
Question Number 139124 by 7770 last updated on 22/Apr/21 $${x}^{\mathrm{2}} +{x}−\mathrm{2}\sqrt{{x}}=\mathrm{36} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by MJS_new last updated on 22/Apr/21 $$\mathrm{you}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate}.\:\mathrm{I}\:\mathrm{get} \\ $$$${x}\approx\mathrm{5}.\mathrm{91193369}…
Question Number 139123 by dayladau1234 last updated on 22/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73582 by arkanmath7@gmail.com last updated on 13/Nov/19 $${Could}\:{you}\:{help}\:{me}\:{with}\:{references} \\ $$$${in}\:{complex}\:{analysis}\:{please}? \\ $$ Commented by mathmax by abdo last updated on 14/Nov/19 $${search}\:{vuibert}\:{and}\:{ellipse}\:{collection}…. \\…
Question Number 139116 by EnterUsername last updated on 22/Apr/21 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{solutions}\:\mathrm{to}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{z}\overline {\left(\mathrm{z}−\mathrm{2i}\right)}=\mathrm{2}\left(\mathrm{z}+\mathrm{i}\right)\:\mathrm{is}\:? \\ $$ Answered by qaz last updated on 22/Apr/21 $${z}\centerdot\overline {{z}−\mathrm{2}{i}}={z}\overset{−} {{z}}+{z}\overline…
Question Number 139118 by EnterUsername last updated on 22/Apr/21 $$\mathrm{Let}\:{z}\:\mathrm{be}\:\mathrm{a}\:\mathrm{complex}\:\mathrm{number}.\:\mathrm{If}\:\mid{z}+\mathrm{1}\mid=\mid{z}−\mathrm{1}\mid \\ $$$$\mathrm{and}\:\mathrm{arg}\left(\frac{{z}−\mathrm{1}}{{z}+\mathrm{1}}\right)=\frac{\pi}{\mathrm{4}}.\:\mathrm{Then}\:{z}\:\mathrm{is}\:?\: \\ $$ Answered by qaz last updated on 22/Apr/21 $$\mid{z}+\mathrm{1}\mid=\mid{z}−\mathrm{1}\mid \\ $$$$\Rightarrow{z}={a}+{bi}={bi} \\…
Question Number 139113 by mathdanisur last updated on 22/Apr/21 $${if},\:{x}=\mathrm{3}+\sqrt{\mathrm{7}} \\ $$$${find},\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{8}{x}^{\mathrm{2}} −\mathrm{1}}} \\ $$ Answered by MJS_new last updated on 22/Apr/21 $$\frac{\mathrm{1}}{\:\sqrt{\mathrm{8}{x}^{\mathrm{2}} −\mathrm{1}}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{127}+\mathrm{48}\sqrt{\mathrm{7}}}}=\sqrt{\mathrm{127}−\mathrm{48}\sqrt{\mathrm{7}}} \\…