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Author: Tinku Tara

Question-73255

Question Number 73255 by TawaTawa last updated on 09/Nov/19 Answered by mr W last updated on 09/Nov/19 $${there}\:{is}\:{no}\:{support}\:{on}\:{the}\:{right}\:{end} \\ $$$${of}\:{the}\:{beam}! \\ $$$$ \\ $$$$\mathrm{0}.\mathrm{4}{L}×{R}_{{Mid}} −\mathrm{0}.\mathrm{2}{L}×\mathrm{0}.\mathrm{6}{W}−\mathrm{0}.\mathrm{8}{L}×\mathrm{0}.\mathrm{15}{W}=\mathrm{0}…

Question-73251

Question Number 73251 by aliesam last updated on 09/Nov/19 Answered by mind is power last updated on 09/Nov/19 $$\mathrm{E}\left(\mathrm{u}_{\mathrm{n}} \right)\leqslant\mathrm{u}_{\mathrm{n}} <\mathrm{E}\left(\mathrm{u}_{\mathrm{n}} \right)+\mathrm{1}=\mathrm{U}_{\mathrm{n}+\mathrm{1}} \\ $$$$\Rightarrow\mathrm{U}_{\mathrm{n}} \mathrm{is}\:\mathrm{a}\:\mathrm{creasing}\:\mathrm{squances}…

2x-y-z-8-equation-i-x-2-y-2-2z-2-14-equation-ii-3x-3-4y-3-z-3-195-equation-iii-Solve-simultaneously-

Question Number 7713 by Tawakalitu. last updated on 11/Sep/16 $$\mathrm{2}{x}\:+\:{y}−\:{z}\:=\:\mathrm{8}\:\:\:\:……….\:{equation}\:\left({i}\right) \\ $$$${x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:+\:\mathrm{2}{z}^{\mathrm{2}} \:=\:\mathrm{14}\:\:\:\:……….\:{equation}\:\left({ii}\right) \\ $$$$\mathrm{3}{x}^{\mathrm{3}} \:+\:\mathrm{4}{y}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:=\:\mathrm{195}\:\:\:\:………\:{equation}\:\left({iii}\right) \\ $$$$ \\ $$$${Solve}\:{simultaneously}. \\…