Question Number 7562 by Master Moon last updated on 03/Sep/16 $$\left({U}_{{n}} \right)=\:\mathrm{2},\mathrm{3},\mathrm{5},\mathrm{6},\mathrm{7},\mathrm{8},\mathrm{10},\mathrm{11},\mathrm{12},\mathrm{13},\mathrm{14},…. \\ $$$${find}\:{U}_{{n}} \\ $$ Commented by Rasheed Soomro last updated on 03/Sep/16 $${Perfect}\:{square}\:{numbers}\:{have}\:\:{been}\:{excluded}\:{from}…
Question Number 138628 by mohammad17 last updated on 15/Apr/21 $${find}\:{the}\:{region}\:{in}\:{which}\:{the}\:{function}\: \\ $$$$ \\ $$$${f}\left({z}\right)=\frac{{log}\left({z}−\mathrm{2}{i}\right)}{{z}^{\mathrm{2}} +\mathrm{1}}\:{is}\:{analytic}\:? \\ $$$$ \\ $$$${help}\:{me}\:{sir}\: \\ $$ Commented by mohammad17 last…
Question Number 138631 by physicstutes last updated on 15/Apr/21 Commented by physicstutes last updated on 15/Apr/21 $$\mathrm{From}\:\mathrm{the}\:\mathrm{figure}\:\mathrm{above}\:\mathrm{show}\:\mathrm{completely}\:\mathrm{how}\:\mathrm{the}\:\mathrm{force}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{pulley}\:\mathrm{can}\:\mathrm{be}\:\mathrm{obtained}. \\ $$ Commented by Dwaipayan Shikari…
Question Number 73090 by ajfour last updated on 06/Nov/19 Commented by ajfour last updated on 06/Nov/19 $${Find}\:{x}\left({t}\right),\:\:{x}\left(\mathrm{0}\right)={a}\:,\:\omega_{\mathrm{0}} =\mathrm{0},\: \\ $$$$\alpha\:{is}\:{constant}. \\ $$ Answered by mr…
Question Number 138624 by Dwaipayan Shikari last updated on 15/Apr/21 $$\frac{\mathrm{1}^{\pi} }{\mathrm{3}!}+\frac{\mathrm{2}^{\pi} }{\mathrm{5}!}+\frac{\mathrm{3}^{\pi} }{\mathrm{7}!}+\frac{\mathrm{4}^{\pi} }{\mathrm{9}!}+\frac{\mathrm{5}^{\pi} }{\mathrm{11}!}+… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138627 by KwesiDerek last updated on 15/Apr/21 $$\boldsymbol{\mathrm{x}}^{\mathrm{2}} =\mathrm{16}^{\boldsymbol{\mathrm{x}}} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Commented by soudo last updated on 15/Apr/21 $$\mathrm{nice} \\ $$…
Question Number 7552 by Master Moon last updated on 03/Sep/16 $$\sqrt{\mathrm{4}}+\mathrm{5}\:= \\ $$ Answered by FilupSmith last updated on 03/Sep/16 $$\sqrt{\mathrm{4}}=\pm\mathrm{2} \\ $$$$\therefore\sqrt{\mathrm{4}}+\mathrm{5}=\mathrm{5}\pm\mathrm{2}=\mathrm{3},\:\mathrm{7} \\ $$…
Question Number 138621 by mnjuly1970 last updated on 15/Apr/21 Answered by Dwaipayan Shikari last updated on 15/Apr/21 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\Gamma^{\mathrm{2}} \left({n}+\mathrm{1}\right)}{\Gamma\left(\mathrm{2}{n}+\mathrm{2}\right)}=\int_{\mathrm{0}} ^{\mathrm{1}} \Sigma{x}^{{n}} \left(\mathrm{1}−{x}\right)^{{n}} {dx}…
Question Number 73084 by rajesh4661kumar@gmail.com last updated on 06/Nov/19 Answered by Tanmay chaudhury last updated on 06/Nov/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138619 by Dwaipayan Shikari last updated on 15/Apr/21 $$\int_{\mathrm{0}} ^{\infty} \left({e}^{−{x}^{\sqrt{\mathrm{3}}} } −\frac{\mathrm{1}}{\left(\mathrm{1}+{x}^{\sqrt{\mathrm{3}}} \right)^{\sqrt{\mathrm{3}}} }\right)\frac{{dx}}{{x}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\psi\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right) \\ $$ Commented by mnjuly1970 last updated on…