Question Number 138209 by 676597498 last updated on 11/Apr/21 $${I}_{{n}} =\int_{\mathrm{0}} ^{\:\mathrm{1}} {x}^{{n}} \sqrt{{x}^{\mathrm{2}} +\mathrm{1}}{dx} \\ $$$${find}\:{reduction}\:{formula} \\ $$ Commented by Dwaipayan Shikari last updated…
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Question Number 7138 by Tawakalitu. last updated on 12/Aug/16 Answered by Yozzii last updated on 13/Aug/16 $${x}^{{x}^{\mathrm{2}} } =\mathrm{3}\:\:\left({x}>\mathrm{0}\right) \\ $$$${Let}\:{x}^{\mathrm{2}} ={e}^{{k}} \Rightarrow{x}={e}^{{k}/\mathrm{2}} \\ $$$$\therefore{e}^{\left({k}/\mathrm{2}\right){e}^{{k}}…
Question Number 72672 by mr W last updated on 31/Oct/19 Commented by mr W last updated on 31/Oct/19 $${find}\:{u}_{{min}} \:{for}\:{the}\:{stone}\:{to}\:{hit}\:{the} \\ $$$${ground}\:{behind}\:{the}\:{sphere}. \\ $$$$\left({see}\:{also}\:{Q}\mathrm{72563},\:{with}\:{thanks}\:{to}\:\right. \\…
Question Number 138205 by Bekzod Jumayev last updated on 11/Apr/21 Commented by Jamshidbek last updated on 11/Apr/21 $$\mathrm{Og}'\mathrm{ayni}\:\mathrm{kun}\:\mathrm{savolini}\:\mathrm{oziz}\:\mathrm{yechmasizmi}? \\ $$$$\mathrm{Yoki}\:\mathrm{kechqurun}\:\mathrm{kanalga}\:\mathrm{tashlanadiku}\:\mathrm{yechim}.\mathrm{O}'\mathrm{shanda} \\ $$$$\mathrm{o}'\mathrm{rganib}\:\mathrm{olardizda} \\ $$ Commented…
Question Number 7135 by Master Moon last updated on 12/Aug/16 $$\boldsymbol{\mathrm{Prove}}\:\boldsymbol{\mathrm{that}} \\ $$$$\:\frac{\mathrm{3}}{\:\sqrt[{\mathrm{5}}]{\mathrm{2}}+\sqrt[{\mathrm{5}}]{\mathrm{3}}+\sqrt[{\mathrm{5}}]{\mathrm{5}}}\:>\:\frac{\sqrt[{\mathrm{4}}]{\mathrm{2}}+\sqrt[{\mathrm{4}}]{\mathrm{3}}+\sqrt[{\mathrm{4}}]{\mathrm{5}}}{\left(\sqrt{\mathrm{2}}+\sqrt{\mathrm{3}}+\sqrt{\mathrm{5}}\right)\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}+\sqrt[{\mathrm{3}}]{\mathrm{3}}+\sqrt[{\mathrm{3}}]{\mathrm{5}}\right)} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:{How}\:{to}\:{prove}\:{it}\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 72671 by aliesam last updated on 31/Oct/19 Commented by kaivan.ahmadi last updated on 31/Oct/19 $$\left.{a}\right) \\ $$$$\mid{x}_{{n}+\mathrm{1}} −{x}_{{n}} \mid\leqslant{c}\mid{x}_{{n}} −{x}_{{n}−\mathrm{1}} \mid\leqslant{c}^{\mathrm{2}} \mid{x}_{{n}−\mathrm{1}} −{x}_{{n}−\mathrm{2}}…
Question Number 72668 by aliesam last updated on 31/Oct/19 Answered by mind is power last updated on 01/Nov/19 $$\theta=\mathrm{DAB}? \\ $$$$ \\ $$ Terms of…
Question Number 138206 by Bekzod Jumayev last updated on 11/Apr/21 Commented by Bekzod Jumayev last updated on 11/Apr/21 $${Help}? \\ $$ Answered by mr W…
Question Number 72666 by aliesam last updated on 31/Oct/19 Answered by mind is power last updated on 31/Oct/19 $$\mathrm{let}\:\alpha=\angle\mathrm{CDA}=\mathrm{BAE}\:\:,\mathrm{OCA}=\mathrm{2}\alpha \\ $$$$\mathrm{E}=\left(\mathrm{AD}\right)\cap\mathrm{BC} \\ $$$$\frac{\mathrm{3}}{\mathrm{5}}=\frac{\mathrm{BE}}{\mathrm{EC}},\mathrm{BE}+\mathrm{EC}=\mathrm{4} \\ $$$$\Rightarrow\mathrm{BE}=\frac{\mathrm{3}}{\mathrm{2}}…