Question Number 72495 by Tony Lin last updated on 29/Oct/19 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\frac{{lnx}}{{x}}\right)^{\frac{{lnx}}{{x}}} =? \\ $$ Commented by mathmax by abdo last updated on 29/Oct/19 $${let}\:{f}\left({x}\right)=\left(\frac{{lnx}}{{x}}\right)^{\frac{{lnx}}{{x}}}…
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Question Number 72492 by petrochengula last updated on 29/Oct/19 $$\frac{\mathrm{1}}{\mathrm{cosx}}+\frac{\mathrm{1}}{\mathrm{sinx}}=\mathrm{8} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$ Commented by petrochengula last updated on 29/Oct/19 $$\mathrm{help}\:\mathrm{please} \\ $$ Answered…
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Question Number 138024 by Algoritm last updated on 09/Apr/21 Answered by TheSupreme last updated on 09/Apr/21 $${e}^{{x}} ={u} \\ $$$${dx}=\frac{\mathrm{1}}{{u}}{du} \\ $$$$\int\sqrt{{u}^{\mathrm{2}} +\mathrm{4}{u}−\mathrm{1}}\frac{{du}}{{u}} \\ $$$$\left({u}+\mathrm{2}\right)={z}…
Question Number 72488 by aliesam last updated on 29/Oct/19 $$\begin{cases}{\mathrm{4}{xy}=\mathrm{1}}\\{\mathrm{4}\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }\:\left(\:{y}−\sqrt{\mathrm{1}−{y}^{\mathrm{2}} }\:\right)=\mathrm{1}}\end{cases} \\ $$$$ \\ $$$${Resolver}\:{elsistema}\:{en}\:{R} \\ $$ Answered by behi83417@gmail.com last updated on 30/Oct/19…
Question Number 138026 by mnjuly1970 last updated on 09/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:………{nice}\:\:…\:…\:…\:{calculus}……….. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\Theta=\:\underset{\overset{{n}=\mathrm{1}} {\:}} {\overset{\infty} {\sum}}\left(\frac{{n}^{\mathrm{2}} }{{n}!.\mathrm{4}^{{n}} }\right)\:=?? \\ $$ Answered by Dwaipayan Shikari last updated…
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Question Number 6947 by Tawakalitu. last updated on 03/Aug/16 $${Prove}\:{that}\: \\ $$$$ \\ $$$$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\left\{\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\frac{{x}\:−\:{y}}{\left({x}\:+\:{y}\right)^{\mathrm{3}} }\:\:{dy}\right\}\:{dx}\:\:\:=\:\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Answered by Yozzii last…
Question Number 72483 by TawaTawa last updated on 29/Oct/19 $$\underset{\mathrm{k}\:=\:\mathrm{0}} {\overset{\mathrm{n}} {\sum}}\:\mathrm{cos}\left(\mathrm{a}\:+\:\mathrm{kb}\right) \\ $$ Answered by Tanmay chaudhury last updated on 29/Oct/19 $${T}_{{k}} ={cos}\left({a}+{kb}\right) \\…