Question Number 137732 by byaw last updated on 05/Apr/21 $$\mathrm{the}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{the}\:\mathrm{interior}\:\mathrm{angle} \\ $$$$\mathrm{to}\:\mathrm{the}\:\mathrm{exterior}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{a} \\ $$$$\mathrm{regular}\:\mathrm{polygon}\:\mathrm{is}\:\mathrm{5}:\mathrm{2}.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{polygon}. \\ $$ Answered by mr W last…
Question Number 6661 by Tawakalitu. last updated on 09/Jul/16 $${Solve}\:{this}\:{equation}\:{by}\:{reducing}\:{it}\:{from}\:{non}\:{homogeneous} \\ $$$${equation}\:{to}\:{homogeneous}\:{equation} \\ $$$$\frac{{dy}}{{dx}}\:=\:\frac{\mathrm{2}\left({x}\:+\:{y}\:−\:\mathrm{1}\right)}{\mathrm{3}{x}\:+\:{y}\:+\:\mathrm{1}} \\ $$$$ \\ $$$${Please}\:{help}\:{with}\:{this}\:{one}\:{too}. \\ $$$${i}\:{was}\:{trying}\:{your}\:{approah}\:{but}\:{not}\:{the}\:{same} \\ $$$$ \\ $$$${thanks}\:{for}\:{your}\:{help}. \\…
Question Number 72194 by mr W last updated on 26/Oct/19 Commented by mr W last updated on 26/Oct/19 $${find}\:{the}\:{sum}\:{of}\:{areas}\:{of}\:{two}\:{squares} \\ $$$${inside}\:{the}\:{semicircle}\:{with}\:{radius}\:\mathrm{10}. \\ $$ Answered by…
Question Number 72190 by oyemi kemewari last updated on 26/Oct/19 $$\mathrm{3}^{\mathrm{x}} +\mathrm{4}^{\mathrm{x}} =\mathrm{5}^{\mathrm{x}} \\ $$ Commented by oyemi kemewari last updated on 26/Oct/19 find x Commented…
Question Number 6655 by Tawakalitu. last updated on 09/Jul/16 $${If}\:\:\:{tan}\mathrm{2}{x}\:−\:{sin}\mathrm{2}{x}\:=\:{b}\:\:{and}\:\:{tan}\mathrm{2}{x}\:+\:{sin}\mathrm{2}{x}\:=\:{a} \\ $$$${prove}\:{that}\::\: \\ $$$${b}^{\mathrm{2}} \:−\:{a}^{\mathrm{2}\:} \:=\:\mathrm{16}{ba} \\ $$ Commented by Yozzii last updated on 09/Jul/16…
Question Number 137721 by Ñï= last updated on 05/Apr/21 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{2}{n}^{\mathrm{2}} }=? \\ $$$${except}\:{use}\:\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{2}{n}^{\mathrm{2}} }=\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{2}{n}−\mathrm{1}}−\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{1}},{any}\:{other}\:{way}? \\ $$ Answered by TANMAY…
Question Number 6651 by Tawakalitu. last updated on 08/Jul/16 $${Solve}\:{this}\:{equation}\:{by}\:{reducing}\:{it}\:{from}\:{non}\:{homogeneous} \\ $$$${equation}\:{to}\:{homogeneous}\:{equation}\: \\ $$$$\frac{{dy}}{{dx}}\:=\:\frac{{x}\:+\:{y}\:+\:\mathrm{3}}{{x}\:−\:{y}\:−\mathrm{5}} \\ $$ Commented by prakash jain last updated on 09/Jul/16 $$\mathrm{Substitue}\:{x}={u}+\mathrm{1}\:\mathrm{and}\:{y}={v}−\mathrm{4}…
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Question Number 72185 by aliesam last updated on 25/Oct/19 Commented by Rasheed.Sindhi last updated on 26/Oct/19 $$\left\{{a},{b},{c}\right\}\equiv\left\{\mathrm{2},\mathrm{3},\mathrm{5}\right\} \\ $$$$ \\ $$ Commented by aliesam last…
Question Number 6648 by Tawakalitu. last updated on 07/Jul/16 $${What}\:{mass}\:{of}\:{ice}\:{at}\:\:−\mathrm{14}\:{will}\:{be}\:{needed}\:{to}\:{cool}\:\mathrm{200}\:{cm}^{\mathrm{3}} \:{of} \\ $$$${an}\:{orange}\:{drink}\:\left({essentially}\:{water}\right)\:{from}\:\mathrm{25}°{C}\:\:{to}\:\:\mathrm{10}°{C} \\ $$$$\left({specific}\:{latent}\:{heat}\:{of}\:{fusion}\:{of}\:{ice}\:=\:\mathrm{3}.\mathrm{36}\:×\:\mathrm{10}^{\mathrm{5}} \:{jkg}^{−\mathrm{1}} \right. \\ $$$${specific}\:{heat}\:{capacity}\:{of}\:{ice}\:=\:\mathrm{2100}\:{jkg}^{−\mathrm{1}} {k}^{−\mathrm{1}} \\ $$$${specific}\:{heat}\:{capacity}\:{of}\:{water}\:=\:\mathrm{4200}\:{jkg}^{−\mathrm{1}} {k}^{−\mathrm{1}} . \\…