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Question Number 223525 by Nicholas666 last updated on 27/Jul/25 $$ \\ $$$$\:\:\:\:{I}\:=\:\int_{\mathrm{0}} ^{\mathrm{2}\pi} \int_{\mathrm{0}} ^{\mathrm{2}\pi} \int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\mid\:\mathrm{cos}\:{x}\:+\:\mathrm{cos}\:{y}\:+\:\mathrm{cos}\:{z}\:\:\mid\:\:{dxdydz}\:\:\:\:\:\:\:\: \\ $$$$ \\ $$ Terms of Service…
Question Number 223523 by Nicholas666 last updated on 27/Jul/25 Commented by Nicholas666 last updated on 27/Jul/25 $$\:\:\boldsymbol{\mathrm{how}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{problem}}\:?\: \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 223487 by Tawa11 last updated on 26/Jul/25 Let Φ be the hyperbola xy = b², b ≠ 0, and P be a point…
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Question Number 223483 by fantastic last updated on 26/Jul/25 $$\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)=\mathrm{1} \\ $$$$\left({x}−\mathrm{1}\right)^{\mathrm{15}} −\frac{\mathrm{1}}{\left({x}−\mathrm{1}\right)^{\mathrm{15}} }=?? \\ $$ Answered by mr W last updated on 26/Jul/25 $${let}\:{t}={x}−\mathrm{1}…
Question Number 223474 by fantastic last updated on 26/Jul/25 $$\sqrt{\mathrm{1}+\sqrt{\mathrm{1}+{x}}}=\sqrt[{\mathrm{3}}]{{x}} \\ $$ Commented by fantastic last updated on 26/Jul/25 $$\sqrt{{a}+\sqrt{{a}+{x}}}=\sqrt[{\mathrm{3}}]{{x}} \\ $$$${let}\:{t}=\sqrt[{\mathrm{3}}]{{x}} \\ $$$${So}\:{the}\:{equation}\:{becomes} \\…
Question Number 223461 by MathematicalUser2357 last updated on 26/Jul/25 Answered by mr W last updated on 26/Jul/25 Commented by mr W last updated on 26/Jul/25…
Question Number 223490 by mr W last updated on 26/Jul/25 Commented by Ghisom last updated on 27/Jul/25 $$\frac{\mathrm{1}}{\mathrm{2}}{a}\left({a}+{b}\right)−\frac{\mathrm{1}}{\mathrm{2}}{a}\left({a}−{b}\right)={ab}=\mathrm{77}{cm}^{\mathrm{2}} \\ $$ Commented by mr W last…